mehran rajabi

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These are questions asked by mehran rajabi

Hi everyone:

I have a matrix with 2(n+1) row and (n+1)^2 column, for example, the matrix A at the below with n=1:

A:=Matrix(4, 8, [[-1, 1-t, 0, 0, 0, 0, 0, 0], [0, 0, 1, 1+t, 0, 0, 0, 0], [0, 0, 0, 0, -1, 1-t, 0, 0], [0, 0, 0, 0, 0, 0, 1, 1+t]]);

I want to obtain the B matrix that created by the matrix A with a general code in Maple:

B:=Matrix(4, 8, [[-1, 1-t1, 0, 0, 0, 0, 0, 0], [0, 0, 1, 1+t1, 0, 0, 0, 0], [0, 0, 0, 0, -1, 1-t2, 0, 0], [0, 0, 0, 0, 0, 0, 1, 1+t2]]);

I can the create the A matrix with any value of n and my goal is create the B matrix? 

tnx...

Hi everyone:

I have two matrices T(t) and Y[i] :N is natural.how can I do it? tnx.

 

 

 

hi everyone:

How can I define this matrix in Maple? N is a Natural number. Thank you. 

Hi everyone:

How can I solve numerically the system of nonlinear algebraic equations by Newton’s method?

eq1:= (1/2)*x[0]*sqrt(3)-(1/2)*x[1]*sqrt(3) = ((1/2)*x[0]*(t+(1/3)*sqrt(3))*sqrt(3)-(1/2)*x[1]*(t-(1/3)*sqrt(3))*sqrt(3))*(1-(1/6)*y[0]*(t+(1/3)*sqrt(3))*sqrt(3)+(1/6)*y[1]*(t-(1/3)*sqrt(3))*sqrt(3)-(1/8)*y[0]*(5*sqrt(3)*(1/12)-1/4+t)*sqrt(3)+(1/8)*y[1]*(-(1/4)*sqrt(3)-1/4+t)*sqrt(3)-(1/8)*y[0]*((1/4)*sqrt(3)-1/4+t)*sqrt(3)+(1/8)*y[1]*(-5*sqrt(3)*(1/12)-1/4+t)*sqrt(3))-5*t^3*(1/2)+49*t^2*(1/12)+17*t*(1/12)-23/6;
eq2:= (1/2)*y[0]*sqrt(3)-(1/2)*y[1]*sqrt(3) = ((1/2)*y[0]*(t+(1/3)*sqrt(3))*sqrt(3)-(1/2)*y[1]*(t-(1/3)*sqrt(3))*sqrt(3))*(-2+(1/2)*x[0]*(t+(1/3)*sqrt(3))*sqrt(3)-(1/2)*x[1]*(t-(1/3)*sqrt(3))*sqrt(3)+(1/4)*(-(1/12)*sqrt(3)-3/4)*((1/2)*x[0]*(5*sqrt(3)*(1/12)-1/4+t)*sqrt(3)-(1/2)*x[1]*(-(1/4)*sqrt(3)-1/4+t)*sqrt(3))+(1/4)*((1/12)*sqrt(3)-3/4)*((1/2)*x[0]*((1/4)*sqrt(3)-1/4+t)*sqrt(3)-(1/2)*x[1]*(-5*sqrt(3)*(1/12)-1/4+t)*sqrt(3)))+15*t^3*(1/8)-(1/4)*t^2+3*t*(1/8)-1;
eq3:=(1/2)*x[0]+(1/2)*x[1] = 1;
eq4:=(1/2)*y[0]+(1/2)*y[1] = 0;

 

Hi everyone:

How can I re-write the EQ with transformation       s=1+2*((tau-t)/T0)    ?

EQ:=int(f1(t-tau)*(Sum(y[k]*F[k](tau), k = 0 .. M)), tau = t-T0 .. t)

tnx...

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