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Question: Summation peculiarity ... and partial fraction expasion of 1/(n(n+1))

Question:Summation peculiarity ... and partial fraction expasion of 1/(n(n+1))

palahnuk 44 Maple
infinity
October 25 2007
0
hello all ... peculiar problem here ... please help the expression is true that 1/n(n+1) = 1/n-1/(n+1) since 1 = n + 1 - n gives 1/n = (n+1)/n - 1 Is there a way to demonstrate this identity in Maple ? ? I cant find any trick with "expand" or such that works. This impact is also seen when evaluating ... the following ... sum(1/n-1/(n+1), n = 1 .. infinity) = 1; = print(`output redirected...`); i get the proper answer of 1 but no answer with ::: sum(1/(n*(n+1)), n = 1 .. infinity); why is this the case ? ? HELP ;-)
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