Maple 15 Questions and Posts

These are Posts and Questions associated with the product, Maple 15

Is there a help page which explains why braces provide the partial text evaluation in this code?

RopeLen := 30;RopeAddLen := .5;

plots[textplot]([1, 1, typeset("%1", (({(1/2)*RopeLen}+{(1/2)*RopeAddLen})^2-{(1/2)*RopeLen}^2)^(1/2))])

eq1 := z = y*log(x): eq2 := z = y+x*log(x):

DispIntersecting := implicitplot3d([eq1, eq2], x = 0 .. 10, y = -30 .. 30, z = -40 .. 40, color = [blue, green]):

solve({eq1, eq2}, [x, y, z]);

assign(%):

DispIntersection := spacecurve([x, y, z], x = 0.1e-2 .. 10, color = red, view = [0 .. 10, -30 .. 30, -40 .. 40]):

display(DispIntersecting, DispIntersection, axes = boxed, scaling = constrained);

Hello guys and gals!

I'm not strong enough with maple to get what the result I want.

It seems that it's because I'm asking for two lenths, and not a lenth and an angle, but I have no Idea how to tackle it diferently.

If you know a trick, please share it!

 

Here's an image:

http://imgur.com/xavAUoB

And here's the maple file attached (I think)

 complex_problem_from_the_internet.mw

Thanks,

Happy new year!

has anybody experienced issues with Maple connectiong to Solidworks?  There doen't seem to be much info ion trouble shooting a failed "OpenConnection" call.

 

thanks,

Bill

Hi

If I have this equation

and I need to use different Z, it's like

how can I solve it

Many Thanks

Amal

Hello I am trying to plot this differential equation,  have not had any success can any one help me.


plot(q(t)= Ce^-1/2 + sin2t +cos4t)

not sure what i am doing wrong and i just used the plot command

Thanks

we have a curve (x^2+y^2)^2=x^2-y^2

parametric representation of the curve is given by

x(t)=cos(t)/1+sin^2(t)

y(t)=sin(t)cos(t)/1+sin^2(t)

 

and we are asked to plot the curve using a parametric plot for -Pi<t<Pi

i got UI interface error when i install maple 15 into intel compute stick in window 8.1

I run the following working maplet:

 

 

Where "muutujad" is a procedure I defined and which returns the three inputs in the form [TF1,TF2,TF3].

It works fine, but if I insert "theta" as input, it of course stays in the string form, not Θ. Even if I copy the symbol and paste it in the textfied, it doesn't accept the symbol. Is there any way I can convert the text input to actual symbol?

The downloaded worksheet below displays 3 points on the unit sphere which define a solid angle with a triangular face. The sides of the solid angle's are red arcs on the surface of the sphere and red radii which outline the planar sides within the sphere.

Three questions:

1. Is there a way to make the surfaces of the solid triangle more apparent by filling them with color?

2. Is there a way to calculate the area of the face on the surface of the sphere?

3. Is there a way to calculate the volume of the solid triangle?

 

Download Mechanics;_irregular_solid_angle.mw

The following commands show that I have an existing archive containing one procedure.

Why do I receive the error message when I try to save a second procedure to the same archive. The procedure I am trying to save has been executed within the same worksheet where I issue the savelib command.

> LibraryTools[ShowContents]("C:\\Program Files\\Maple 15\\Earl.mla");

LibraryTools[WriteMode]("C:\\Program Files\\Maple 15\\Earl.mla");

savelibname := "C:\\Program Files\\Maple 15\\Earl.mla";

savelib('CreateCircleVector');


[["RotateDisplay.m", [2015, 10, 1, 16, 3, 22], 41984, 655]]
[["C:\Program Files\Maple 15\Earl.mla", "WRITABLE"]]
"C:\Program Files\Maple 15\Earl.mla"


Error, cannot lock repository, C:\Program Files\Maple 15\Earl.mla

Shading is not valid as an option in the command defining a plottools object e.g. a parallelepiped, and yet shading can be selected in the actual display of the object. Is there a way to code for shading when creating the object?

Hi !

I am trying to solve a pde with initial/boundary conditions, in the numeric mode. It works very well when I provide 3 numerical conditions : 1 initial condition (uniform distribution at first), and two boundary conditions.

Now I want to switch the initial condition to a function of r. It's a polynome I obtained after interpolation of another result. I tested it and the function interp20(r) works. But the pdsolve doesn't seem to evaluate the function, when it comes to start the procedure and pdsolve doesn't return a module as it should, although it doesn't send any message error.

You can see the code following, with the error messages I get.

 

Is it strictly impossible to use a function as an initial condition ?
Is it just a problem I could solve by converting the function or its result to something else ?
Is float the right type of input ? For example, if I write a:=283.15, is it a float ?
Have you already had similar problems ? How did you solve them ? Where could I find working code examples on this ?
Could I solve this problem with non-uniform initial condition with another Maple function ?

Then you very much for your help !

 

 

I have a problem about the integration of a function. The maple returns mathematical form of the given command

the function is

fn :=(-4.079067798*10^(-16)+3.422708023*10^(-16)*I)*(3.363377947*10^(-11)+5.977507284*10^(-12038)*I+(3.363377947*10^(-11)+4.678081798*10^(-22)*I)*erf(1.664331698*10^15*qq-0.2503507367e-1-4.649313602*I)) *exp(-2.77*(qq/(tau*tau))^2)*exp(-I*w0*qq)*exp(-(ss-qq)/T_pop)

qq is the integration variable qq=-inf..ss

w0=10^15

tau=10^(-15)

T_pop=30e-15

i have to compute lie algebra condition by using maple 15, but currently i have code in maple 5.,

i already try to run in maple 15 but it say 'error,unable to match delimeters'
i try to find error, but i cant find it..
the coding are here...

check[lie]:=proc(A,n)

local  i,j,k,l,m;  

for i from 1 by 1 to n do

for j from 1 by 1 to n do  

for k  from 1 by 1 to n do    

if A[i,i,k]<>0 then  

RETURN ('Input is NOT a Lie algebra (',i,i,k,')=',A[i,i,k], 'is not zero');  

elif A[i,j,k]+A[j,i,k]<>0 then  

RETURN ('Input is NOT a Lie algebra,(',i,j,k,')+(',j,i,k,')=',A[i,j,k]+A[j,i,k],'is not zero');  

else  

for 1 from 1 by 1 to n do

if  

simplify(sum(A[i,j,m]*A[m,l,k]+A[j,l,m]*A[m,i,k]+A[l,i,m]*A[m,j,k],   m=1..n))<>0  

then  

RETURN('Input is NOT a Lie algebra---the Jac(',i,j,l,') is not zero');    

fi;  

od;  

fi;  

od;  

od;  

od;  

print('Yes,input IS a Lie algebra');  

end:

can anyone help me here? Thank You..

Here, i attached the result in printscreen

4 5 6 7 8 9 10 Last Page 6 of 43