32 Reputation

16 years, 92 days

What do you mean?...

Your post was what was needed. The difference I wanted was to be able to group by n. Thanks.

What do you mean?...

Your post was what was needed. The difference I wanted was to be able to group by n. Thanks.

seq( fsolve(x^n - Thanks...

Thanks for the explanation; it was what I needed. The only minor problem with it was it would be nice to have a way to tell the difference in the solutions by n; when I ran your expression, I saw the solutions, two for each even n and one for each odd.

seq( fsolve(x^n - Thanks...

Thanks for the explanation; it was what I needed. The only minor problem with it was it would be nice to have a way to tell the difference in the solutions by n; when I ran your expression, I saw the solutions, two for each even n and one for each odd.

Thanks for assign...

Thanks for assign usage.

I think I may have found one...

I think I may have found one way to get what I was trying to do: > theList[1]; b = 9. > theOtherList := op(theList[1]); b, 9. > xx := sqrt(theOtherList[2]); 3.000000000

theList[0] gets me b=9 and...

theList[0] gets me b=9 and the List[1] is c=10. What I had wanted to do was get the 9 or the 10 to take the square root of. Thanks for showing how to isolate solution result expressions.
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