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AOA... I want to plot the following function which is continuous in [0,3]

f:=x^2+1  for x belong to [0,1]

f:=x^2-1  for x belong to [1,2]

f:=x+1  for x belong to [2,3]

Kindly help...

AOA... I wan to plot the following piecewise function

 

f := x^2+1         if x belongs to (0,1)

f := x-x^2          if x belongs to (1,2)

f := x+1-x^2       if x belongs to (2,3)

AOA... There are three question

1. I want to convert exp(Iota*theta) into ternometric function i.e., 

exp(Iota*theta) = cos(theta)+Iota*sin(theta)

Is there any comand pl help...

2. Also i want to rationalize the complex number...

3. I want to seprate real and imaginary parts of a comaplex numbers

 

 

I want to introduce a matrix of order M by M as for any m, M, pl help as show in file

 

Help.mw

 

 

AOA... I want to solve the following system in maple pl help

 

sys_ode := diff(y(eta), eta, eta, eta)+3*y(eta)*(diff(y(eta), eta, eta))-2*(diff(y(eta), eta))^2+x(eta) = 0, diff(x(eta), eta, eta)+3*Pr*y(eta)*(diff(x(eta), eta)) = 0

ics := y(0) = 0, (D(y))(0) = 0, (D(y))(infinity) = 0, x(0) = 1, x(infinity) = 0

Help.mw

AOA... Pl correct it

Help.mw

AOA...I want to introduce an operator to find the derivative of fractional order i.e.,

 

J^((alpha)) x^(k):=(GAMMA(k+1))/(GAMMA(k-alpha+1))x^(k-alpha):

 

when i applied J^(1/2) on x^2+x^3 it gives

 

GAMMA(3)*x^(3/2)/GAMMA(7/2)+GAMMA(4)*x^(5/2)/GAMMA(9/2)

 

Help.mw

AOA... I want to convert system of equations into matirx form.

F[0] := u[0, n]-u[0, n-1]+u[1, n]-u[1, n-1]+u[2, n]-u[2, n-1]+u[3, n]-u[3, n-1]

F[1] := u[0, n]-u[0, n-1]-u[1, n]+u[1, n-1]+u[2, n]-u[2, n-1]-u[3, n]+u[3, n-1];

F[2] := u[0, n]/P-u[0, n-1]/P-.7071067810*u[1, n]/P+.7071067810*u[1, n-1]/P+.7071067810*u[3, n]/P-.7071067810*u[3, n-1]/P+0.4549512860e-1*exp(-1.*t)-.3431457508*u[2, n]+.3431457508*u[2, n-1]+1.556349186*u[3, n]-1.556349186*u[3, n-1] = 0;

F[3] := u[0, n]/P-u[0, n-1]/P-.7071067810*u[1, n]/P+.7071067810*u[1, n-1]/P+.7071067810*u[3, n]/P-.7071067810*u[3, n-1]/P+0.4549512860e-1*exp(-1.*t)-.3431457508*u[2, n]+.3431457508*u[2, n-1]+1.556349186*u[3, n]-1.556349186*u[3, n-1] = 0;

I want to export the above system of equation in to matrices of as

AU[n]+BU[n-1]-C = O;

where*U[n] = Typesetting[delayDotProduct](Vector(4, {(1) = u[0, n], (2) = u[1, n], (3) = u[2, n], (4) = u[3, n]}), a, true)*n*d*U[n-1] and Typesetting[delayDotProduct](Vector(4, {(1) = u[0, n], (2) = u[1, n], (3) = u[2, n], (4) = u[3, n]}), a, true)*n*d*U[n-1] = (Vector(4, {(1) = u[0, n-1], (2) = u[1, n-1], (3) = u[2, n-1], (4) = u[3, n-1]})), Help me plz;

Help_Constrct.mw

I want to find the solution in a special form.
How can I do it?
Here is what I tried:

(Maple)

(Maple)


In the left hand side u_1 is not changed in  D(u_1).
I want to substitute and evalute (differentiate) it.

Thanks,  Sandor

 

 

 

 

AOA... I want to export system of linear equation into matrix form...

Help.mw

I can not interpret this answer.

I think here I is the complex unit.

compute the squarefree decomposition of the following polynomials in Q[x] and inF_3[x].
(1)  f=x^6-x^5-4x^4+2x^3+5x^2-x-2
(2)  g=x^6-5x^5+12x^4-6x^3-9x^2+12x-4
            

Hi,

I want to compute a formula which is too complicated and it contains some variables. So I divide it into several parts. But it always turns out kernel connection has been lost. I looked maplesoft online help system and change the ConnectionType from 0 to 2. But it does not work. So how does this happen and how to solve?

I attach my maple file which appears error.
Thanks a lot!

Regards,

Yan

> assume(a < 0);
> convert(cosh(sqrt(a)), sincos);
print(`output redirected...`); # input placeholder
/ (1/2)\
cos\(-a) /

This is what I expected.

Now

> assume(L > 0);
> assume(K > 0);
> assume(mu > 0);
> assume(mu^2 < 4*L*k);
> assume(t > 0);
> convert(cosh((1/2)*t*sqrt(mu^2-4*L*k)/L), sincos);
print(`output redirected...`); # input placeholder
/ (1/2)\
| / 2 \ |
|t \mu - 4 L k/ |
cosh|--------------------|
\ 2 L /

I wanted to obtain again the cos function. Could someone help me?
(What is the reason that convert does not work "well" in later case?)

 Thanks,  Sandor

 

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