Need to do in maple smth like that:

I am searching for an analytical solution, if one exists, of a first-order differential equation of the Chini type, which is a generalization of the Abel type. The equation I'm trying to solve is very closely related to one presented in Maple's help files and which does admit an integral representation, namely the equation reported by Kamke as number 152 (according to the reference given in Maple). The equation I'm grappling with is similar to Kamke152 but with the forcing...

Let A(2;-2;3), B(4;-5;6) and (M(1;2;3) be three points. Write the equation of the plane (P) passing through two points A and B 

Problem: Write the equation internal bisector and external bisector of a triangle ABC with A(1,2,-7), B(3,-1,-1), C(-5,14,-3). This is my code.

restart;
> with(LinearAlgebra):
> A:=: B:=: C:=: M:=:

>v:=1/Norm(A-B,2)*(A - B) + 1/Norm(A-C,2)*(A - C): M=A + v*t;

>u:= 1/Norm(A-B,2)*(A - B) - 1/Norm(A-C,2)*(A - C): M=A + u*t;

in the commands M = A + v*t and M = A + u*t, please comment for me. Thank you.

Hello everybody,

I represented a polynomial P type:
P := a + b*x + c*x^2-d*y + e*y^2 + f*x*y
(where a, b, c, d, e, d, are real)

using fucntion pointplot3D
G1 := plot3d(P, x = 0 .. 5, y = -0,5 .. 1);
display(G1);

I represented this polynomial which look like a paraboloid.

I'm just wondering if I can animate continuously...

Have s:={'a', 'b'};

a:=4;

naturally s[1] resolves to 4. Moreover, eval(s[1],1)=4, so s successfully should forget about a.

But...

a:='a'; and s[1] returms... again a.

So, why dereferencing of pointers  is not the same as 'eval 1-level' resolving?

How actually can i unassign 'a' having s only?

Or (not obviously, but same!) related question:

how to obtain s1:={'a', 'b'} having s={a,b} with nonresolvable a and b .i.e. eval(smth, -1)?

Is there any command in Maple 15 to linearize an PDE non-linear? Or or there is a package or help file to do so?

I'm handling with Non-linear PDEs in my work and I would like to solve them by these methods.

Thank You

Washington Inacio

It's possible to define a field in Maple 15 with 2 kinds of indices, say type spacetime μ,ν,ρ... and one of the type integer, i,j,k varying from 1 to n?

I would like to define a field like A_μⁱ where:

A_μ¹=A_μ

A_μ²=B_μ 

and so on.  

Thank you Washington Inacio

I expected

int(x^(-13/10), x):
eval(%,x=1000)-eval(%,x=1/1000);

but i get

int(x^(-13/10), x=1/1000..1000);

Write a procedure, primesum, whose input is a positive integer n and whose output is the sum of all primes p such that p is less than or equal to n. You may use th built-in procedure isprime.

Bonjour

Je n'arrive pas à faire fonctionner un montage simple.

J'ai un message d'erreur : (in dsolve/numeric/RunSimulation) unable to compile, please check your options by running with infolevel [ToExternal]:=1; simulation failed.

Que dois-je faire ?

Windows 7  64bits / Maple 61bits

Merci

Greetings,

I have purchased Maple 15 Student Edition 2 months ago. My problem is that when I click the button under the text "To obtain a complete annotated solution, click:" Maple crashes. This happens in the browse tasks window accessed through Tools>Tasks>Browse. In addition to this issue, the interactive commands does not seem to work. How can resolve these issues? I am running a 64-bit version of Maple 15 under Windows 7 Home Premium 64-bit.

Any help is appreciated.

MAPLE is not able to show me the output of nested loop. How can I get it?

for i from 0 to N do for j to 3 do

eqn[i] := sort(coeff(lhs(dequn[j]), epsilon, i)) = coeff(rhs(dequn[j]), epsilon, i)

end do

nested_loops.mwend do

What is the difference between them?

daesys0:={diff(I3(t),t) = 1/L*u(t), I1(t) = I3(t) + 1/R * u(t), I3(0)=0, I1(0)=0};

and

daesys0:={diff(I3(t),t) = 1/L*u(t), I1(t) = I3(t) + 1/R * u(t), I3(0)=0};

If I use the procedure for numerical solution, their solutions are similar.

Suppose I have a system of three coupled equations as:

eqn[1] := a*x+b*x^2+c*x^3

eqn[2] := a1*x+b*x^3

eqn[3] := a2*x^2+b2*x^3 = a*x^2

If I simply write

eqs :=( eqn[1], eqn[2], eqn[3])

the equations get coupled.

1. Can I do it using loop structure?

2. Secondly, after coupling suppose I want to collect coefficoent of x, x^2 and x^3 from three equations ang get the equation in form

eq[0]:=a=0,a1=0