## 92 Reputation

18 years, 125 days

## Thanks...

Thanks for those very helpful points.

## Thanks...

Thanks for those very helpful points.

## I'm not sure how to do this...

I'm not sure how to do this for what I am doing. A simple example of my code is: her:=proc(i) for j in [k[1],k[2],k[3]] do for z in [1,2,3] do if is(solve(A[i][3,z]=T[z]-1,j),integer) then print(j=solve(A[i][3,z]=T[z]-1,j)); break; end if; end do; end do; end; where A is some matrix and T is some vector. Now with this code sometimes it can give results, k[1]=2; k[2]=2; or k[3]=1; or k[1]=2; k[2]=4; k[3]=2; and so on depending on A and T. But I don't know how to make this output as a sequence. I'm sorry if this is quite simple, but I'm not really very good with MAPLE.

## print 2...

I'm sorry, I hadn't previously read all those other comments. thank you very much. I just needed that procedure for inside a larger thing. If I refer you to Tim Van Dusen's post "not quite what I meant", I was wondering how to get the values, as a list, instead of just printing them; so I could use this later. So [1,2] instead of 1 2

## print...

Thanks for your suggestions. What would I do if I wanted the output to be separated by commas. With the print I would get say, 1 2 but how would I get the output as 1,2

## permutation...

wow.. I think I made it actually happen.

## Is there any way I can...

Is there any way I can extend this to giving all permutations of, say a 2 by 4 matrix (in this case). So all the permutations of 1100 in the first and second row of a matrix? i.e. (1 1 0 0) (1 1 0 0) (1 1 0 0) (1 0 1 0) (1 1 0 0) (1 0 0 1) etc
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