4 years, 48 days

## Thanks a lot....

Dear friend,

Thanks a lot for your help.

These codes also work very well.

Thanks again.

@Kitonum

Dear friend,

## Thanks a lot....

Dear friend,

Thanks a lot. These codes work very well.

## problem solved...

Dear friend,

Thanks a lot for your explanations.

The answer of @acer 26216 was exactly what I want.

## no problem....

Dear friend,
Thanks a lot for your efforts.

## Thanks a lot....

Dear friend,
Thanks a lot for your help and excellent solutions.

## Thanks a lot....

Dear friend,
Thanks a lot for your help and excellent solutions.

## @acer  Dear friend, Thanks a lot f...

Dear friend,
Thanks a lot for your help and excellent solutions.

## Thanks a lot....

Dear friend,

Thank you very much.

## Thanks a lot....

Dear friend,

I'll consider the problem again.

## Thanks a lot....

Dear friend,

Thanks a lot for your help.

Two conditions correspond to the first and third time intervals.

I want that maple to distinguish this and solve the ode at the first interval with the first bc and solve the ode at the third interval with the second bc and give me the true result, but ....

## sorry...

Yes, you and dear carol are right.

I realized my mistake a couple of hours ago.

sorry!

## @Carl Love  Dear friend, Thanks a...

Dear friend,

Thanks a lot for consideration.

But, x[0](tau) and y[0](tau) are independent from each other. For this reason, I have this expectation that maple understand this and use separation method and then splits the eq to 2 equations as:

eq[1]:=diff(x[0](tau), tau) + x[0](tau)=0;

eq[2]:=- diff(y[0](tau), tau) - y[0](tau)=0;

then the solutions with that boundary conditions are exactly exp(-tau) as I mentioned.

Is there any way to get this?

## Thanks a lot....

Dear friend,

Thank you very very much.

It is exactly what I wanted.

## one/two/three real non-zero root(s)...

Hi,

one (or 2 or 3) real non-zero (if possible) root(s) for each variable (a[1],a[2],...) is sufficent.

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