## 290 Reputation

9 years, 190 days

## Cool !!...

I was not aware of user lighting, it is wonderful

## Typo...

I am sorry for typo, read this as

e1 -> -2e3, e2 -> e2, e3 -> e1

also check on link I have given you.

## Explicit isomorphism...

The example of Lie algebras that I have given you are really isomorphic through transformations:

e1 -> - e3, e1-> e2 and e3 -> e2

see query on stack exchange regarding isomorphism among Lie algebra where isomorphism is preserving Lie bracket.

http://math.stackexchange.com/questions/1815341/how-many-three-and-four-dimensional-lie-algebras-are-there

## Example...

For If I consider following case

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 (1)
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 (2)
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 (3)
 alg1 >
 (4)
 alg2 >
 (5)
 alg2 >
 (6)
 alg2 >

## Atleats one should be non-singular ?...

I can see that all three matrices are singular, suppose if there were alteast one non-singular matrix then can we assume the existence of homomorphism ?

## Exactly !!...

@Thomas Richard This is exactly what I was wanting. Thanks

## Wonderful....!!!!...

@Carl Love This iis really amazing solution to my problem. I can manage without equation number, instead I would try to assign a name to equation. Are you aready using this feature anyway ?

You should try uploading Maple code while asking question, there is big green upward arrow, click and insert content. No need of Latex.

Regards

## I was also thinking so !...

I took this code from Maple help and it worked as desired. This also work for first example too, but now constant become functions of xi and eta, see below:

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 (3)
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 (4)
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 (5)
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 (6)

This looks fine,  but constants are now become functions of and

## No need of Value...

I have tried dchange in following manner:

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 (1)
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 (2)
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 (3)
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 (4)
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 (5)
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The equation (1) is accidently left after deletion, please ignore it.

Regards

## ohh....!!!!...

But, that what I was expecting from operator to operate even on expression.

## This worked as desired but not completel...

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 (1)
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 (2)
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 (3)
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 (4)

I was expecting this to be like