witribm

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3 years, 315 days

MaplePrimes Activity


These are replies submitted by witribm

delta[1,1]= 1 and delta[1,1]^2= 0 just notation.

delta[1,1]^2 does not means delta[1,1] power of 2 but delta[1,1] in second term.

delta[1,1]= 1 means delta[1,1] in first term.

 

thanks

@tomleslie 

Thank you. The problems solved.

@tomleslie 

I hope can get this system of equations:

n:=2

(i,j,s)

(1,1,1)=alpha*gamma[1,1]^t*d[1,1]-beta*d[1,1]*gamma[1,1]^1-gamma*d[1,1]*gamma[1,1]^1+alpha*gamma[1,1]^2*d[1,2]-beta*d[2,1]*gamma[2,1]^1-gamma*d[2,1]*gamma[1,2]^1

(1,1,2)=alpha*gamma[1,1]^1*d[2,1]-beta*d[1,1]*gamma[1,1]^2-gamma*d[1,1]*gamma[1,1]^2+alpha*gamma[1,1]^2*d[2,2]-beta*d[2,1]*gamma[2,1]^2-gamma*d[2,1]*gamma[1,2]^2

(1,2,1)=alpha*gamma[1,2]^1*d[1,1]-beta*d[1,1]*gamma[1,2]^1-gamma*d[1,2]*gamma[1,1]^1+alpha*gamma[1,2]^2*d[1,2]-beta*d[2,1]*gamma[2,2]^1-gamma*d[2,2]*gamma[1,2]^1

and others...((1,2,2),(2,1,1),(2,1,2),(2,2,1),(2,2,2))

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