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4 years, 244 days

## @vv Thanks. I was thinking about so...

Thanks. I was thinking about something similiar when I said that I want to find the final solution by having solutions for each equation.

Intersection of S1 and S2 is a null set here. If we consider a S3 set, with all intersection elements and all combination of variables in S1 and S2, then what you said works. But it is not true for other examples. Like:

S1:= (a+A1, a+A2, B1, B2),  S2:=( A1, A2, a+B1, a+B2). The final answer must be:

(-A1+A2, a+A1+B1,a+A1+B2).

## @rlopez Thanks. I don't want a ...

Thanks. I don't want a union of sets. For example, if there are two PDEs:

Then the answer for the first one is , and for the second one is . But I need the following result, which is not a union of those two and we only get it if PDEs are solved at the same time:

.

....... and now this makes me think it is not possible to get the final answer by having answers for each individual PDE. I guess the only way is to solve them all simultaneously (which is not working for a large number of equations).

## Thanks...

Thank you so much.

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