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Question: Plotting with a floor function

Question:Plotting with a floor function

Nitroxxx 261 Maple
July 10 2007
0
I wonder if this is the right way to plot following function. > restart: > huur:=t->400*(1.01)^ceil(t); floor(t) huur := t -> 400 1.01 > plot(huur(t),t=0..50,discont=true); As you can see I have a the function huur(t) with t a positive integer. I can't find another way to plot this function except by making use of the floor function. Isn't there a better way? Asumming that t is a positive integer didn't worked.
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