You can enter the expression with unevaluation quotes:

'((D-2)^2)(f)(x)'

Note that function definition should be done as f:= x-> ..., not as f(x):=.

You can enter the expression with unevaluation quotes:

'((D-2)^2)(f)(x)'

Note that function definition should be done as f:= x-> ..., not as f(x):=.

What does the syntax

m=-4.65...*10^8,n= 8.65..*10^8

mean? I cannot input it to Maple.

What does the syntax

m=-4.65...*10^8,n= 8.65..*10^8

mean? I cannot input it to Maple.

@digerdiga

p:= ()-> p;

@digerdiga

p:= ()-> p;

I don't know what's wrong, but I'm sure that there's nothing wrong with your syntax. I can copy your procedure to a Maple execution group and it works. My advice is to use Worksheet mode rather than Document mode (this is an option that you get when you create a new worksheet).

@pzwp Could you give more details of what you would like for expand? It could probably be done easily. Note that you should probably be using Expand (with capital E) instead of expand in conjunction with mod.

@pzwp Could you give more details of what you would like for expand? It could probably be done easily. Note that you should probably be using Expand (with capital E) instead of expand in conjunction with mod.

@Markiyan Hirnyk 

All powers can be removed from an expression ex by evalindets(ex, `^`, x-> op(1,x)).

@Markiyan Hirnyk 

All powers can be removed from an expression ex by evalindets(ex, `^`, x-> op(1,x)).

@yewslyewsl Do you have reason to believe that there is a solution? You have two equations

Fn(n,m) = 0, Fm(n,m) = 0.

I can't find a shred of evidence that there is any point (n,m) that makes either one equal to zero, let alone one that makes them both equal zero. The evidence suggests that Fm is strictly positive and Fn is strictly negative. Mind you, I haven't proved anything; I've just looked at it empirically.

It looks like you may have tried to upload a file, but the link in your post is not clickable.

F:= subs(b= 1-a, eval(f)):
limit((F(x)-F(1))/(x-1), x= 1, right);
                               -1
limit((F(x)-F(1))/(x-1), x= 1, left);
                              2 a

F:= subs(b= 1-a, eval(f)):
limit((F(x)-F(1))/(x-1), x= 1, right);
                               -1
limit((F(x)-F(1))/(x-1), x= 1, left);
                              2 a