## 20 Reputation

12 years, 134 days

## Infact, it is a singularity! thank you...

> ans1 := dsolve({eq2, x(0) = -1, y(0) = -1}, numeric, [x(t), y(t)]);
> ans1(1.3617);
[t = 1.3617, x(t) = HFloat(-3.902822445560783),  y(t) = HFloat(110431.41657939098)]
> ans1(-1.1646698);
[t = -1.1646698, x(t) = HFloat(-0.31202567404723713),  y(t) = HFloat(-5.991828159068897e7)]

so the point x=1.3617 and x=-1.1646689 is singularity!

## Infact, it is a singularity! thank you...

> ans1 := dsolve({eq2, x(0) = -1, y(0) = -1}, numeric, [x(t), y(t)]);
> ans1(1.3617);
[t = 1.3617, x(t) = HFloat(-3.902822445560783),  y(t) = HFloat(110431.41657939098)]
> ans1(-1.1646698);
[t = -1.1646698, x(t) = HFloat(-0.31202567404723713),  y(t) = HFloat(-5.991828159068897e7)]

so the point x=1.3617 and x=-1.1646689 is singularity!

## thank you very much...

thank you very much

## thank you very much...

thank you very much

## it wokers well,thanks u...

it wokers well,thanks u

## it wokers well,thanks u...

it wokers well,thanks u

## thank u ,it is a perfect answer!!...

thank u ,it is a perfect answer!!

## thank u ,it is a perfect answer!!...

thank u ,it is a perfect answer!!

## than u vert much,  my problem...

than u vert much,  my problem solved prefectly, i learnd much form your answer.

## than u vert much,  my problem...

than u vert much,  my problem solved prefectly, i learnd much form your answer.

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