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Question: ln(e)=1

Question:ln(e)=1

SandorSzabo 607 Maple
February 13 2008
0

I obtained the following result

> dsolve({diff(y(x), x, x)+e^x*(diff(y(x), x))+(1+x^2)*y(x) = 0, y(0) = 1, (D(y))(0) = 0}, y(x), series);
 
y(x) = 1-(1/2)*x^2+(1/6)*x^3+((1/12)*ln(e)-1/12)*x^4+O(x^5));


                            1  2   1  3    /1            1 \  4      / 5\
             y(x) = 1 - - x  + - x  + |-- ln(e) - --| x  + O\x /
                            2       6        \12         12/          

  Why does not know Maple that    ln(e)=1?

How can I persuade Maple to simpliy the result symbolically?

Thanks,      Sandor

 
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