Bengu Kaplan

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16 years, 139 days

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These are questions asked by Bengu Kaplan

Hello,
I have a second problem which is related to converting horizontal axis to degrees ( or in terms of Pi :  0 - Pi/2 ).

Thank you for your helps

Bengu


restart;
s1 := (1/3*(4*(1.66+10^(-1))^2-x^2))^(3/2)/(x^2*(1+.66+10^(-1)))-sin(2*a);
s2 := (1/3*(4*(1.66+10^(-2))^2-x^2))^(3/2)/(x^2*(1+.66+10^(-2)))-sin(2*a);
s3 := (1/3*(4*(1.66+10^(-3))^2-x^2))^(3/2)/(x^2*(1+.66+10^(-3)))-sin(2*a);
k1 := series(s1, x);
                    (-2)                                 
       4.769067180 x     + (-0.5773502688 - 1. sin(2. a))

                           2    / 4\
          + 0.01164914507 x  + O\x /
k2 := series(s2, x);
                    (-2)                                 
       4.293792441 x     + (-0.5773502692 - 1. sin(2. a))

                           2    / 4\
          + 0.01293857500 x  + O\x /
k3 := series(s3, x);
                    (-2)                                 
       4.247636750 x     + (-0.5773502693 - 1. sin(2. a))

                           2    / 4\
          + 0.01307916821 x  + O\x /
p1 := convert(k1, polynom);
  4.769067180                                                2
  ----------- - 0.5773502688 - 1. sin(2. a) + 0.01164914507 x 
       2                                                      
      x                                                       
p2 := convert(k2, polynom);
  4.293792441                                                2
  ----------- - 0.5773502692 - 1. sin(2. a) + 0.01293857500 x 
       2                                                      
      x                                                       
p3 := convert(k3, polynom);
  4.247636750                                                2
  ----------- - 0.5773502693 - 1. sin(2. a) + 0.01307916821 x 
       2                                                      
      x                                                       
with(plots, implicitplot);
implicitplot([p1, p2, p3], a = 0 .. (1/2)*Pi, x = 0 .. 3, style = point, symbol = [box, cross, circle], labeldirections = [horizontal, vertical], labels = ["θ (radians)", "Switching  field (T)"], color = [blue, red, black], symbolsize = 13);


Hello,

How can I fit my equation with the experimental data given below? 

My equation is:  y = A*y^3+B*x ,  where x is the independent variable,  and y is the dependent variable. 
Also how can I determine A and B constants? 
Thanks

Bengu


restart;
Xvals := [.53993447, .5599647, .57995479, .59995566, .61996118, .63994512, .65994136, .6799731, .69996782, .71997949, .73997422, .75995044, .77994976, .7999707, .81995146, .83995244, .85996729, .87994951, .8999458];
Yvals := [-.79625455, -.75585259, -.67800183, -.47955884, -.25493698, -0.65747361e-1, .10114507, .26994542, .41484068, .50621122, .60363251, .65510417, .7251356, .75804148, .76002419, .8030069, .82774732, .8429559, .8692888];
with(Statistics);
points := ScatterPlot(Xvals, Yvals);
PLOT(CURVES(Matrix(19, 2, {(1, 1) = .53993447, (1, 2) = 

   -.79625455, (2, 1) = .5599647, (2, 2) = -.75585259, (3, 1) = 

   .57995479, (3, 2) = -.67800183, (4, 1) = .59995566, (4, 2) = 

   -.47955884, (5, 1) = .61996118, (5, 2) = -.25493698, (6, 1) 

   = .63994512, (6, 2) = -0.65747361e-1, (7, 1) = .65994136, 

   (7, 2) = .10114507, (8, 1) = .6799731, (8, 2) = .26994542, 

   (9, 1) = .69996782, (9, 2) = .41484068, (10, 1) = .71997949, 

   (10, 2) = .50621122, (11, 1) = .73997422, (11, 2) = 

   .60363251, (12, 1) = .75995044, (12, 2) = .65510417, (13, 1) 

   = .77994976, (13, 2) = .7251356, (14, 1) = .7999707, (14, 2) 

   = .75804148, (15, 1) = .81995146, (15, 2) = .76002419, (16, 

   1) = .83995244, (16, 2) = .8030069, (17, 1) = .85996729, 

   (17, 2) = .82774732, (18, 1) = .87994951, (18, 2) = 

   .8429559, (19, 1) = .8999458, (19, 2) = .8692888}, datatype 

   = float[8]), COLOUR(RGB, 0., 0.054901961, 0.47058824), 

  STYLE(POINT)), AXESLABELS("", ""), VIEW(DEFAULT, DEFAULT))
with(plots);
display(points);

Statistics:-Fit(a*y^3+b*x, Xvals, Yvals, y);
                              3                             
   HFloat(2.996866026020011) y  - HFloat(0.9272751314432008)
example("?");

  

 

Hello,

My equation is the following:

Y = 1 - ( sin (2*theta)/ (X+cos(2*theta)))^2

where theta=20 degrees = pi/9  and X= 0..30. How can I numerically calculate Y as a function of X.  And also how can I plot Y(X),

Y(1/X)  and  Y(1/X^2). I like to do these for different theta values (i.e., theta=2*pi/9,  theta= 3*pi/9,,,,,, theta=4*pi/9 ).

Thank you in anvance

Bengu

Hello,

I have an equation which is   Y=A*x^3 +B*x.     Y=-60..60  and  x=-1..1

How can I find the A and B parameters using Maple?

thanks

Bengu

Hi,

My equation is  Y= m.Y^3 + n. B

y: (-1..1) and  B: (-60..60)   have this values.

How can I fit the m and n parameters by using maple7?

And also how can I plot  Y(B) ? Thanks.
 

Regards,

Bengu

 

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