## 1002 Reputation

1 years, 221 days

## @Samir Khan Many thanks! I hope thi...

@Samir Khan Many thanks! I hope this is useful in some cases.

## documented...

@vv It's in convert/to_special_function, yet I don't think it's very useful in practice.

## ‘prettyprint’...

@acer Thank you for your reminder. I forgot that I had changed the default “output display” option before.
I believe that Maple has an internal function to appropriately abbreviate repeated common subexpressions in large output, yet I cannot find it. (As you said, the codegen:-optimize often over-optimizes common subexpressions, which is not the default behavior of "subexpression labeling".)

## design details...

@acer Sometimes the documentation seems to tend to describe those subtle things too briefly. Anyway, thanks for your valuable comments!

## the original problem...

@acer Sorry for the late reply. I try to find a simpler example, yet ended up with nothing.

Well, here is the nested integral:

expr := (x + Pi/2) - (Pi/(2*sqrt(3))*sin(x) + Pi/2*cos(x) + 2*x*sin(x/2)):
simplify(combine(1/4*sin(x)*int(1/cos(x1/2)**2*int(cos(x2/2)**2/sin(x2/2)**3*int(sin(x3/2)/(1 + sin(x3/2))*int((1 + sin(x4/2))*(2*sin(x4/2) - 1) + x4/2*(cos(x4/2) + sin(x4)), x4 = 0 .. x3), x3 = 0 .. x2), x2 = x1 .. Pi), x1 = Pi/3 .. x)) - expr) assuming RealRange(Open(Pi/3), Open(Pi));
simplify(combine(1/4*sin(x)*int(1/cos(x/2)**2*int(cos(x/2)**2/sin(x/2)**3*int(sin(x/2)/(1 + sin(x/2))*int((1 + sin(x/2))*(2*sin(x/2) - 1) + x/2*(cos(x/2) + sin(x)), x = 0 .. x), x = 0 .. x), x = x .. Pi), x = Pi/3 .. x)) - expr, assume = RealRange(Open(Pi/3), Open(Pi)));

Ideally, both results should be , but in fact, there will be several WARNING messages.
At last, I have to use

assume(Pi/3 < x, x < Pi):
simplify(combine(1/4*sin(x)*int(1/cos(x/2)**2*int(cos(x/2)**2/sin(x/2)**3*int(sin(x/2)/(1 + sin(x/2))*int((1 + sin(x/2))*(2*sin(x/2) - 1) + x/2*(cos(x/2) + sin(x)), x = 0 .. x), x = 0 .. x), x = x .. Pi), x = Pi/3 .. x)) - expr);

or

undefine('x'): # free from assume
assuming([simplify(combine(1/4*sin(x)*int(unapply(1/cos(x/2)**2*int(unapply(cos(x/2)**2/sin(x/2)**3*int(unapply(sin(x/2)/(1 + sin(x/2))*int(unapply((1 + sin(x/2))*(2*sin(x/2) - 1) + x/2*(cos(x/2) + sin(x)), x), 0 .. x), x), 0 .. x), x), x .. Pi), x), Pi/3 .. x)) - expr)], [Pi/3 < x, x < Pi]);

Besides, the help page states that

the assuming command does not place assumptions on dummy integration variables in definite integrals …,

while I notice that assuming does not appear to strictly distinguish between the bound variables (i.e., the variables of integration) and free variables (e.g., the limits of integration) in definite integrals whenever there exists a possibility of confusion like duplication of names:

int(…*int(…*int(…*…, x = 0 .. x), x = 0 .. x), x = 0 .. x) assuming x::…:

In my opinion, setting global assumptions (using assume) may be convenient but also dangerous; perhaps the limitation that no assumptions are placed on the variables when using assuming can be disabled in future releases.

## another instance...

@acer Thanks for your detailed reply. But there exists an addition problem. If int is not invoked when executing coulditbe (or is), why is the returned value below still true

trace(int):
coulditbe(x = 1) assuming 0 < x, x < 1;
=
false

int(RETURN(coulditbe(x = 1)), x = 0 .. x) assuming 0 < x, x < 1;
=
true



Although this is just confusing … in my opinion, as the int procedure has not been called yet, no renaming of the formal parameter (i.e., the red x in the first argument) is done at this time; nevertheless, the result is still true. Did I miss something again?

(Note. My original problems originate from the calculation of nested integrals, but I think that the simplified version above is enough to illustrate the problem.)

@Carl Love Thanks. The use of RETURN is only to print out the corresponding operation results without exceptions (or unnecessary output), since there will be an error if I use print instead. (Besides, so far as I know, although the ERROR function has been deprecated, using the error statement must require more keystrokes here.)

## Pure regular expression Substitutions ...

@nm Regular expressions can still be used, yet the problem is that so far as I know currently Maple does not support the so-called “tokens”; however, you may execute the following code in Mma

In[1]:= sp[s_String] :=
StringReplace[RegularExpression["(?s)^(.*?)\\\\textrm({(?>(?2)|[^}{])*})(.*+)$" ] \[RuleDelayed] StringTemplate["\\begin{minipage}{\\linewidth}\\textrm\\end{minipage}", InsertionFunction \[Rule] #0]["$1", "$2", "$3"]][#]&[s]

In[2]:= sp["0{0\\textrm{11}\\textrm{2\\textrm{33}2\\textrm{44}2}0}endl"]

Out[2]= 0{0\begin{minipage}{\linewidth}\textrm{11}\end{minipage}\begin{minipage}{\linewidth}\textrm{2\b\

>    egin{minipage}{\linewidth}\textrm{33}\end{minipage}2\begin{minipage}{\linewidth}\textrm{44}\end{mi\

>    nipage}2}\end{minipage}0}endl


## No progress?...

Has this bug been fixed? It appears that it can still be reproduced in Maple 2024.

## @dharr Thanks. After reading A bug ...

@dharr Thanks. After reading A bug of Minpoly?, it seems better to manually convert algebraic objects into RootOf representation beforehand. Anyhow, I believe that there must exist a bug in PolynomialTools:-MinimalPolynomial (because no warning message is issued during execution).

## not over Q[beta]...

@Christian Wolinski Thanks. But I think this doesn't meet the requirement, since all of coefficients are expected to be rational. (Note that the constant term of your F (as a polynomial in lambda) is an irrational algebraic number.)

## Waiting for good news...

@C_R Thanks. I believe that the default simplifier is set up to avoid some of sophisticated but time‐consuming transformations that may make remarkable simplifications. (So I hope there will be a smarter approach to automatically simplify the second one in Maple.)

## keyboard shortcuts...

@vv Thanks. I think there're (at least) 2 points:

1. In practice, simply typing <…, …; …, …> is apparently more convenient than typing Matrix([[..., ...], [..., ...]])), and
2. it appears that in this way one can access a new container (a Matrix) without constructing another temporary data structure (a list (of list)).

## attributes...

@vv Thanks. The trouble is that neither special evaluation nor Construction Shortcuts mentions that <,> (as well as <|>) has special evaluation rules. Anyway, is there a direct way to force the arguments to be completely evaluated immediately (rather than being evaluated under the control of the procedure)?

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