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Question: large integers

Question:large integers

mattcanderson1 35 Maple
April 08 2010
1

I want to factor the 34 th Fermat number.

F(n) := 2^(2^n) + 1

I can enter the 29th Fermat number: 2^(2^29) +1, and Maple will evaluate it.

I seem to be under the maxdigits limit:

> kernelopts(maxdigits);
 

38654705646

I think I can set up a trial division loop once I can represent F(34)

How can I evaluate even the 30th Fermat number?

 
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