cinderella

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1 years, 57 days

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These are questions asked by cinderella


 

H := (alpha*(2-beta)*S__0^2+2*D*(S^(2-beta)-S__0^(2-beta)))/(2*D*alpha*(2-beta))

T := (S^(-beta+1)-S__0^(-beta+1))/(alpha*(-beta+1))+S__0/D

NULL

NULL

NULL

Profit1 := ((s-C)*S-C__1*H-C__3)/T

((s-C)*S-(1/2)*C__1*(alpha*(2-beta)*S__0^2+2*D*(S^(2-beta)-S__0^(2-beta)))/(D*alpha*(2-beta))-C__3)/((S^(-beta+1)-S__0^(-beta+1))/(alpha*(-beta+1))+S__0/D)

(1)

NULL

Profit1 := subs(D = alpha*S__0^beta, Profit1)

((s-C)*S-(1/2)*C__1*(alpha*(2-beta)*S__0^2+2*alpha*S__0^beta*(S^(2-beta)-S__0^(2-beta)))/(alpha^2*S__0^beta*(2-beta))-C__3)/((S^(-beta+1)-S__0^(-beta+1))/(alpha*(-beta+1))+S__0/(alpha*S__0^beta))

(2)

NULL

Profit1 := eval(Profit1, [alpha = 5, S__0 = 28, C__1 = .5, C__3 = 10])

((s-C)*S-0.1000000000e-1*(7840-3920*beta+10*28^beta*(S^(2-beta)-28^(2-beta)))/(28^beta*(2-beta))-10)/((1/5)*(S^(-beta+1)-28^(-beta+1))/(-beta+1)+(28/5)/28^beta)

(3)

DEF_Profit1 := diff(Profit1, S)

(s-C-.1000000000*S^(2-beta)/S)/((1/5)*(S^(-beta+1)-28^(-beta+1))/(-beta+1)+(28/5)/28^beta)-(1/5)*((s-C)*S-0.1000000000e-1*(7840-3920*beta+10*28^beta*(S^(2-beta)-28^(2-beta)))/(28^beta*(2-beta))-10)*S^(-beta+1)/(((1/5)*(S^(-beta+1)-28^(-beta+1))/(-beta+1)+(28/5)/28^beta)^2*S)

(4)

NULL

NULLNULL

``

``

sol1 := solve(DEF_Profit1, S)

RootOf(-100*_Z^(-beta+1)*28^beta*beta^2+300*_Z^(-beta+1)*28^beta*beta-10*C*_Z^(2-beta)*28^beta*beta^2+10*_Z^(2-beta)*28^beta*beta^2*s+20*C*_Z^(2-beta)*28^beta*beta-20*_Z^(2-beta)*28^beta*beta*s+_Z^(3-2*beta)*196^beta*7^(-beta)-200*28^beta*_Z^(-beta+1)+28*_Z^(2-beta)*beta^2-392*_Z^(-beta+1)*beta^2-56*_Z^(2-beta)*beta+392*_Z^(-beta+1)*beta+280*C*_Z*beta^2-280*_Z*beta^2*s-560*C*_Z*beta+560*_Z*beta*s)

(5)

NULL

NULL

NULL

NULL

NULL

``


 

Download doubt_case.mw

how to find the maximum value of the column of the table?  for making the table i have used table command.

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