## 30 Reputation

1 years, 303 days

## How to Quantify the Difference between R...

Maple

I am considering a Fourier series

$cos (\alpha x) = \frac{1}{2}a_0 + \sum_{k=1}^{\infty}a_k cos(kx)$ for x between -pi and pi.

I have also shown using a different Fourier series that cos (\alpha x) has an alternative representation:

\frac{cos(\alpha x)}{\sin \alpha \pi} = \frac{1}{\pi \alpha} (1 + \frac{(\alpha \ pi)^2}{6} - \frac{\alpha x^2}{2 \pi} + \frac{2*\alpha^3}{\pi}\sum_{k=1}^{\infty}\frac{(-1)^{k-1}}{k^2(k^2 - \alpha^2}*cos(kx)$. To show that the second representation is a better approximation, I need to find the number of terms for this series and the original Fourier series needed for there to be a difference of 10^{-3} from the exact value of cos(\alpha \pi), assuming that \alpha = 0.75. Could someone advise how I might do this? ## Piecewise Definition of a Green's Functi... Maple I have just begun to study Green's functions and made some initial progress on a problem, but now need Maple to make further progress. Apologies, I have written up the equations in LaTeX form rather than Maple, as my Maple has gotten very rusty.$\frac{d^4y}{dx^4}=f(x)

y(0)=y'(0)=0, y(1)=y'(1)=0$I showed that the Green function$G(x,u)$for this equation satisfies a condition$\lim_{\epsilon\to0}\bigg[\frac{\partial^3G}{\partial x^3}\bigg]_{x=u-\epsilon}^{u+\epsilon}=1$and showed that there is continuity of the Green's function and its first and second partial derivatives with respect to$x$at$x=u\$.  The next step is to show that this function has a piecewise definition such that

$G=\frac{1}{6}x^2(1-u)^2(3u - 2ux -x$ for x between the range 0 and u and such that

\[G(x,u)=\frac{1}{6}u^2(1-x^2)(3x - 2xu - u) for x between u and 1

I am not entirely sure how to do this with pen and paper, so I have reason to believe that it could be a done a lot more easily with Maple, if someone could give some pointers that would be much appreciated.

## Writing a Procedure for a Series Represe...

Maple

I am attempting to write a series representation of a general integral of a function from a to b as follows:

int(f(x), x = a..b)= h*sum((c_k)*f(a+kh))+O(h^p),k=1..N;

where h:=(b-a)/(N+1), p(N) is greater than or equal to N + 1 and c_k are coefficients.  I then need to write procedures with Maple to evalue c_k from 1,..,N and also to evaluate P(N) for any N.  If I take the case for N = 3 and N = 6 I have to use those procedures to prove that:

int(f(x), x = a..b)=(4h/3)*(2*f_1 - f_2 +2*f_3) + O(h^5) = (7*h/1440)*(611*(f_1 + f_6) - 453*(f_2 + f_5) + 562*(f_3 + f_4)) + O(h^7)

where f_k = f(a + kh).  I am really at a loss as to how to write this procedure, although I may have used something similar before:

seq( evalhf(P(p)), p = 1 .. 5 );

## How do I use Maple to calculate the Chri...

Maple

FLRW_Metric.mw

I have been tasked with calculating all the non-vanishing Christoffel symbols (first kind) of a metric and have done these long-hand using the Lagrangian method and shown my working. However, for peace of mind I would like to run the metric through Maple and double-check that it returns the same answers (going back through my calculations if I have missed anything). I have attached the code I have written at the bottom.

I have no trouble defining the metric and the manifold but I receive an error message when I try to compute the Christoffel symbols 'improper op or subscript selector'. Could someone point out where I have made a mistake. The metric is the FLRW metric if that helps.

with(DifferentialGeometry):with(Tensor);

g1:=evalDG(-(dt)^2 +a(t)^2*((dx)^2+(dy)^2+(dz)^2)/(1+(k/4)*(x^(2)+y^(2)+z^2))^2 );

C1:=Christoffel(g1, "FirstKind");

## Procedure to evaluate a sum...

Maple

I am studying the sum below and am trying to write a procedure with Maple which I can use to efficiently evaluate the sum for large values of n.

sum((1/k^0.1)*sin(1/k), k=1..n)

I have read the section on procedures in my textbook for Maple but it only has very simple examples with nothing relevant to this situation and I am struggling to apply it here: can anyone assist?

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