Hi, this is probably very simple but I can't seem to get Maple to show me the Matrix that I want. Could you please let me know what is the problem?

N₀:=s->1-s;

N₁:=s->s;

N:=s->[N₀(s) N₁(s)];

Both `$`N(s) and N(s) shows me the statement "error, in N[0] too many levels of recursion"

Then I change to N_j:=s->[N₀(s) N₁(s)];

The solution comes out to be [N

HI experts,

can anyone here help mi in transform a Mathematica v8.0 sheet into maple v.15 ?

I am still maple novice.

Thanks a lot 

My MMA file as ZIP:

general_two_compartm.zip

Let A(-5,-3,-3), B(0,1,-2) be two points and

(d): x = t - 3, y = 2*t, z = t+2.

Find the coordinates the point M on (d) so that the area of the triangle ABM obtain minimum value.

This is my code.

restart; with(LinearAlgebra):

A:=: B:=: M:=:

u:=A-B: v:=A-M:

T:=CrossProduct(u,v):

S:=minimize(1/2*Norm(T,2), location = 'true');

M:=subs(op(1,op(1, S[2])),M);

Let A(-2, -1, 3), B(0, 1, 4) be two point and

(d): x = -t-2, y = t+1, z = -t-1 be a line.

Find coordinates point M lies on (d) so that area of the triangle ABM equal to 3*sqrt(5).

This is my code

restart; with(LinearAlgebra):

A:=: B:=: M:=:

u:=A-B: v:=A-M:

T:=CrossProduct(u,v):

sol:=solve(1/2*Norm(T,2)=3*sqrt(5),{t});

for i from 1 to 2 do print('M'[i]=(subs(op(sol[i]), M[1]), subs(op(sol[i]), M[2]),subs(op(sol[i]), M[3]))) end do;

i have a function f(alpha)=1+2cos5alpha, i had no trouble plotting f(alpha), but when i try to plot f(alpha.t) i keep getting empty plot.

please help

create the function f(x)=(x²,x=<0), (2x, 0<x<1), (2sin(Pi.x/2),x>=1). how do you find derivative in one command and integrate f(s)ds from -1 to 2.

Hello,

I have created a MapleSim model including a few custom components. When I try to run the simulation, I receive the following error:

cannot resolve function `Main.'Typesetting:-mambiguous'`; there is no function `'Typesetting:-mambiguous'` visible in model `Main`

How do I know where the source of the error is?

Thank you,

Behzad

how do you analytically and numerically solve the IVP: y" + 4y' + 13y = cos2t, y(0)=2, y'(0)=-1.

Let A(1,0,0) be a point and two lines

d1: (x-5)/3 = (y-1)/1 = (z - 2)/2,

d2: (x-5)/1 = (y-1)/1 = (z - 3)/3

Let B and C be two point lies on d1 and d2, respectively so that the three points A, B, C

If log₁₀5 =c and log₂₀50=d express log₉40 in terms of c and d ?

Hey everyone.

I have been trying to solve an ODE with BC with dsolve,numeric but always get the error below:

> Error, (in dsolve/numeric/BVPSolve) matrix is singular

My problem is not solving it (ie fine to do with LinearAlgebra package or similar), but why does this error occur? What is the problem with the ODE/BC that produces this error?

And is there a way of adjusting the ODE/BC to be able to solve it simply by using dsolve,numeric?

On my Dell Latitude E5400 laptop with up-to-date Fedora 16:

$ maple15
    |\^/|     Maple 15 (X86 64 LINUX)
._|\|   |/|_. Copyright (c) Maplesoft, a division of Waterloo Maple Inc. 2011
 \  MAPLE  /  All rights reserved. Maple is a trademark of
 <____ ____>  Waterloo Maple Inc.
      |       Type ? for help.
>  log[2](8);

I've been trying to solve eqn1,eqn2,eqn3,eqn4 for T[water],T[air],T[Al],T[plastic] by using the defined variables listed above the set of eqn's, but everytime I get the "Warning, solutions may have been lost". Is there a solution to this or are the eqn's unsolvable?

> restart;
>
> h[infinity] := K[infinity]*(0.37e-1*RE[infinity]^(4/5)-871)*Pr[infinity]^3/L[plastic]:
> h[plastic] := N[plastic]*K[plastic]/L[plastic]:
> h[water...

Problem. Write the equation of the plane passing the point H(1,1,1) and cut the coordinates axes Ox, Oy, Oz at A, B, C respectively so that H is centre of the circumscribed of the trianlge ABC.

This is my code.

restart:

with(geom3d):

with(LinearAlgebra):

A:=:

B:=:

C:=:

H:=:

f:=(x,y,z)->x/a + y/b +z/c-1:

solve([f(H[1],H[2],H[3]) = 0, Norm(H - A, 2) = Norm(H - B, 2), Norm(H - A, 2) = Norm(H - C, 2)],{a,b,c}): assign(%):

Problem. Write the equation of the plane passing the point H(2, 1, 1) and cuts the coordinates Ox, oy, oz at A, B, C respectively so that H is orthocenter of the triangle.

This is my code.

restart:

with(geom3d):

with(LinearAlgebra):

A:= <a,0,0>:

B:=<0,b,0>:

C:=<0,0,c>:

H:=<2,1,1>:

f:=(x,y,z)->x/a + y/b +z/c-1:

eq:=solve([f(H[1],H[2],H[3]) = 0,DotProduct(B-C, A-H, conjugate = false...