Hi dear users:

i will plot the equation below abs(y) in terms of x,(note:abs(y) and x is real values),can every body help me?

eq:

-32.46753247/(Pi*x^2)+1.053598444*10^8*Pi^2*y/x^2-5.342210338*10^14*Pi^2*y*(2.574000000*10^8*Pi^2-.7700000000*x^2)/((-3.904240733*10^6*x^2+1.305131902*10^15*Pi^2-159.8797200*Pi^2*x^2+2.672275320*10^10*Pi^4+2.391363333*10^(-7)*x^4)*x^2)+1.504285714*10^9*Pi^4*y^3/x^2 = y

Hi every body:

how can i solve this equations(without numerical method):

eq1 := (D[1, 1](eta11))(t, a*t, a^2*t)+1.326096634*10^8*Pi^2*eta11(t, a*t, a^2*t)-3.315241586*10^7*Pi*eta21(t, a*t, a^2*t) = 0

eq2 := 2.054901810*10^13*eta21(t, a*t, a^2*t)+(D[1, 1](eta21))(t, a*t, a^2*t)-8.219607239*10^13*Pi*eta11(t, a*t, a^2*t)+4.137421500*10^8*Pi^2*eta21(t, a*t, a^2*t) = 0

eq3 := (D[1, 1](eta31))(t, a*t, a^2*t)+4.137421500*10^8*Pi^2*eta31(t, a*t, a^2*t) = 0

Hi:

how i find the roots of the below equation?

eq := tan((1/2)*x)-tanh((1/2)*x) = 0

Hi:
i have two functions(f(x)&g(x)),i calculated values this functions with numerical method(dsolve,numeric),
now i will plot the f(x)-g(x) for 0<x<1,how do this work?

Hi:

i will seprate coefficients of a,a^2,a^3 and this coefficients equivalent zero(0) in EQ below,how can i do this?

EQ:= 3.522088319*10^(-10)*a^2*q21(T)+3.522088319*10^(-10)*a^3*q22(T)-6.094634327*10^(-16)*a*q41(T)-6.094634327*10^(-16)*a^2*q42(T)+6.094634327*10^(-16)*a*q51(T)+6.094634327*10^(-16)*a^2*q52(T)-1.106493792*10^(-9)*a*q11(T)-1.106493792*10^(-9)*a^2*q12(T)+2.429209785*10^(-24)*a^2*(diff(q21(T), T, T))+2.429209785*10^(-24)*a^3*(diff(q22(T), T, T)) = 0