scmch.mw

I can't get a graph. Is this code is correct.Please help.

sps1.mw

how to plot this.i got error

How to integrate eq (4)? Since 'a', 'b', and 'c' are constant. 

Download integration.mw

sstf.mw

In Graph has curves that are overlapping each other and the values of  S[t] = -1, -2, 1, 2 and also the y axis to range from 0 to 1.

I am trying to separate the real and imaginary parts of a complex expression in Maple to get Eq. (1.5) as in the attached image, but the Re and Im functions do not seem to return the expected results. Instead, Maple leaves the expression unchanged. PD_OD.mw

Is it possible to set a worksheet or maple up to only express trigonometric functions as sines? This is very helpful for certain exotic coordinate systems. Meaning cos(x)=sqrt(1-sin(x)^2)  and NOT equivalently  adding Pi/2 to the argument cos(x)=sin(x+Pi/2).
It is completely useless and futile to do algsubs, as Maple will later just revert back to cosines, so you want to do it in the headers so output is always expressed as sines in the document by default.

Basically you want to set something in the header of a worksheeet to always use expsincos on output, and then in addition cos(x)=k sqrt(1-sin(x)^2)   k\e{1,-1} on the output.

Download liouville_reduced_2-2-2025_mprimes_vraag.mw

I did some example to change them but i didn't get the same result as book did it and i try to figure out by hand i get another result i know all of them are true but polar is for making the simple shap for ploting so How i can get the simple shape and if possible How do step by step like using totur we have for polar or not? 

Download polar.mw

Good day, 

I have this system of differential equations, which I solved numerically. 

Now I need to integrate the function y(t) numerically to get the corresponding expression for 

Z= exp(int y(t) dt ) (integrate from a given t to 0)

then I need to plot that system of differential equation vs (Z) with (t) as the parameter.

can you please help?

 eq1 := diff(x(t), t)-(1/6)*(6*x(t)^3*y(t)+(2*y(t)^2-2)*x(t)^2+3*y(t)*(z(t)-2)*x(t)-2*y(t)^2+2)*sqrt(3) = 0;

eq2 := diff(y(t), t)-(1/6)*(y(t)-1)*sqrt(3)*(y(t)+1)*(6*x(t)^2+2*y(t)*x(t)+3*z(t)-2) = 0;

eq3 := diff(z(t), t)-(1/3)*z(t)*sqrt(3)*(6*y(t)*x(t)^2+2*x(t)*y(t)^2+3*z(t)*y(t)-2*x(t)-3*y(t)) = 0;

eq4 := diff(s(t), t)-(1/3)*(y(t)-1)*sqrt(3)*(y(t)+1)*(6*x(t)^2+2*y(t)*x(t)+3*z(t)-2)*y(t) = 0;

eq5 := diff(Q(t), t)+sqrt(3)*((4/3-z(t)-2*x(t)^2)*y(t)+(2/3*(1-y(t)^2))*x(t))*Q(t)+2*((2/3)*y(t)+x(t))*P(t)/sqrt(3)-(2/3)*R(t) = 0;   
eq6 := diff(P(t), t)+(sqrt(3)*(1-z(t)-2*x(t)^2)*y(t)+2*(2-y(t)^2)*x(t)/sqrt(3))*P(t)+2*sqrt(3)*x(t)*Q(t)+(1/2)*R(t) = 0;       
eq7 := diff(R(t), t)-sqrt(3)*((3*x(t)^2+(3/2)*z(t)+4)*y(t)-(1/3*(1-3*y(t)^2))*x(t))*R(t)-z(t)*P(t) = 0;
eq8 := diff(T(t), t)-sqrt(3)*((6*x(t)^2+3*z(t)+1)*y(t)-(2*(1-y(t)^2))*x(t))*T(t)-(1-y(t)^2)*(Q(t)-(2/3)*P(t)) = 0;   
syst := {eq1, eq2, eq3, eq4, eq5, eq6, eq7, eq8};

ics := x(0) = .1, y(0) = .9, z(0) = .1, s(0) = .2, Q(0) = .1, P(0) = .9, R(0) = .1, T(0) = .2;
  

sol1 := dsolve({ics, op(syst)}, {P(t), Q(t), R(t), T(t), s(t), x(t), y(t), z(t)}, type = numeric, output = listprocedure);
 

Hi All,

Maple is changing fast. It is not possible to run some older codes. 

Is it possible those who have a valid Maple license to have the old versions free of charge?

I have Maple 7, 2018, 2021 licenses but still have problem running older codes.

I read the install.html that is installed with Maple2024 and the instructions to increase stack and heap limits are definately outdated.

None of the files they list there for Linux even exists after the Maple2024 installation.

So where exactly can I set the stack and heap size limits on Linux,  as Maple give me stack and heap errors.

Hello,
I have another vector problem, and I honestly have no idea how to solve it. (I am not even sure if there is a solution). I tried to simplify it as much as possible (also the attached maple file)unknown_vector.mw

We are looking for the vectors v2, v3 and v4 
Given are vector v1 (with its unit vector e1 and magnitude m1), the unit vector of v2 (e2) and the unit vector of v3 (e3)
From vector v4 we don't have any information.
The following should be true:
v2 = v1 + v3 + v4, with the condition that v4 shall be as small as possible, with the goal to find the combination of v1 and v3 that comes as close as possible to v2. Of course, depending on the unit vectors, v4 can also be zero. But we assume that the given unit vectors can not be changed. 
I would be really grateful for any help. Thanks in advance! 
Roman

I have two equations on either side of an inequality that contain like terms such as Am and Ce. Could you simplify the expressions by mathematically eliminating these common terms from both sides? For example, if we have an equation like x+y⋅d+hx=g⋅f+hx , it simplifies to x+y⋅d=g⋅f.

Additionally, please solve for Cv and Ce.

Note: All terms are positive except R0er and R0m​.

I am attaching the relevant sheet for reference. Q_12.mw

Download BE.mw

Hi,

Experiencing the following problem.  One of our servers was cloned, the GUID was replaced and then rejoined to the domain.  All applications are working exept Maple.  The application launches but then closes right away.  No error messages provided so not sure where else to look for possible fixes to this problem.  The application is runing on Server 2022.

Thank you.