MaplePrimes Questions

Hi everyone,

 

I am creating a Maplet containing an area to plot some math function using Plotter command. The point is that I want to put the toolbar native from Maple in order to avoid to add extra buttons for zooming, moving, 1:1 or etcetera the graph, but I have not been successful.

Some suggestions?


Thank you, Friends!

Hello everyone!

Can somebody help me to sovle the following system numerically?

V:=5*10^(-5):
A:=2*10^(-4):
L:=0.02:
C0:=0.01:
d:=0.25:
eq1:=CL(t)*V+CR(t)*V+A*int(CS(x,t),x=0..L):
eq2:=CL(t)=eval(CS(x,t),x=0):
eq3:=CR(t)=eval(CS(x,t),x=L):
eq4:=CL(0)=C0:
eq5:=CL(10000)=C0/2:
eq6:=CL(10000)=CR(10000):
eq7:=V*(C0-CL(t))=A*d*int(eval(diff(CS(x,t),x),x=0),t=0..t1):
eq8:=V*CR(t)=A*d*int(eval(diff(CS(x,t),x),x=L),t=0..t1):
eq9:=diff(CS(x,t),t)=d*diff(CS(x,t),x,x):

Thanks!

I'm trying to export a worksheet to Latex. I'm able to exprot it. But the long equations are not broken into multiple lines. I have used Mathlinebreaking width 5.0 inch in the export option. But it still does not work. I can see the linebreaking command (\\) in the tex file. But when I compile my latex code the pdf does not have any linebreak. The equation just overflows. Any help will be appreciated. 

Assume we have a map f from a polynomial ring R to another polynomial ring S, I know how to compute kernel (a generator for the kernel ideal) of these maps by Singular, but I want to know can I do it with Maple too? Thanks.

An example;

Consider the homomorphism f:k[x,y]-->k[u,v] sending x to v and y to v^2 then using Singular;

ring r1=0,(x,y),lp;

ring r2=0,(u,v),lp;

ideal i=v,v2;

map f=r1,i;

setring r1;

kernel(r2,f);

_[1]=x2-y

So at above I took k a field of characteristic zero. The kernel is the ideal generated by x^2-y.

I am trying to do some algebra with the derivatives of some variables within a program. As a result i need to relable them before i feed them into solve.

To relable them i create vectors and use subs. one of these vectors behaves differently within a proc to how it behaves outside it. This is weird.

TimefullBehavesFunny := proc (nPars, nVars)
local nDiffs, timefull, timeless;
nDiffs := nPars;
timefull := [seq(dx[j, i] = diff(x[i](t), `$`(t, j)), i = 1 .. nVars)];
timefull := [seq(op(timefull), j = 0 .. nDiffs), seq(x[i] = x[i](t), i = 1 .. nVars)];
timeless := `~`[`=`](`~`[rhs](timefull), `~`[lhs](timefull));
timefull, timeless, nDiffs;
end proc

When i run the above for (3,3) i get a differet result to when i run the following
nVars:=3;
nDiffs := 3;
timefull := [seq(dx[j, i] = diff(x[i](t), `$`(t, j)), i = 1 .. nVars)];
timefull := [seq(op(timefull), j = 0 .. nDiffs), seq(x[i] = x[i](t), i = 1 .. nVars)];
timeless := `~`[`=`](`~`[rhs](timefull), `~`[lhs](timefull));

and similarly for other numbers.

any ideasas to why?

Hello, 

How can I flatten this list ? [1,2,3, {4,5,6}]

I tried this :

Flatten([1,2,3, {4,5,6}]); But it doesn't work.

Flatten seems to work only on this kind of list [1,2,3, [4,5,6]]

and I would like to obtain this :[1,2,3,4,5,6]

Thank you for your help

P.S:

If I can use Flatten, it would be fine

Hello,

I have two equations (1) and (2) and i want to divide (2) with (3). A good point is that Maple understand division with equations. Nevertheless, I didn't obtain a simplified solution.

Here my code :

restart;
eq1:=-sin(alpha0(t))*cos(beta0(t)) = -sin(alpha[1](t))*cos(beta[1](t));
-sin(alpha0(t)) cos(beta0(t)) = -sin(alpha[1](t)) cos(beta[1](t))
eq2:=cos(alpha0(t))*cos(beta0(t)) = cos(alpha[1](t))*cos(beta[1](t));
cos(alpha0(t)) cos(beta0(t)) = cos(alpha[1](t)) cos(beta[1](t))
simplify(eq1/eq2,trig);

Here the result obtained :-sin(alpha0(t))/cos(alpha0(t)) = -sin(alpha[1](t))/cos(alpha[1](t))

Consequently, I would like to obtain tan(alpha0(t))=tan(alpha1(t))

Do you have ideas why I didn't obtain a simplified result ? And How can I obtain the solution with tangents ?

Thank you for your help

Hey,

I think I found a bug concerning the useage of assume and alias:

restart:

alias(a=a(t),b=b(t));

a, b

(1)

assume(a(t),real);

getassumptions(a(t));

{((a(t))(t))::real}

(2)

assume(b(t),real);

getassumptions(a(t));

{((b(t))(t))::real}

(3)

getassumptions(b(t));

{((b(t))(t))::real}

(4)

 

 

 

Commenting out the alias command produces correct results. I am on linux with build 922027.

alias_bug.mw

I want to solve a system of equations using f-solve (two unknowns) and exporting the solutions to a matrix where the solutions are in seperate columns. How do I do this?

I have tried:

for i from 1 to 937 do

AP[i,1]:=fsolve(x=KL[i,1].y=KL[i,2],x=..8,y=0..15))

end if

end do

 

But this returns the solutions for X and Y in the same column. Also, for the values that are not possible to solve, it returns the entire expression instead of e.g. 0 or "undefined".

Thank you.

f := a - b;
g := op(f);
seq(abs(g[i]), i=1..nops([g]));

i discover abs still in expression

how to result in [a,b] when input is [a,-b]

 from determinant's polynomial?                                                                                                       

question1 := b(t)*(diff(c(t), t))*(diff(a(t), t))+a(t)*(diff(b(t), t))

how to subs(b(t)=0, question1) result in a(t)*(diff(b(t), t)) ?

in fact b(t) = 0 but diff(b(t), t) != 0 

Dear All

I have updated my Maple 18, I am surprised to see that ordinary "solve" do not work and return error massage like;

"Error, (in coulditbe) invalid input: `coulditbe/internal` uses a 1st argument, obj, which is missing"

or like;

"Error, (in solve) invalid input: hastype expects 2 arguments, but received 1"

I am totally confused !!!

Can anybody help me out please !!!!

 

 


solve({x+2*y = 3, y+1/x = 1}, [x, y])

Error, (in coulditbe) invalid input: `coulditbe/internal` uses a 1st argument, obj, which is missing

 

solve({x+2*y = 3, y+1/x = 1}, {x, y})

Error, (in solve) invalid input: hastype expects 2 arguments, but received 1

 

``


Download Solve_Command.mw

Regards

Hello,

I would like to determine the position jacobian matrix from a set of constraint equations.

Here my constraint equations :

eq1:=l1*cos(theta(t))+l2*sin(beta(t))-x(t)=0
eq2:=l1*sin(theta(t))-l2*cos(beta(t))=0

The jacobian matrix that I would like to determine is :

 

Can you help me to make a general procedure to calculate a jacobian position matrix from a set of constraint equations ?

Thank you for your help

 

What is the easiest way to ask roots of a polynomial on a finite field. For example asking roots of x^2+xy+y on GF(8)? I was thinking to run a two for on members of GF(8) and ask to check it but I couldn't do it using Galois package or maybe I couldn't use that package. Thanks for any help.

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