Question: Want to solve equation, need help interpreting results :)

I'll start off by saying that I suck at rearranging equations and doing complex maths... which is why I use Maple :) (I've got an old copy of Maple 8, which I use rather infrequently since it's not often I need to calculate complex equations). Right now, I have the equations below: S1 := ((R+(D1*sin(90-x)))^2+(D1*cos(90-x))^2)^(1/2); S2 := ((R-(D2*cos(x)))^2+(D2*sin(x))^2)^(1/2); eqn := (L1/(k*(S1^2)) + L2/(k*(S2^2)))^(1/4) = T; I need to make R the subject of the last equation (R is contained in S1 and S2). To do this I'm assuming that I just need to type "solve (eqn, {R});" to make R the subject but if I do that, I get this: RootOf(T^4*k*_Z^4+(2*T^4*k*D1*sin(90)*cos(x)-2*T^4*k*D2*cos(x) -2*T^4*k*D1*cos(90)*sin(x))*_Z^3+(-L2+T^4*k*D2^2+4*T^4*k*D1*cos(90) *sin(x)*D2*cos(x)+T^4*k*D1^2-L1-4*T^4*k*D1*sin(90)*cos(x)^2*D2)*_Z^2 +(2*L1*D2*cos(x)-2*T^4*k*D1*cos(90)*sin(x)*D2^2-2*T^4*k*D1^2*D2*cos(x) +2*L2*D1*cos(90)*sin(x)+2*T^4*k*D1*sin(90)*cos(x)*D2^2-2*L2*D1*sin(90) *cos(x))*_Z-L1*D2^2+T^4*k*D1^2*D2^2-L2*D1^2) Unfortunately this is complete gibberish to me :(. What does "RootOf" mean (the help file for that is similarly incomprehensible to me)? Where are those Z terms coming from? What do they mean? Is there any way I can simplify this at all? It looks like some kind of series to me, is there any way to collapse it somehow? Any help would be appreciated!
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