## 20 Reputation

15 years, 224 days

## Interesting...

Seems to be strange at all: I get in a special case no result at all .. just stops without any output and you get different results .. maybe Maple is just to weak for my math equations. I just wanted to derive the simple pauli matrices's. http://en.wikipedia.org/wiki/Pauli_matrices Maybe i should look out for some other Algebra-systems Are there any Tipps? (Hot Question in an Maple forum!!) us rene

## Interesting...

Seems to be strange at all: I get in a special case no result at all .. just stops without any output and you get different results .. maybe Maple is just to weak for my math equations. I just wanted to derive the simple pauli matrices's. http://en.wikipedia.org/wiki/Pauli_matrices Maybe i should look out for some other Algebra-systems Are there any Tipps? (Hot Question in an Maple forum!!) us rene

## Solver-bug or am I silly ???...

Thanks again But now I am coming up with an strange thing. solve({conjugate(f)-g, seq(i, i = (VectorCalculus[DotProduct])(A, A)-E), seq(j, j = (VectorCalculus[DotProduct])(B, B)-E), seq(i, i = (VectorCalculus[DotProduct])(A, B)+(VectorCalculus[DotProduct])(B, A))}) don't bring an answer solve({conjugate(g)-f, seq(i, i = (VectorCalculus[DotProduct])(A, A)-E), seq(j, j = (VectorCalculus[DotProduct])(B, B)-E), seq(i, i = (VectorCalculus[DotProduct])(A, B)+(VectorCalculus[DotProduct])(B, A))}) brings a nice one 1st case: "conjugate(f)-g" 2nd case: "conjugate(g)-f" is the only difference In my mathematical understanding this should be the same, so it should bring up the same answer Or is there an option that must be set to force the solve to bring up the answer, or so...???

## Solver-bug or am I silly ???...

Thanks again But now I am coming up with an strange thing. solve({conjugate(f)-g, seq(i, i = (VectorCalculus[DotProduct])(A, A)-E), seq(j, j = (VectorCalculus[DotProduct])(B, B)-E), seq(i, i = (VectorCalculus[DotProduct])(A, B)+(VectorCalculus[DotProduct])(B, A))}) don't bring an answer solve({conjugate(g)-f, seq(i, i = (VectorCalculus[DotProduct])(A, A)-E), seq(j, j = (VectorCalculus[DotProduct])(B, B)-E), seq(i, i = (VectorCalculus[DotProduct])(A, B)+(VectorCalculus[DotProduct])(B, A))}) brings a nice one 1st case: "conjugate(f)-g" 2nd case: "conjugate(g)-f" is the only difference In my mathematical understanding this should be the same, so it should bring up the same answer Or is there an option that must be set to force the solve to bring up the answer, or so...???

## right tought, but have a more equations...

Thanks "solve({seq(i,i=A.A-E)});" seems to be the right way but my real case is more complicated. Maybe you could also help me in this case A := Matrix(2, 2, {(1, 1) = a, (1, 2) = b, (2, 1) = c, (2, 2) = d}) B := Matrix(2, 2, {(1, 1) = e, (1, 2) = f, (2, 1) = g, (2, 2) = h}) E := Matrix(2, 2, {(1, 1) = 1, (1, 2) = 0, (2, 2) = 1, (2, 1) = 0}) N := Matrix(2, 2, {(1, 1) = 0, (1, 2) = 0, (2, 1) = 0, (2, 2) = 0}) solve({A.A=E, B.B=E, A.B+B.A=N}) don't work. I tryed to solve seqences of solutions, and seqences of seqences, but didn't come to a working point. us rene

## right tought, but have a more equations...

Thanks "solve({seq(i,i=A.A-E)});" seems to be the right way but my real case is more complicated. Maybe you could also help me in this case A := Matrix(2, 2, {(1, 1) = a, (1, 2) = b, (2, 1) = c, (2, 2) = d}) B := Matrix(2, 2, {(1, 1) = e, (1, 2) = f, (2, 1) = g, (2, 2) = h}) E := Matrix(2, 2, {(1, 1) = 1, (1, 2) = 0, (2, 2) = 1, (2, 1) = 0}) N := Matrix(2, 2, {(1, 1) = 0, (1, 2) = 0, (2, 1) = 0, (2, 2) = 0}) solve({A.A=E, B.B=E, A.B+B.A=N}) don't work. I tryed to solve seqences of solutions, and seqences of seqences, but didn't come to a working point. us rene
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