## 10 Reputation

11 years, 73 days

## making B periodic to 2 *Pi...

Hi Douglas,

Thanks for the previous help.  I just need some help in making the function periodic over 2*Pi instead of alphad.

`beta := 0.25;alpha0 := 0.2580;alphad := 0.545;Bmax := 0.7;B1 := (1-beta-beta*cos(Pi*alpha/(0.8*alpha0)))*Bmax;B2 := Bmax;B := piecewise( alpha<0.8*alpha0, B1, B2 );plot( B, alpha=0..alphad );`

I shall be very thankful if you could help me.

Kind Regards

A.Q.

## Thanks Doug Meade and Kitonum...

I am very greatful for your kind replies. My program is working fine now with your help.

Kind Regards

A.Q

## Thanks Doug Meade and Kitonum...

I am very greatful for your kind replies. My program is working fine now with your help.

Kind Regards

A.Q

## Thanks Alot Acer...

Hi  Acer,

Thanks alot for the solution.  It not only worked but gave me insight to the problem as well.

Best Wishes

A.Q

## Thanks Alot Acer...

Hi  Acer,

Thanks alot for the solution.  It not only worked but gave me insight to the problem as well.

Best Wishes

A.Q

## Thanks...

Thanks Axel problem solved,

As you mentioned I have to define angles in radians rather than degrees.

Best Regards

A.Q

## Thanks...

Thanks Axel problem solved,

As you mentioned I have to define angles in radians rather than degrees.

Best Regards

A.Q

## overflow...

@Markiyan Hirnyk @acer 7136

Hi Markiyan and Acer,

Thankyou for the answers,  but I think I didn't write my Question properly.  Sohere it is again:

If I have a matrix A = [1 2 3] , I need Matrix B = [[A]  [A]  [A]]   lets assume Matrix A IS DIAGONAL.

In Matrix B = [[A] [A] [A]]  diagonal.

The method suggested by you guys cause over flow as it increase the size of matrix B.  I actually want matrix A= [3*3] in another matrix B= [3*3]   where each diagonal element is [A] as mentioned above.

Sorry if I got it wrong but actually I need above.

Best Regards

A.Q.

## overflow...

@Markiyan Hirnyk @acer 7136

Hi Markiyan and Acer,

Thankyou for the answers,  but I think I didn't write my Question properly.  Sohere it is again:

If I have a matrix A = [1 2 3] , I need Matrix B = [[A]  [A]  [A]]   lets assume Matrix A IS DIAGONAL.

In Matrix B = [[A] [A] [A]]  diagonal.

The method suggested by you guys cause over flow as it increase the size of matrix B.  I actually want matrix A= [3*3] in another matrix B= [3*3]   where each diagonal element is [A] as mentioned above.

Sorry if I got it wrong but actually I need above.

Best Regards

A.Q.

## Thanks alot...

I am really thankful to you Markiyan and Axel.  I can see my mistake now.

Your advice is well taken and implemented.

Best Regards to both of you

A.Q

## Thanks alot...

I am really thankful to you Markiyan and Axel.  I can see my mistake now.

Your advice is well taken and implemented.

Best Regards to both of you

A.Q

## Thanks...

helpmaple.mw

Thanks alot Markiyan for the procedure.  Is it possible to implement another if statement which i tried but it didn't worked.  Actually I implemented m*Pi = k*bo,    and m*Pi is not equal to k*bo

I am attaching the Maple file for your kind consideration.

Once again thanks for your time.

Best Regards

A.Q

## Thanks...

helpmaple.mw

Thanks alot Markiyan for the procedure.  Is it possible to implement another if statement which i tried but it didn't worked.  Actually I implemented m*Pi = k*bo,    and m*Pi is not equal to k*bo

I am attaching the Maple file for your kind consideration.

Once again thanks for your time.

Best Regards

A.Q

## k and p are integers...

Hi Markiyan,

Thanks for your reply.  K and P are integers.  P is number of machine poles, which are fixed i.e. can be 2, 4, 6,  where as value of K varies such that K / P = 1, 3 ,5 ,7 ,9, 11.   This means that if p = 2 then the value of K can be 2, 6, 10,14, 18 etc.

Also only for K/P = 1,3,5,7,9, 11    eti is not equal to zero ,  where as for all other values of K/P = 2,4,6, 8....eti is zero.

Best Regards

A.Q

## Thanks problem solved...

Hi Adri vanderMeer van der Meer

Your suggestion worked fine. Thanks alot for your time. Your effort is really appreciated.

Best Regards

A.Q.

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