I have to solve a complex equation whose solutions, I'm looking for, are real numbers, I chose a command 'solve ' to solve this problem but the program shows me this message 'warning solutions May Have Lost'. How I can resolve this problem?

this is the equation and the message :

solve({((abs((((1-(nc-I*kc))/(1+(nc-I*kc)))+(((nc-I*kc)-(0.518-I*0.023))/((nc-I*kc)+(0.518-I*0.023)))*exp(-I*4*3.14*h*(nc-I*kc)/lamda))/(1+((1-(nc-I*kc))/(1+(nc-I*kc)))*(((nc-I*kc)-(0.518-I*0.023))/((nc-I*kc)+(0.518-I*0.023)))*exp(-I*4*3.14*2500*(nc-I*kc)/581))))^2)*100=43.12,((abs((((1-(nc-I*kc))/(1+(nc-I*kc)))+(((nc-I*kc)-(0.176-I*0.023))/((nc-I*kc)+(0.176-I*0.023)))*exp(-I*4*3.14*h*(nc-I*kc)/lamda))/(1+((1-(nc-I*kc))/(1+(nc-I*kc)))*(((nc-I*kc)-(0.176-I*0.023))/((nc-I*kc)+(0.176-I*0.023)))*exp(-I*4*3.14*2500*(nc-I*kc)/720))))^2)*100=44.37},{kc,nc});
{kc,nc};

Warning, solutions may have been lost            {kc, nc}

So I need a help .

Hi,

I have a system of equations for which I want to get a solution around an initial guess, unfortunatly I cannot succed it. Here is the system and the initial guess

solve({(-(((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.005+0.009)*sin(-0.785)+(0.072+1*(Ladssec+Ll))*cos(-0.785)))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.072+1*(Laqssec+Ll))*sin(-0.785)-(0.005+0.009)*cos(-0.785)))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0))/(2*2.5))=-1.7858
,(-((((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/Lfd))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-(((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*Lfd))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0)+((Ladssec*iq0)/Lfd)) /(2*2.5))=0.1036
,(-((-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/L1d))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-(((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1d))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0)+((Ladssec*iq0)/L1d)) /(2*2.5))=0.2279
,(-((((0.072+1*(Ladssec+Ll))*Laqssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1q))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Laqssec/L1q))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0)-((Laqssec*id0)/L1q)) /(2*2.5))=-2.3313

,(-(1*Rfd*((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.072+1*(Laqssec+Ll))*sin(-0.785)-(0.005+0.009)*cos(-0.785)))*Ladssec)/(Lfd))=0.0023
,(-(1*Rfd*(1-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*Lfd)) *Ladssec)))/(Lfd))=-0.0054
,(-(1*Rfd*(-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1d)) *Ladssec)))/(Lfd))= 0.0018
,(-(1*Rfd*(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Laqssec/L1q))*Ladssec)/(Lfd))=5.8369e-04

,(-(1*R1d*((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.072+1*(Laqssec+Ll))*sin(-0.785)-(0.005+0.009)*cos(-0.785)))*Ladssec)/(L1d))=0.1303
,(-(1*R1d*(-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*Lfd))*Ladssec)))/(L1d))=0.1157
,(-(1*R1d*(1-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1d)) *Ladssec)))/(L1d))= -0.3192
,(-(1*R1d*(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Laqssec/L1q))*Ladssec)/(L1d))=0.0333

,(-(1*R1q*((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.005+0.009)*sin(-0.785)+(0.072+1*(Ladssec+Ll))*cos(-0.785))) *Laqssec)/(L1q))=-0.1323
,(-(1*R1q*(((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/Lfd))*Laqssec)/(L1q))=-0.0044
,(-(1*R1q*(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/L1d))*Laqssec)/(L1q))= 0.0051
,(-(1*R1q*(1-(Laqssec/L1q)+((((0.072+1*(Ladssec+Ll))*Laqssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1q))*Laqssec)))/(L1q))=-0.2349}, {L1d, L1q, Ladssec, Laqssec, Lfd, R1d, R1q, Rfd},useassumptions)

Lfd ~=0.233, R1d~=0.0848, L1d~=0.2, L1q~=-0.09, Ladssec~=0.099, Laqssec~=-0.1, Rfd~=0.00173, R1q~=0.0129

1. 1.    The bending moment M, in a simply supported beam is represented by the formula: (5marks)

 M = w x/2 (l-x)

Where: w = uniformly distributed load in KN per m

            x = distance from the left hand end of the beam in m 

            l = span of the beam in m 

If  = 4KN per m and  = 5m, calculate the value of  where  = 12KNm

Any thoughts on this guys? 

I know this is cheeky but i was wondering if there was anyone out there that would be willing to pretty much do this question for me? i have been at this all night and still not the slightest clue. Any help would be much apprefiated. 

1. 1.    Below are 4 questions that require solving problems by formulating simultaneous equations. Solve each question and explain the method you used. What other methods could be used other than those you have used to solve here. (total 30 marks)

(a)  A penalty clause states that a groundwork’s sub-contractor will forfeit a certain sum of money for each day that they are late in completing a contract (i.e. the sub-contractor gets paid the value of the original contract less any forfeit). If they are 6 days late they receive £5000 if they are 14 days late they receive £3000. (8marks)

1. a.    Find the amount of the daily forfeit
2. b.    Determine the value of the original contract.

(b)  The total cost of purchasing 2 excavators, A and B is £30,000. The 2 tonne excavator costs £2,000 more than the 1.5 tonne excavator. Find the individual cost for each excavator. (7marks)

(c)  You are estimating costs for a heat recovery installation. You know that 100m of 100mm dia ducting and 8 bends cost £100 and 150m of 100mm ducting and 10 bends cost £147.50. Find the cost for 1m of ducting and 1 bend. (8marks)

(d)  You are a Site Manager who is organising a lift utilising a tower crane you have on site. You know that the Force (F) in Newtons required to lift a load (W) in Newtons is represented by the equation F = aW + b. You know that a force of 100N lifts a load of 180N and a force of 150N lifts a load of 280N. Find the values of a and b and the force required to lift a load of 500N. (7marks)

Dear Maple forum,

given A, B real numbers,

and after defining the recurrent sequence

x(0) = A

x(n) = 0.5* x(n-1)^3 + B

I would like to see a graphic of x(n) on the plane x(n) - n.

how could I implement in maple 16?

thank you for your help.

JeanJ

I have my cod and I have written in C++. I get the result lower than which I expected between radius of gyration and scaled temperature to find Theta temperature!

thanks  for your help

Lano

Can Cayley table be converted to function ?

What can Cayley table use in Maple?

Dear sirs/madams,

I tried to use my MAPLE in a MacBook with a quiet large screen...however I see the letter sizes of my Maple16 very small (the same wiht the font size on input and ouput sheets..and everywhere)..

Is there some way to "see larger and bigger"?

Thanks for your attention,

JeanJV

So I have the energy of an ion at a several points in space, where the x and z coordinates have been varied from 0-1, keeping y constant. The data is in the following file: 

y=0.xlsx

When I come to produce a 3D surface plot (grid) of this file using the plots option in the context menu (on right clicking), the following is produced: the x-axis is in red and the y-axis (z-coordinate) is in blue.

Yet if I use the interactive plot builder, to plot the same data, the only option available to me is a 3D point plot, which produces the following:

[If I try to plot a 3D surface plot (points) using the context menu, I get stuck at a evaluating stage...]

as, ideally, I want a surface plot, why, in the surface plot (grid) is MAPLE not recognising the data that corresponds to the higher z-coordinate values and how I can produce a full surface plot... 

Hi, I just want to know if there is simulated annealing programming in maple 14 and where I can get that programming

accroding to http://www.maplesoft.com/support/help/Maple/view.aspx?path=convert%2fVector  set can't be converted to Vector.

So I have to convert set to list, then convert the list to a Vector:

a:={1,2}:
convert(convert(a,list),Vector);

I was wondering if there is a short way to type this or a command that I might have overlooked, as it seems too much typing for such a common operation. (it would be nice if convert would support this automatically by doing the above so one can just type convert(a,Vector).  I am using Maple 17.02. I googled around, and did not find anything.

On a side note: The reason I ask, is that dsolve and many other operations like it, return the solutions as a set. Many times I need to multiply this by a Matrix. Hence the conversion need.

Hi

 I have a problem why the result does not appear..my code are:

> P := array([[8, 4], [8, 3], [8, 2], [7, 1], [6, 0], [5, 0], [4, 0], [2, 1], [1, 1], [1, 4]]);

> for j from 2 to 5 do k[j] := j+1;

x[j] := add(P[j, 1], j = j-1 .. j+2);

X[j] := add(P[j, 1]^2, j = j-1 .. j+2);

y[j] := add(P[j, 2], j = j-1 .. j+2);

Y[j] := add(P[j, 2]^2, j = j-1 .. j+2);

xy[j] := add(P[j, 1]*P[j, 2], j = j-1 .. j+2);

cx[j] := evalf(x[j]/k[j]);

cy[j] := evalf(y[j]/k[j]);

c11[j] := evalf(X[j]/k[j]-cx[j]^2);

c22[j] := evalf(Y[j]/k[j]-cy[j]^2);

c12[j] := evalf(xy[j]/k[j]-cx[j]*cy[j]);

C[j] := evalf(Matrix(2, 2, [[c11[j], c12[j]], [c12[j], c22[j]]]));

E[j] := Eigenvalues(C[j]);

if E[j][1] > E[j][2] then lambda[j] := E[j][2]/(E[j][1]+E[j][2]) else lambda[j] := E[j][1]/(E[j][1]+E[j][2])

end if;

end do;

the If function does not work and the result does not appear. Is there any problem in my code.

 Thanks

1.   The formula to calculate a length of rafter may be given as

Length of rafter = √ (rise)squared + (run)squared            

      (The whole of the RHS has been square rooted but cant type that symbol)

Transpose this equation and express in terms of the rise. Describe each stage so as to clearly identify what you have done.  Using this new equation calculate the rise if the length of the rafter is 7m and the run is 6. Write your answer to 3 s.f. 

If anyone has any ideas or could help it would be really appreciated. Thanks. 

I was asked to transform (x+y)^2+(1)/x+y into ((x+y)^3+1)/x+y, I have tried nomer/denom, but i don't how to factorise the nomer bit into (x+y)^3+1 because maple factorise it differently by default. therefore, it would be grateful if anyone can help me with this...please?

I am trying to run the application "The Cosmic Travel Planner" by Christian Bar (CBaer), uploaded on August 21, 2013 on Maple cloud (Mobius@admin). I use the left panel of GUI where "MapleCloud" is opened. While opening the application GUI asks my permission for running some code automatically. After my 'YES' Maple gives me an error:

Startup Code Error
0, "permission denied: no read access (%1)", "C:\Users\Andriy\MapleLib"

I tried to give the permission to folder "C:\Users\Andriy\MapleLib" however unsuccessfuly.

OS: Win 8

Could you help me with this Error? Thank you.