sharmamanjeet391

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These are replies submitted by sharmamanjeet391

Sir, I am unable to download the GeM package. Can you send me this GeM package. I shall be highly thankful to you

@Carl Love if we remove the dependency of t from the dependent variable p(x,t),we obtain the different solution as given in the worksheet .problemfilepdsolve.mw

eq1 := diff(p(x, t), x)-p(x, t)*(1/(p(x, t)^2*q(x, t)^(1/3)))

diff(p(x, t), x)-1/(p(x, t)*q(x, t)^(1/3))

(1)

eq2 := diff(q(x, t), x)-(-3*q(x, t))*(1/(p(x, t)^2*q(x, t)^(1/3)))

diff(q(x, t), x)+3*q(x, t)^(2/3)/p(x, t)^2

(2)

pdsolve({eq1, eq2})

Error, (in pdsolve/sys) found the element '_F2' repeated in the indication of blocks variables

 

eq3 := diff(p(x), x)-p(x)*(1/(p(x)^2*q(x)^(1/3)))

diff(p(x), x)-1/(p(x)*q(x)^(1/3))

(3)

eq4 := diff(q(x), x)-(-3*q(x))*(1/(p(x)^2*q(x)^(1/3)))

diff(q(x), x)+3*q(x)^(2/3)/p(x)^2

(4)

dsolve({eq3, eq4})

[{q(x) = -27/(_C1*x+_C2)^3}, {p(x) = (-3*(diff(q(x), x))*q(x)^(2/3))^(1/2)/(diff(q(x), x)), p(x) = -(-3*(diff(q(x), x))*q(x)^(2/3))^(1/2)/(diff(q(x), x))}]

(5)

eq5 := diff(p(x, t), x)-x = 0

diff(p(x, t), x)-x = 0

(6)

pdsolve(eq5)

p(x, t) = (1/2)*x^2+_F1(t)

(7)

eq6 := diff(p(x), x)-x = 0

diff(p(x), x)-x = 0

(8)

dsolve(eq6)

p(x) = (1/2)*x^2+_C1

(9)

NULL

``

(10)

Download problemfilepdsolve.mw

@Carl Love Sir this is not working. Help me in fixing my error.

@Carl Love this is not working in my case. Please help me to find the solution

eq1 := diff(p(x, t), x)-p(x, t)*(1/(p(x, t)^2*q(x, t)^(1/3)))

diff(p(x, t), x)-1/(p(x, t)*q(x, t)^(1/3))

(1)

eq2 := diff(q(x, t), x)-(-3*q(x, t))*(1/(p(x, t)^2*q(x, t)^(1/3)))

diff(q(x, t), x)+3*q(x, t)^(2/3)/p(x, t)^2

(2)

pdsolve(`~`[numer]([eq1, eq2]))

Error, (in pdsolve/sys) found the element '_F2' repeated in the indication of blocks variables

 

NULL

Download problemfilepdsolve.mw

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