MaplePrimes Questions

Hello people in mapleprimes,

I installed maple 2018 Japanese version.
And, with solve(x^2-1,x), its solution is expressed as _EXPSEQ(1, -1)

I know this expression is an internal represantation.
How can I have maple answer as 1, -1?

Thanks in advance.

Addition: my pc is mac osx 10.13.6.
 

 

 

Hello,

I'm trying to solve  inverse trigonometric equation:

EQ := sqrt(3)*arctan(x/sqrt(3))-arctan(x) = 1;

sol := solve(EQ, {x});

#sol := {x = sqrt(3)*tan(RootOf(-tan(sqrt(3)*_Z-1)*sqrt(3)+3*tan(_Z)))}

evalf(sol);

#{x = 13.24164497} OK. one Real solution.

sol2 := evalf(allvalues(sol));

#sol2 := {x = -.1141310781-1.108044977*I}, {x = -.1141310781+1.108044977*I}, # {x = 1.142681884}, {x #= -2.379974990}, {x = 13.24164497}

Check:

seq(evalf(eval(EQ, sol2[k])), k = 1 .. nops([sol2]));

#.99999999991340592650+1.61960960*10^(-11)*I = 1., .99999999991340592650-#1.61960960*10^(-11)*I = 1., .15821278548775934290 = 1., -.4580182246463005988 = 1., #.9999999996233630663 = 1.

1.Can someone explain to me where did Maple find these Additional roots like: {x = 1.142681884}, {x = -2.379974990}?

2.It's a Bug or normal behavior ?

 

I have three questions

1:= If I have summation over i from 0 to 100 how do I prevent maple from unpacking the sum and set it like it is?

2:= Does the comand evalf give me an imaginary evaluation if we apply it in a sum and how do I avoid that?

3:= For infinite sum, Maple evaluates it with term hyper geometry and can't after that evaluate the diffrentation how do I prevent that?

Good morning, I'm trying to solve this very simple problem : plot a graph starting from the origin. The problem is that the x_axis is located at the lower value of my function, but i want it to go through the point (0,0). Let's see this example:

plot(piecewise( x<5, 100, x>5,200), x=0..10); As you can se the X-axis passes through y=100.

Now with this option I obtain:

plot(piecewise( x<5, 100, x>5,200), x=0..10, y=0..200); 

The problem is taht I need to specify the upper bound of the range for each function (200). Is there an automatic way? Any help is appreciated.


 

Hi.

I want to use canonical analysis or any other method to get vlaue of X1,X2.

How do I get  x 1, x 2 value?

please help!!

Hi.

Is possible to pdsolve these equations via maple.

Functions f1(x) and f2(x) and g(x) are aviable and only  phi and p1(x,z) and p3(x,z) are unknown.

I want to determine phi and p1(x,z) and p3(x,z).

 Also other parameter suvh as h-alpha-beta-beta1 -beta3 and L,..  are aviable and are not unknown.

Thanks

After calculations the integral contains infinity. what it resembles? Is it correct  answer?  Please check the file maple
 

restart

with(DifferentialGeometry):with(JetCalculus):NULL``

DGsetup([x, t], [u], E, 1):

``

 

 
E > 

(-3*t*u[1]^2*u[2]-t*u[2]^3+x*u[1]^3+3*x*u[1]*u[2]^2)*((-2*u[]^2+1)*(-u[1, 1]+u[2, 2])+2*u[]*(-u[1]^2+u[2]^2))/((u[1]-u[2])^3*(u[1]+u[2])^3)

(-3*t*u[1]^2*u[2]-t*u[2]^3+x*u[1]^3+3*x*u[1]*u[2]^2)*((-2*u[]^2+1)*(-u[1, 1]+u[2, 2])+2*u[]*(-u[1]^2+u[2]^2))/((u[1]-u[2])^3*(u[1]+u[2])^3)

(1.1)
E > 

``

E > 

A := evalDG((-3*t*u[1]^2*u[2]-t*u[2]^3+x*u[1]^3+3*x*u[1]*u[2]^2)*((-2*u[]^2+1)*(-u[1, 1]+u[2, 2])+2*u[]*(-u[1]^2+u[2]^2))*`&w`(Dx, Dt)/((u[1]-u[2])^3*(u[1]+u[2])^3))

_DG([["biform", E, [2, 0]], [[[1, 2], -(3*t*u[1]^2*u[2]+t*u[2]^3-x*u[1]^3-3*x*u[1]*u[2]^2)*(2*u[]^2*u[1, 1]-2*u[]^2*u[2, 2]-2*u[]*u[1]^2+2*u[]*u[2]^2-u[1, 1]+u[2, 2])/((u[1]-u[2])^3*(u[1]+u[2])^3)]]])

(1.2)
E > 

simplify(HorizontalHomotopy(A))

_DG([["biform", E, [1, 0]], [[[1], -t*(int(-infinity*(u[1]+u[2])*(1+(u[2, 2]+u[1, 1, 2]+u[1, 2, 2]+u[2]+u[1, 2])*_z1)*_z1*(u[1]-u[2])*(u[1]^4+u[2]^4)*signum(1, (_z1*t*u[2]^6+(-3*_z1*x*u[1]-u[])*u[2]^5+3*_z1*((2/3)*t*u[1]^2+u[]*(t*u[1, 1]+x*u[1, 2]))*u[2]^4-12*(-(1/6)*_z1*x*u[1]^2+(1/6)*u[]*u[1]+_z1*u[]*(t*u[1, 2]+x*u[1, 1]))*u[1]*u[2]^3+18*_z1*u[1]^2*(-(1/6)*t*u[1]^2+u[]*(t*u[1, 1]+x*u[1, 2]))*u[2]^2-12*u[1]^3*(-(1/12)*_z1*x*u[1]^2-(1/4)*u[]*u[1]+_z1*u[]*(t*u[1, 2]+x*u[1, 1]))*u[2]+3*_z1*u[]*u[1]^4*(t*u[1, 1]+x*u[1, 2]))/(_z1^2*(u[1]-u[2])^4*(u[1]+u[2])^4))+infinity*(u[1]+u[2])*_z1*(1+(u[1, 1, 2]+u[1, 2, 2]+u[1]+u[1, 1]+u[1, 2])*_z1)*(u[1]-u[2])*(u[1]^4+u[2]^4)*signum(1, (_z1*x*u[1]^6+(-3*_z1*t*u[2]-u[])*u[1]^5+3*_z1*((2/3)*x*u[2]^2+u[]*(t*u[1, 2]+x*u[2, 2]))*u[1]^4-12*u[2]*(-(1/6)*t*_z1*u[2]^2+(1/6)*u[]*u[2]+_z1*u[]*(t*u[2, 2]+x*u[1, 2]))*u[1]^3+18*_z1*u[2]^2*(-(1/6)*x*u[2]^2+u[]*(t*u[1, 2]+x*u[2, 2]))*u[1]^2-12*(-(1/12)*t*_z1*u[2]^2-(1/4)*u[]*u[2]+_z1*u[]*(t*u[2, 2]+x*u[1, 2]))*u[2]^3*u[1]+3*_z1*u[]*u[2]^4*(t*u[1, 2]+x*u[2, 2]))/(_z1^2*(u[1]-u[2])^4*(u[1]+u[2])^4))+6*(u[]*(u[1]^2-u[2]^2+u[]*(-u[1, 1]+u[2, 2]))*_z1^2-(1/2)*u[2, 2]+(1/2)*u[1, 1])*(t*u[1]^2*u[2]+(1/3)*t*u[2]^3-(1/3)*x*u[1]^3-x*u[1]*u[2]^2), _z1 = 0 .. 1))/((u[1]-u[2])^3*(u[1]+u[2])^3)-signum((t*u[2]^6+(-3*x*u[1]-u[])*u[2]^5+(2*t*u[1]^2+3*u[]*(t*u[1, 1]+x*u[1, 2]))*u[2]^4+(2*x*u[1]^3-2*u[]*u[1]^2-12*u[]*(t*u[1, 2]+x*u[1, 1])*u[1])*u[2]^3+18*(-(1/6)*t*u[1]^2+u[]*(t*u[1, 1]+x*u[1, 2]))*u[1]^2*u[2]^2+(x*u[1]^5+3*u[]*u[1]^4-12*u[]*(t*u[1, 2]+x*u[1, 1])*u[1]^3)*u[2]+3*u[]*u[1]^4*(t*u[1, 1]+x*u[1, 2]))/((u[1]-u[2])^4*(u[1]+u[2])^4))*infinity], [[2], x*(int(-infinity*(u[1]+u[2])*(1+(u[2, 2]+u[1, 1, 2]+u[1, 2, 2]+u[2]+u[1, 2])*_z1)*_z1*(u[1]-u[2])*(u[1]^4+u[2]^4)*signum(1, (_z1*t*u[2]^6+(-3*_z1*x*u[1]-u[])*u[2]^5+3*_z1*((2/3)*t*u[1]^2+u[]*(t*u[1, 1]+x*u[1, 2]))*u[2]^4-12*(-(1/6)*_z1*x*u[1]^2+(1/6)*u[]*u[1]+_z1*u[]*(t*u[1, 2]+x*u[1, 1]))*u[1]*u[2]^3+18*_z1*u[1]^2*(-(1/6)*t*u[1]^2+u[]*(t*u[1, 1]+x*u[1, 2]))*u[2]^2-12*u[1]^3*(-(1/12)*_z1*x*u[1]^2-(1/4)*u[]*u[1]+_z1*u[]*(t*u[1, 2]+x*u[1, 1]))*u[2]+3*_z1*u[]*u[1]^4*(t*u[1, 1]+x*u[1, 2]))/(_z1^2*(u[1]-u[2])^4*(u[1]+u[2])^4))+infinity*(u[1]+u[2])*_z1*(1+(u[1, 1, 2]+u[1, 2, 2]+u[1]+u[1, 1]+u[1, 2])*_z1)*(u[1]-u[2])*(u[1]^4+u[2]^4)*signum(1, (_z1*x*u[1]^6+(-3*_z1*t*u[2]-u[])*u[1]^5+3*_z1*((2/3)*x*u[2]^2+u[]*(t*u[1, 2]+x*u[2, 2]))*u[1]^4-12*u[2]*(-(1/6)*t*_z1*u[2]^2+(1/6)*u[]*u[2]+_z1*u[]*(t*u[2, 2]+x*u[1, 2]))*u[1]^3+18*_z1*u[2]^2*(-(1/6)*x*u[2]^2+u[]*(t*u[1, 2]+x*u[2, 2]))*u[1]^2-12*(-(1/12)*t*_z1*u[2]^2-(1/4)*u[]*u[2]+_z1*u[]*(t*u[2, 2]+x*u[1, 2]))*u[2]^3*u[1]+3*_z1*u[]*u[2]^4*(t*u[1, 2]+x*u[2, 2]))/(_z1^2*(u[1]-u[2])^4*(u[1]+u[2])^4))+6*(u[]*(u[1]^2-u[2]^2+u[]*(-u[1, 1]+u[2, 2]))*_z1^2-(1/2)*u[2, 2]+(1/2)*u[1, 1])*(t*u[1]^2*u[2]+(1/3)*t*u[2]^3-(1/3)*x*u[1]^3-x*u[1]*u[2]^2), _z1 = 0 .. 1))/((u[1]-u[2])^3*(u[1]+u[2])^3)-signum((x*u[1]^6+(-3*t*u[2]-u[])*u[1]^5+(2*x*u[2]^2+3*u[]*(t*u[1, 2]+x*u[2, 2]))*u[1]^4+(2*t*u[2]^3-2*u[]*u[2]^2-12*u[]*(t*u[2, 2]+x*u[1, 2])*u[2])*u[1]^3+18*(-(1/6)*x*u[2]^2+u[]*(t*u[1, 2]+x*u[2, 2]))*u[2]^2*u[1]^2+(t*u[2]^5+3*u[]*u[2]^4-12*u[]*(t*u[2, 2]+x*u[1, 2])*u[2]^3)*u[1]+3*u[]*(t*u[1, 2]+x*u[2, 2])*u[2]^4)/((u[1]-u[2])^4*(u[1]+u[2])^4))*infinity]]])

(1.3)
E > 

``

``

E > 

``

E > 

``


 

Download maple1.mw

1.mw maple1.pdf

Hi everybody, I have some programming difficulties on the maple, this is the algorithm and link article, hope everyone help me, please, thank you so much!!

Algorithm:

1: for Search every non-singular m × m matrix T with a few of XORs over F2. do

2: Find the minimum polynomial f(x) of T.

3: if f(x) = g(x)t(x) satisfying g(x) 6= 1, t(x) 6= 1 and g(x) is relatively prime with t(x). then

4: Find ri1(x), ri2 satisfying g(x)ri1 +t(x)ri2 = 1. Let pi1=g(x)ri1, pi2=t(x)ri2 = 1 . Sore pi1 and pi2.

5: end if

6: end for

7: for i from 1 to k. do

8: for Search a over F2[x]/(fi(x)). do

9: for Search b over F2[x]/(fi(x)). do

10: c = a + pi1(x), d = b + pi2.

11: if The circulant orthogonal matrix (a, b, c, d) is MDS. then

12: Store fi(x) and (a, b, c, d).

13: end if

14: end for

15: end for

16: end for

17: for Search every m × m non-singular matrix T with a few of XORs. do

18: for i from 1 to k. do

19: if fi(T) = 0. then

20: Substitute T into corresponding circulant orthogonal MDS matrix (a, b, c, d). Compute the sum of XORs of (a, b, c, d).

21: end if

22: end for

23: end for

Link: https://eprint.iacr.org/2017/371.pdf

i am trying to solve some equations ......but the comand f solve is not always work .i have two Question 
1:=is there any ather comand in maple solve the quations and looking for the answer in acetrtian region of real line other than f solve?

2:=iam trying to tell maple if you couldnt solve this equation assign another value of X as 
(if fsolve(Q[1])=Nill then X:=3;) but this comand desnt actually work in my loop

sol := dsolve([op(eqs), op(ICs)], numeric, range = 0 .. tmax, abserr = 10^(-3), relerr = 10^(-3), stiff = true, maxfun = 0);
Error, (in dsolve/numeric/process_input) system must be entered as a set/list of expressions/equations
can any one tell how to remove this error?

Good day 

Recently, I decided to learn Maple. So, I came across these exercises(uploaded) but I don't have any idea about the shooting method's Maple coding and how to compare especially representing it in tables.
 

What is the Maple coding needed?

How do I compare both results in a tabular form?

How do I calculate the error analysis? and

How do I plot the graph?

I believe with the knowldege gotten from the solutions of this exercises, I will be able to answer any question on shooting method.

Thank You. 

 

How come there is an imaginary value in the result?

restart;

int(exp(-t)/(1-t), t = 0 .. infinity, CauchyPrincipalValue = true)

First 787 788 789 790 791 792 793 Last Page 789 of 2428