nonlinear identity / matching

Question:nonlinear identity / matching

Posted: edgar 669 Product: Maple

July 16 2007

Do you have some suggestions on how to do this?

> restart;

> K := exp(-b*x+c*exp(x))*(log(x))^a-exp(-x);

> # for this identity, I want to get: {a=0, b=1, c=0} .

> solve(identity(K,x),{a,b,c}) assuming x>10;

> match(K=0,x,'s');

> SolveTools[Identity]({K},{},{a,b,c});

> {subs(x=j,K)$j=5..10};

> solve(%,{a,b,c});

Warning, solutions may have been lost

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