Unanswered Questions

This page lists MaplePrimes questions that have not yet received an answer

How to change the numbers shown in the diagram shapes from y=0.5- to rigth form y=-0.5a.mw

Download a.mw


 

 

 

 

 

 

Hello,

Please , how can we plot two figures with different X-axis and the same Y-axis ?

Thank you

 

general_solution.mwI want to calculate the diff equations numerical solutions at z=500 with calling the integrals with limits -500..Z and i want the datefile of resualts

 

Dear authors,
How to solve this ode problem.

Download link ode.mw

In this problem the boundary condition is

Note: F=g in our problem.

eta approaches N.

Thank you.

 

Hello, I need to figure out what theta is through this matrix:

https://imgur.com/RldbcJD

Should I use a solve command for this?

Executing the entire worksheet several times I obtain random results for Threads:-Seq

restart;

N:=10^3;
f:= (a,b) -> add(evalf(j), j=a..b);

1000

 

proc (a, b) options operator, arrow; add(evalf(j), j = a .. b) end proc

(1)

seq(f(k*N/4+1,(k+1)*N/4), k=0..3);

31375., 93875., 156375., 218875.

(2)

Threads:-Seq(f(k*N/4+1,(k+1)*N/4), k=0..3);

31218.+j, 93875., 156375., 218875.

(3)

Threads:-Seq(f(k*N/4+1,(k+1)*N/4), k=0..3);

31375., 93875., 156375., 218875.

(4)

Threads:-Seq(f(k*N/4+1,(k+1)*N/4), k=0..3);

31900., 94170., 156375., 218875.

(5)

 


Download threads!.mw

 

I need to find all integer solutions of these multivariable equations (and many more similar equations)

I have the boundary conditions that b-1 ≥ a1 > a2 ≥ 0

How can I do this in Maple?

For context, b is a base and a1 and a2 are digits in a b-adic number where a1 is bigger than a2. Solutions to these equations correspond to numbers that have a particular property.

 

I have posted this question on math.stackexchange, but saught an algebraic approach rather than a computational one. Here it is shown that a1 and a2 are linear functions of b. This is where the families of solutions come in. Mathloves answer is detailed and potentially useful in regards to formatting the answer.

https://math.stackexchange.com/questions/3001095/integer-solutions-of-a-variable-coefficient-polynomial

 

Thank you for any help / advice. Ben

I have to use the Chinese Remainder Theorem but once I have found m^e I cant seem to figure out a way that works to get just the message without the exponent. I assumed that the exponent is 3 since the message was encrypted 3 different times. How can I do this with Maple?

CRA_project.mw

is possible to solve this pde via maple?

m1.mwm1.mw
 

restart

sys := [-(-r^2+1)*(diff(theta(r, z), z))+(diff(theta(r, z), r)+r*(diff(theta(r, z), r, r)))/r+diff(theta(r, z), z, z)+(diff(theta(r, z), r))*(diff(sigma(r, z), r))+(diff(sigma(r, z), z))*(diff(theta(r, z), z))+(diff(theta(r, z), r))^2+(diff(theta(r, z), z))^2 = 0, -(-r^2+1)*(diff(sigma(r, z), z))+(diff(sigma(r, z), r)+r*(diff(sigma(r, z), r, r)))/r+diff(sigma(r, z), z, z)+(diff(theta(r, z), r)+r*(diff(theta(r, z), r, r)))/r+diff(theta(r, z), z, z) = 0]; IBCs := {sigma(1, z) = 1, sigma(r, 0) = 1, theta(1, z) = 1, theta(r, 0) = 1, (D[1](sigma))(0, z) = 0, (D[1](theta))(0, z) = 0, (D[2](sigma))(r, 1) = 0, (D[2](theta))(r, 1) = 0}

[-(-r^2+1)*(diff(theta(r, z), z))+(diff(theta(r, z), r)+r*(diff(diff(theta(r, z), r), r)))/r+diff(diff(theta(r, z), z), z)+(diff(theta(r, z), r))*(diff(sigma(r, z), r))+(diff(sigma(r, z), z))*(diff(theta(r, z), z))+(diff(theta(r, z), r))^2+(diff(theta(r, z), z))^2 = 0, -(-r^2+1)*(diff(sigma(r, z), z))+(diff(sigma(r, z), r)+r*(diff(diff(sigma(r, z), r), r)))/r+diff(diff(sigma(r, z), z), z)+(diff(theta(r, z), r)+r*(diff(diff(theta(r, z), r), r)))/r+diff(diff(theta(r, z), z), z) = 0]

 

{sigma(1, z) = 1, sigma(r, 0) = 1, theta(1, z) = 1, theta(r, 0) = 1, (D[1](sigma))(0, z) = 0, (D[1](theta))(0, z) = 0, (D[2](sigma))(r, 1) = 0, (D[2](theta))(r, 1) = 0}

(1)

NULL


 

Download m1.mw

 

convert(...,Int) in Maple 2018.2 works for fourier, invfourier, laplace, but does not work for invlaplace.  

Why is that? Is there a workaround?

expr:=fourier(f(x), x, w):
convert(expr,Int);

expr:=invfourier(f(w), w, x):
convert(expr,Int);

expr:=laplace(f(s),s,t):
convert(expr,Int)

expr:=invlaplace(f(s),s,t):
convert(expr,Int)

Was expecting to see the Mellin's inverse formula.

Maple 2018.2 on windows 10

 

 write a programe for fractional calculus and it shows subscript error plzz help me with that

hai, 
greetings,

I require help to plot graphs by changing differernt parameters. i am enclosing my codes and sample codes,

 my_codes.mw

nanofluid_sample.mw

Thanks in advance.

Ok so when a module is loaded, there is a .dll file that loads a list of symbols into maple.exe, what can be done if an error occurs for which the debugging output declares that the PDB file for the module could not be found? 

I have read that the program database file stores debugging information related to the locating symbols, how can i fix this if my computer isn't finding theres files for a list of .dll it attempts to load into maple.exe, or is there a way for which i can make these files for each corresponding module?

It seems that the forum activity of the user  Markiyan Hirnyk   is no longer accessible.
Is it a site problem?

how I can pdsolve these equations?

moadelat.mw


 

NULL

restart

f1 := -3*(diff(theta(r, z), z))+(diff(r*(diff(theta(r, z), r)), r))/r+diff(theta(r, z), z, z)+2*((diff(theta(r, z), r))*(diff(sigma(r, z), r))+(diff(sigma(r, z), z))*(diff(theta(r, z), z)))+4*((diff(theta(r, z), r))^2+(diff(theta(r, z), z))^2) = 0; f2 := -3*(diff(sigma(r, z), z))+2*((diff(r*(diff(sigma(r, z), r)), r))/r+diff(sigma(r, z), z, z))+(diff(r*(diff(theta(r, z), r)), r))/r+diff(theta(r, z), z, z) = 0

-3*(diff(theta(r, z), z))+(diff(theta(r, z), r)+r*(diff(diff(theta(r, z), r), r)))/r+diff(diff(theta(r, z), z), z)+2*(diff(theta(r, z), r))*(diff(sigma(r, z), r))+2*(diff(sigma(r, z), z))*(diff(theta(r, z), z))+4*(diff(theta(r, z), r))^2+4*(diff(theta(r, z), z))^2 = 0

 

-3*(diff(sigma(r, z), z))+2*(diff(sigma(r, z), r)+r*(diff(diff(sigma(r, z), r), r)))/r+2*(diff(diff(sigma(r, z), z), z))+(diff(theta(r, z), r)+r*(diff(diff(theta(r, z), r), r)))/r+diff(diff(theta(r, z), z), z) = 0

(1)

f3 := sigma(r, 0) = 1, theta(r, 0) = 1, (D[2](theta))(r, 1) = 0, (D[2](sigma))(r, 1) = 0, (D[1](theta))(0, z) = 0, (D[1](sigma))(0, z) = 0, sigma(1, z) = 1, theta(1, z) = 1

sigma(r, 0) = 1, theta(r, 0) = 1, (D[2](theta))(r, 1) = 0, (D[2](sigma))(r, 1) = 0, (D[1](theta))(0, z) = 0, (D[1](sigma))(0, z) = 0, sigma(1, z) = 1, theta(1, z) = 1

(2)

``


 

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