## 470 Reputation

7 years, 251 days
Maple is to me difficult. The first version I bought was Maple9, and it was more than 15 years ago. But, I couldn't use it, feeling it too difficult. But, three years ago, I thought Maple might be helpful to my study, and since then, I have continued to learn Maple. As I got able to read the Maple help, I think that I could get to use maple better now than before. But, I feel that I am a beginner yet.

## Thank you...

Thank you for teaching me the usage of ||.

Take care.

taro

## Thank you for your question...

When I looked for the meaning of `` in helppage of Maple, that page of ?emptysymbol appeared.

But, I couldn't know what kind of relation that emptysymbol has to the usage of "``", which is used in this question.

## Thank you and I have another question...

Thank you Cari Love,

Owing to you, I could understand well about the usage of ``

Then, I could writite the following expression as well.

``(``(-2)*``(-1))/``(``(-5)*``(-1));

On the other hand, I couldn't find the pages of ``, with google and in the help page of my Maple.

If you know some page of it, would you mind telling me about it?

At last, I will repeat thank you to you.

Best wishes.

taro

## Thank you....

I could know why gamma cannot be singled out as a solution.

## thank you...

Thank you for telling me how to repeat expand for a few times.

I will get to be able to use the way you showed me.

Best wishes

taro

## Thank you....

Thank you for telling me about your dividend. I will try to understand its procedure.

Best wishes

taro

## Thank you very much...

Thank you very much. I could do what I wanted to do owing to you!

## Thank you...

Thank you. I could understand what the point was owing to your comment.

What I wanted to do is as follows.

Integral is like summation, just the integrand is continuous function of t as q(t).
In this case, I wanted to calculate

u:=integrate(q(i),i=0..M);

diff(u,q(k)), where q(k) is a value of q(i) for the specific i=k.

That is like

diff(x+y+z,y)

Thank you for your reply. I m sorry to say that you might misunderstand the problem I wrote.

`With the calculation you wrote, that is,v:=Int(q^2,i=0..M)^2;diff(v,q);what I obtained was`

2*Int(q^2, i = 0 .. M)*Int(2*q, i = 0 .. M)

This is not right, because the answer has to be

2*Int(q^2, i = 0 .. M)*2*q

q is considered to be a vector with infinite dimension. And, for its particular element q(i), I wanted to differentiate the integral.

Take care.

Taro

## Hello...

Hello,

I wanted to differentiated u with respect to q(i) with the particular i.
The reason I used q(i) not q[i] is that it is necessary for integration.
And, on the other hand, q(i) becomes variable, for a particular i.
I wanted to differentiate u with that q(i).

Originally, I wanted to calculate this.

v:=Int(q(i)^2,i=0..M)^2;
dv:=diff(v,q(i));

which shows an error message.

So, I modified this as

> v:=(Int(q(i)^2,i=0..M)+q[k]^2)^2;
>diff(v,q[k]);

Then,

4*(Int(q(i)^2, i = 0 .. M)+q[k]^2)*q[k]   (*)

appears. I don't like the expression of (Int(q(i)^2, i = 0 .. M)+q[k]^2) in the (*), and haven't been able to modify this to 4*(Int(q(i)^2, i = 0 .. M). And, with algsubs, q[k] which is in a expression outside of the original expression v, is modified, which is not good for me.

But, I think that my problem might have been settled down owing to you.

Thank you very much.

taro

## The correct answer did not appear....

Thank you for your reply. I did as you kindly taught me.

But, the answer I could obtain through your codes was M not 1.

1 is the correct answer, which I couldn't obtain.

Take care.

taro

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