I would like to ask a 2-part question in Maple TA in which the correct response to the second part of the question is based on the student's response to the first part of the question.

Here is a simple example.

Question #1

A) What is 1+4 ?

B) What is 2 times your solution to part A?

Obviously, the correct answer to B is 10, but what if the student thought that the correct answer to A was 4? Then if they put 8 as the answer to B I would...

When I write

evalf(Pi);

I get  3.14159...

But, when I want to visualize the value  "e", after writing 

evalf(e);

I get       e .

Why I cannot see the digits of "e"?

Did I instal not properly my Matlab14.0?

Hi,

Just a simple question:

How do I unassume (remove the assume) all the variables in my code in the easiest way?

Thanks a lot for your help.

In a loop (variables set to some calculation) when maple produces an error how can I set it to a value of zero?

I want to find the first positive and first negative root of a bessel function

j2 := (x, a) -> k(x)^2*a^2*(diff((diff(1000000000*sin(1/1000000000*k(x)*a)/(k(x)*a), x))/(k(x)*a), x))/(k(x)*a)

I couldn't use the built in bessel function with two variables, so I had to enter it by hand.

I want to find the values of x where j2 is zero as a function of a:

f := (a) -> RootOf(j2(x, a), x, 0 .. 2)

plot(f(a), a = 2 .. 2.25, y = -3 .. 3)

Hey folks. I have a massively complicated equation I'm trying to solve and the internal memory can't take it.

Here is the problem.

Let f(x) := 1 - lambda*x^2

alpha := 1/f(1)

By solving the following equation,

alpha*f(f(x/alpha)) = f(x) + O(x^4)

We can determine a value of lambda and hence alpha (for which the real value is roughly -2.5 and the calculated value here is roughly -2.7).

hello everybody

please heeeelp

In the name of God

Dear friends

Hi

I have a question about releasing a part of memory occupied by some lists, sequences and matrices, for example matrix "M" or list "L".

If we use the following commands to allocate amount of memory for a matrix or list:

M:=Matrix(2000,2000,float[8]);
L:=[seq(equ[i],i=1..10000)]:

where equ[i...

hello everybody can you help me please

how can i canvert this list [1,2,3,4,5,6] to a number 123456

hi ,friends

  now ,i get a matrix of symbolic expression,it's difficulty to find the simplest forms using the common command  as like simplify or combine

p := Matrix(4, 4, {(1, 1) = (1/2)*exp((1/2)*J[1]-(1/2)*J[2]+(1/2)*J[3])+(1/2)*exp(-(1/2)*J[1]+(1/2)*J[2]+(1/2)*J[3]), (1, 2) = 0, (1, 3) = 0, (1, 4) = (1/2)*exp((1/2)*J[1]-(1/2)*J[2]+(1/2)*J[3])-(1/2)*exp(-(1/2)*J[1]+(1/2)*J[2]+(1/2)*J[3]), (2, 1) = 0, (2, 2) = (1/2)*exp(-(1/2)*J[1...

Hello friends,

When I solve the optimization problem with restriction (below):

NLPSolve( ln(x1) +ln(x2+5), {x1 +x2 <=4}, assume = nonnegative);
     [-Float(infinity),

       [x1 = HFloat(0.0), x2 = HFloat(0.8333333333333334)]]

I get the expression  "-Float(infinity)"..

What do Float(infinity) and  HFloat(0.833333) mean?

Thanks for the attention,

Hello everybody!

I'm working on a statistical problem. I need to plot confidence regions for parameters in the model, but I don't know what I should do. I tried to get some programs from the internet, but either they don't work or I don't understand details of them to change for my work. Can someone introduce a good program to me?, or does anyone have another useful idea for me?

Thanks a lot!

I meet a problem in the use physcis package.

    for example,

                                   restart;  with(Physics); Setup(mathematicalnotation = true):

                  ...

I am analyzing a system that was at steady state and then subjected to a step change.  I have the steady state modeled with a system of ODEs.

I am going to model the step change with a system of PDE's.  The system will be discretized in space and time (z,t).  I know how to setup one side of the boundary conditions (0,t) for all variables, but the other (i.e A(z,0)) I would like to use the results of the steady analysis. Does anybody have some ideas on...

I would like to do the following

A[1,1],A[2,2],A[3,3]:=seq(i+2,i=1..3)

using seq on the left-hand-side. I know I have done it in the past but don't get it this time. End up with error messages. Not sure what am I missing.

thanks a lot

Dimitrios