Why input fraction to eigenvector and then evalf output are all the same when input different ?

i would like to see more decimal numbers

digits := 36 

command can not show more decimal numbers

why can not see the difference?

if start from fraction

After set round screen display to 36 digits in options

If start from floating value

the result different from start from fraction

start from which is the most accurate and correct?

if fraction is correct, why all result are the same even if input are different?

I'm absolutely new in maple, but I need to solve PDE and I don't understand why maple do not solve it

restart; with(PDEtools);
U := diff_table(u(x, t));

pde[1] := U[t, t] = U[x, x]+5*sin(3*x);

bc[1] := eval(U[], x = 0) = 0; bc[2] := eval(U[], x = Pi) = 0;
ic[1] := eval(U[], t = 0) = 0; ic[2] := eval(D[2]*U[], t = 0) = 1;

sys[1] := [pde[1], bc[1], bc[2], ic[1], ic[2]];
pdsolve(sys[1]);

Error: Error, (in PDEtools:-Library:-NormalizeBoundaryConditions) unable to isolate the functions {u(0, t), u(Pi, t), u(x, 0)} in the given boundary conditions {D[2]*u(x, 0) = 1, u(0, t) = 0, u(Pi, t) = 0, u(x, 0) = 0}

If I solve it  with only boundary conditions or without any conditions, maple gives me an answer. 

Please, help me to understand, how to solve this pde system with boundary and initials conditions. This is my firs use of maple so I hardly understand how to write code correctly.

Real part + complex part

but 

sometimes it display

complex part + real part 

how to consistent display real part + complex part?

Sometimes we have questions that apply to every execution we make, regardless of what the actual nature of the commands included in that execution are.

For this reason, I propose that in the same way that we have the feature of "start up" code, which automatically executes upon opening the specified worksheet, we also implement an option of automatically executed code for every execution that is carried out within the specified worksheet. 

for example, code that serves purposes of output such as 

" This execution took xxxx minutes and xx.x seconds to complete, and required an average of x % of your computer's total processor utilization capacity across all cores "

I know how i will be providing this feature in my worksheets, but i just feel that it would be a beneficial feature for those that use maple for purposes that do not involve a knowledge of how maple is programmed, and would not be able to do so.

Any discussion about this would be welcomed, which is why i am posting about it of course.

I am trying to see if Maple can solve Laplace PDE inside the disk in polar coordinates. Standard textbook problem. Radius of disk is `a`. The boundary conditions on the disk is `f(theta)`. One of the conditions needed also is that the solution is finite in the center of the disk.

I do not know how to tell Maple that the solution should be finite in the center of the disk. If I do not give this conditions, Maple gives me strange looking solution, which does not look like anything close to the standard series solution one gets from hand solution. There is not even a series solution.

This is what I tried

restart;
pde:=diff(u(r,theta),r$2)+1/r*diff(u(r,theta),r)+1/r^2*diff(u(r,theta),theta$2)=0;
bc:=u(a,theta)=cos(theta);
sol:=pdsolve([pde,bc],u(r,theta)) assuming r<=a,r>0

Now, how to tell it that `u(0,theta)` is bounded? So that the `ln(r)` solution do not show up? Adding `u(0,theta)<infinity` to the boundary conditions, gives error

restart;
pde:=diff(u(r,theta),r$2)+1/r*diff(u(r,theta),r)+1/r^2*diff(u(r,theta),theta$2)=0;
bc:=u(a,theta)=cos(theta),u(0,theta)<infinity;
sol:=pdsolve([pde,bc],u(r,theta)) assuming r<=a,r>0

The standard solution to this PDE is

Where `c0` and `cn` and `kn` above are found from boundary conditions at $u(a,\theta)$.

How can one get Maple to give the above solution? How to tell it that $u$ is bounded at $r=0$?

we know that the exponotial function is represented as a taylor series, that means that the exponontial of any value is approximatvly evaluated ,the same thing of sinus function when i calcute sin(Pi/6) it give me the exacte result,
 

Download trying.mws

,can anyone explain to me these results ?

Came across this issue again.  While working within a worksheet, everything seems fine, using commands like imagetools outputing bmp files etc.  I had to, in the the Options->Precision, uncheck limit expression length to 1000000 during my session.  I saved it multiple times, however and unfortunately did not save as seperate versions, so I was left with one file.

The file size ended up being 64Mb.  The problem is trying to load it into Maple, everytime I try to load the worksheet my computer seems to freeze (laptop, 4Gb RAM, windows 7 64 bit, Maple 2017) I check task manager and my javaw.exe file is consuming 3.7Gb of memory!  So that's why it's locking up. 

I've tried multiple times to open the file and utilmately end up pressing and holding the power button to restart my system. 

C: y^2=10161/256*t^2+8829189/25600*t+7266953961/1024000 

how to find the (t, y) points on the curve C ?

THANKS.

Attractor.mw
Hello, anybody could help with this error?

Download Attractor.mw

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conservation_of_wave_eq.mw

If i was a good student i wouldnt be using the is function for these at all, but im quite tired now so i thought that it would be fine this time. But i honest cannot see what additional declarations need to be made here, and why a false is returned for the first query, then FAIL for the negation of the first in the second query, the only thing i can think of is declaring that indeed n and m are elements of N, but if maple was allowing for Gaussian n,m surely both queries would return fail, and so obvious it is indeed acknowledging the arguments are on R, anyway hopefully someone gets the chance to make me feel silly here

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I'm stuck with applying boundary conditions for a cantilever beam please help with format

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Hi all,

I don't know why this file doesn't work anymore! It was ok last week. I even reinstall the Maple on my laptop, but it went wrong again...

Please help me.

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