I have a problem about the integration of a function. The maple returns mathematical form of the given command

the function is

fn :=(-4.079067798*10^(-16)+3.422708023*10^(-16)*I)*(3.363377947*10^(-11)+5.977507284*10^(-12038)*I+(3.363377947*10^(-11)+4.678081798*10^(-22)*I)*erf(1.664331698*10^15*qq-0.2503507367e-1-4.649313602*I)) *exp(-2.77*(qq/(tau*tau))^2)*exp(-I*w0*qq)*exp(-(ss-qq)/T_pop)

qq is the integration variable qq=-inf..ss

w0=10^15

tau=10^(-15)

T_pop=30e-15

I have this matrix

and I want a matrix which components are de real parte of the components of A. I have tried this:

but it doesn't work.

What is wrong?

Thank you so much.

I have this two matrices

and

and I want to check that their are the same. I have tried

but it says it false. It should say that is true, because - I think- this two matrices are the same.

Does anyone know what is wrong?

Many thanks

Can anyone offer an explanation why the following error occurs, and how it can be avoided? Thanks!

Download error.mw

In preparation for learning GR, I need somme trick on how to use the DifferentialGEometry package or else. So I want to show you what I want to do (see the link to the document below) and I would like some help on how to do it with tensor.  That would help me a lot.  Then, I will extansion it on a 3-D problem and next in 4-D.

Thank you in advance dor your help

here is the file : Finding_covariant_and_contravariant.mw

--------------------------------------
Mario Lemelin

Maple 2015 Ubuntu 14.04 - 64 bits
Maple 2015 Win 10 -  64 bits
messagerie : mario.lemelin@cgocable.ca
téléphone :  (819) 376-0987

For the life of me I cannot find the method to do so.

So the solution would look like:

1. Euation

2 Step 2

3 Step 3

4 step 3+n

where n is the number of steps reuired.

Any help will be appreciated so very much.

.

.TIA

Larry C

Is there in Maple a command to verify that one segment on the real axis is a subset of another segment?  For example  RealRange(2, 4)  is subset of  RealRange(2, 5) . 

Of course easy to write a procedure that makes it:

Subset:=proc(r1::RealRange, r2::RealRange)

local a, b, c, d;

a, c:= op~(1,[r1, r2])[];

b, d:= op~(2,[r1, r2])[];

if a>=c and b<=d then true else false fi;

end proc:

Example of use:

Subset(RealRange(2,4), RealRange(2,5));

Subset(RealRange(2,5), RealRange(2,4));

                            true

                            false

I have this matrix

and I would like to evaluate the variables like this

I tried this

but it didnt work.

Any suggestions??

Thank you so much

I want to compute some matrix multiplications and i need this expression to be 1 always, i.e,

x^2+y^2+z^2+w^2=1

for every calculation I do.

I have tried x^2+y^2+z^2+w^2:=1 and assign(x^2+y^2+z^2+w^2,1) but it doesn't work.

What I should type to make it work?

Thank you

Hi,

In line with my previous questions

http://www.mapleprimes.com/questions/201944-Convergence-Problem-In-My-Algorithm-DSOLVE

I write a code with different variables and odes. However I tried to get the solution, I cannot get the results. I think it should be some problems with my Guess procedure. The code is attached. I would be most grateful if you help me on this problem.

code.mw

Thank you.

Amir

with(DynamicSystems)

T:= a vector

Iwant to make a single plot of:

DiscretePlot(T,x1,stile=stair); DisdretPlot(T,x2,stile=stair)

The usal way: DiscreePlot(T,[x1,x2]... ain't work

Thansk for helping

I am trying to solve a PDE which is converted to ODE when we assign one of the  variables some value. The boundary conditions given to the PDE are numerical values given for fixed numerical values to the two independent variables. I am trying to solve the PDE with the staandard syntax:

pds := pdsolve(pde,[ibc],numeric,time=z,range=0..beta);

The error message I get is:  

Error, (in pdsolve/numeric/process_PDEs) PDEs can only contain dependent variables with direct dependence on the independent variables of the problem, got {theta(z, 0)}

The pde and boundary conditions are as follows:

PDE:   pde := diff(theta(z, 0), z, z)+theta(z, 0)

Where zero is the fixed value for an independent variable

Boundary Condition:  ibc:={theta(0,0)=beta,D[1](theta)(0,0)=0};

When I try to solve it as an ODE the error is:

Error, (in dsolve) not an ODE system, please try pdsolve

Hello,

I would like to know : how I can get all the contents of the module GetMultibody of MapleSim?

Is there in classic maple a function enabling me to ask the content of a module ?

Thank a lot for your help.

Hello

i was stuck with some simple problem. I tried using if condition in program that involves a truth condition. If maple cannot determine the condition is true or false i want to assign o to a particular varable. I  show a similar program.

restart;

h[1] := -1;

for i from 1 by 1 while(i<150 and h[i]<0) do

p1[i] := .989347189582843*x^2-0.139423979061219e-1*x-1.82559474469870*10^8*x^15+1.30761381361453*10^8*x^16-6.88520063191821*10^7*x^17+2.51079317463498*10^7*x^18-5.66094206949155*10^6*x^19+5.94129446612678*10^5*x^20-6812.74182685426*x^5+59230.0931084044*x^6-3.83520584559500*10^5*x^7+1.90126822307036*10^6*x^8-7.34991883857609*10^6*x^9+2.24203561757434*10^7*x^10-5.43284775909785*10^7*x^11+1.04806113793011*10^8*x^12-1.60600324339222*10^8*x^13+1.94090536353833*10^8*x^14+559.557918804679*x^4-30.6576714427729*x^3-3.93727537464007*10^(-15)-i^2-i; fsolve(p1[i]-0.312e-1, x, -1 .. 1);

if fsolve(p1[i]-0.312e-1, x, -.2 .. 0) < 0 then h[i+1] := fsolve(p1[i]-0.312e-1, x, -.2 .. 0) elif FAIL then h[i+1] := 0 end if;

print(i, h[i])

end do;

i got an error message

Error, cannot determine if this expression is true or false: () < 0

how can i get a value of 0 for h[i] if the error comes.

Thanks.

Aditya