MaplePrimes Questions

Hello guys..

I am a master student and I am interested in modelling of six dof industrial robots. in this study, ı firtsly import autocad model into Maplesim and add revolute jont between each  two link. I want to coriolisis matrix from the model with inertia matriix . I wait your helping and thanks for your interest   

What shall I do to install Maple 15 and MapleSym 5 in a Windos 10 environment.

I find the procedure in Maplesoft site up to Windows 8.

May I follow it for Windows 10.

Thank you for any help. Kind regards

Hi everyone,

I created a procedure "SIM" which depends on two formal parameters x and y. I write Threads:-Map(SIM, x, y) in order to execute it with the Threads package.

I would like to create .mpl files automatically, each one made of the code Threads:-Map(SIM, x, y) with specific values of x and y. For instance:

Threads:-Map(SIM, 5000, 1), then Threads:-Map(SIM, 5000, 2) ... and so on until Threads:-Map(SIM, 5000, 5000).

The fact is, I tried writing the following:

for y from 1 to 5000 do
a[y] := Threads:-Map(SIM, 5000, y);
save a[y], sprintf("SIM_%d.mpl", y)
end do

However, it does not work. The error message says "Error, save can only save names". I also tried, but without success:

for y from 1 to 5000 do
a[y] := Threads:-Map(SIM, 5000, y);
save convert(a[y], name), sprintf("SIM_%d.mpl", y)
end do

Any idea? Thanks a lot.

 

 

I want to plot the argument for a complex function. The input (x,y) represented in polar coordinates (r,phi) by default puts the cut at -I*Pi. Likewise the argument function:

argument(f(x)) plots the range -Pi..Pi.

However the function f(x)=x^2 could typically be plotted with 2 riemann surfaces on top of each other. When phi becomes 2Pi f(x) becomes 4Pi and only then I want to identify the 0 with 4Pi again since the points are equivalent in the preimage.

On the other hand the function f(x)=sqrt(x) never surpasses its own domain. The values always stay within the argument range of (0,2Pi) (in fact it only goes till Pi, or -Pi/2..Pi/2 in maple) when the preimage is taken to be (0,2Pi). Thus when plotting a preimage value of (x,y) with argument phi and 2Pi+phi they will have the same value since phi=2Pi+phi and I see a step in the plot. This step is actually there since the function has a cut at this point.

This step in the plotting image is also shown for f(x)=x^2 (e.g. at phi=+-Pi/2) but it is not of importance since it just comes from the argument function being constrained to -Pi..Pi.

So is it possible to change this behaviour?

Can i make Explore with number of parameters differs from parameter in explore?
For excemple i whant to make sum with 'l' values wich will declorate in explore, and 'l' - count of them will declorate in same explore, but it dont work, so is it posible?
 

restart

``

``

Explore(add(cat('c', eval('i')), i = 1 .. l), parameters = [l = [seq(i, i = 1 .. 5)], seq(cat('c', eval('i')) = 0 .. 1.0, i = 1 .. l)])

Error, unable to execute seq

 

``

ec := proc (l) global f, p; f := add(cat('c', eval('i')), i = 1 .. l); print(f); p := [seq(cat('c', eval('i')) = 0 .. 1.0, i = 1 .. l)]; Explore(f, parameters = p) end proc;

proc (l) global f, p; f := add(cat('c', eval('i')), i = 1 .. l); print(f); p := [seq(cat('c', eval('i')) = 0 .. 1.0, i = 1 .. l)]; Explore(f, parameters = p) end proc

(1)

``

ec(4);

c1+c2+c3+c4

(2)

Explore(ec(l), l = [seq(i, i = 1 .. 5)])

c1

(3)

``

NULL


 

Download Explore_Problem_Exemple.mw

 

I need yours hepl.  I work with the physics paсkage and I set:

with(Physics)

Setup(mathematicalnotation = true)

 Coordinates(X)

Setup(Dgammarepresentation = standard)

Setup(spaceindices = uppercaselatin)

Define(M, aa, mu, mu5, Pi, eta)

M_[mu, mu5] := Dgamma[mu]*d_[mu]+M+Psigma[A]*aa[A]-mu*Dgamma[0]-mu5*Dgamma[0]*Dgamma[5]+i*Dgamma[5]*Psigma[B]*Pi[B]+i*Dgamma[5]*eta

And next:

Dagger(M_[mu, mu5])

How is Maple explained that  

Dagger(d_[mu])=d_[mu]

conjugate(M)=M

conjugate(aa[A])=aa[A]

conjugate(i)=i

and so on?

Dear Friends, I work with physics paсkage. I have a quation. I don't understend how one works with metrics. For example, let:

Nice!
Very good!

1) It doesn't work. Why? (I want exactly gamma_[A,B], rather than g_[A,B], because as i guess gamma_[A,B] has a signature [1,1,1] but g_[A,B] has a signature [-1,-1,-1])

 2) And how may I see what is matrices g_[A, B], gamma_[A, B] explicitly? That is I know how to see what is g_[mu, nu], for this one needs write "g_[];".  But how may I see g_[A, B] and gamma_[A, B] in explicitly forms?

3) Why command Trace(g_[mu, nu]))  does not work?"

i want to have plot int.  but i get error 

"Error, (in type/EvalfableProp) too many levels of recursion"

how can i draw this plot

please help me . thank you

Simple issue. I think it is a bug, but if not, it tends to cause logic problems with new users of Maple.

with(plots):
z := A*x*y:
A:=1.0:
plot3d(z, x=0..1, y=0..1); # works as expected
contourplot(z, x=0..1, y=0..1); # works
fieldplot(z, x=0..1, y=0..1); 
    --> Error, (in plots/fieldplo) invaled 1st argument (the function) 1.0*x*y

Is there something special about what the fieldplot expects for the function? I don't see it in the help. Or is this a bug?  

Yes, there is a work around, define all constants first

A:=1.0:   z := A*x*y: fieldplot(z, x=0..1, y=0..1); 

But I fail to understand why my example should fail. (Note, I have seen this situation for every version, so it is not new.)

Any way to type in dy/dx differentiation without having to use the graphic pallete?

I can do a couple of ways ..

y'

diff(y,x)

but dy/dx direct typing eludes maple, I thought there was a way at one time

Silly, but what command will move the one first under the sqrt here...

a:=sqrt(1+x^2)  # maple moves the x^2 in front
                           sqrt(x^2+1)

What maple command will move the 1 in front of the x^2 under the square root?

I'm trying to plot contours in Maple, but the 2d contour plot output is not pretty. I tried the following command:

contourplot(-(1/2)*y^2-(1/2)*x^2-(1-.3)/sqrt((x+.3)^2+y^2)+((-1)*.3)/sqrt((x-1+.3)^2+y^2), x = -1.5 .. 1.5, y = -1.5 .. 1.5, axes = boxed)

and the plot is so much uglier than the 3d one:

contourplot3d(-(1/2)*y^2-(1/2)*x^2-(1-.3)/sqrt((x+.3)^2+y^2)+((-1)*.3)/sqrt((x-1+.3)^2+y^2), x = -1.5 .. 1.5, y = -1.5 .. 1.5, view = -2 .. -1.3, axes = boxed)

Is there any way I can get the same detail in the 2d one as there is in the 3d one.

Thanks in advance!

Hello everyone !

I have several values loaded into Maple as a matrix from a .txt file (output of my measurement).

I measured power in dependence on time.

Here is an example of my txt file in which the first column represents the time and the second column represents the force:

29.04 997.54
29.06 998.83
29.08 999.79
29.10 1000.76
29.12 1001.72
29.14 1003.01
29.16 1003.81
29.18 1004.94

From 3624 values I need to get specific amount of values, lets say 3000, while keeping the course. We could call it a dilution I guess.

Here is a simple illustration of the problem:

So I am asking you to help me find out some function to dilute measured values while keeping the curve.

I will be grateful for any advice.

Dear All

Please see my query below:


 

Suppose I have a expression whose terms are in summation:

sum(P[n]*xi^n, n = 0 .. infinity)+(sum(P[n]*xi^n, n = 0 .. infinity))^2+sum(P[2*n+1]*P[2*n]*xi^n, n = 0 .. infinity)

sum(P[n]*xi^n, n = 0 .. infinity)+(sum(P[n]*xi^n, n = 0 .. infinity))^2+sum(P[2*n+1]*P[2*n]*xi^n, n = 0 .. infinity)

(1)

diff(sum(P[n]*xi^n, n = 0 .. infinity)+(sum(P[n]*xi^n, n = 0 .. infinity))^2+sum(P[2*n+1]*P[2*n]*xi^n, n = 0 .. infinity), xi)

sum(P[n]*xi^n*n/xi, n = 0 .. infinity)+2*(sum(P[n]*xi^n, n = 0 .. infinity))*(sum(P[n]*xi^n*n/xi, n = 0 .. infinity))+sum(P[2*n+1]*P[2*n]*xi^n*n/xi, n = 0 .. infinity)

(2)

In above summation, how I can write specific term ? For example, how I can display term for n = 2etc.

NULL


 

Download Summation.mw

Dear Friends, I work with physics paсkage. And I don't know how to simplify the next expression: Dgamma[mu]*a[mu]*Dgamma[nu]*a[nu]

(I want to obtain  the well-known result a2 )

The command "Simplify" doesn't work in this case.

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