Maple Questions and Posts

These are Posts and Questions associated with the product, Maple

Why the interface typesettings option doesn't affect the content of a MathContainer?

I opened a new document. Then I inserted the command interface(typesetting=extended); to improve the visualization of a disequation's solution. It works in the worksheet, but it doesn't work in the content of a MathContainer.

Hello! I have written a algorithm. Can you help me find errors? thank you very much. sorry, my English is not very good!

LL:=proc(A::Matrix)
uses LA= LinearAlgebra;
local i, j, k, n:= LA:-RowDimension(A),
L:= Matrix(LA:-Dimensions(A));
L[1,1]:=sqrt(A[1,1]);
for j from 2 to n do
L[j,1]:=(A[j,1])/(L[1,1]);
end do;
for i from 2 to n-1 do
L[i,i]:=(A[i,i]-add(L[i,k]^(2),k=1..i-1))^(1/(2));
for j from i+1 to n do
L[j,i]:=(1/L[i,i])*(A[j,i]-add(L[j,k]*L[i,k],k=1..i-1));
end do;
end do;
L[n,n]:=(A[n,n]-add((L[n,k])^(2),k=1..n-1)^(1/(2));
L;

I want to know the mistakes i have made in the documents attached to get the expected results every time.

NULL

Case 1: control = works fine now.

M1 := K__1*A*(Matrix(2, 2, {(1, 1) = 1, (1, 2) = -1, (2, 1) = -1, (2, 2) = 1}))/l__1 = Matrix(2, 2, {(1, 1) = 0.30e-2, (1, 2) = -0.30e-2, (2, 1) = -0.30e-2, (2, 2) = 0.30e-2})

NULL

NULL

Case 2: control = prints answer in next line.M1 := K__1*A*(Matrix(2, 2, {(1, 1) = 1, (1, 2) = -1, (2, 1) = -1, (2, 2) = 1}))/l__1 = Matrix([[K__1*A/l__1, -K__1*A/l__1], [-K__1*A/l__1, K__1*A/l__1]]) = Matrix(2, 2, {(1, 1) = 0.300000000000000e-2, (1, 2) = -0.300000000000000e-2, (2, 1) = -0.300000000000000e-2, (2, 2) = 0.300000000000000e-2})

NULL

control = prints expression and answer in the next line.

case 3

M1 := K__1*A*(Matrix(2, 2, {(1, 1) = 1, (1, 2) = -1, (2, 1) = -1, (2, 2) = 1}))/l__1 = Matrix([[K__1*A/l__1, -K__1*A/l__1], [-K__1*A/l__1, K__1*A/l__1]]) = Matrix(2, 2, {(1, 1) = 0.300000000000000e-2, (1, 2) = -0.300000000000000e-2, (2, 1) = -0.300000000000000e-2, (2, 2) = 0.300000000000000e-2})

NULL

Numeric formating does not function in case2 and cae 3. I dont know shat hv i done for these things to occur. But what should i do?

NULL

 

Download onlineResultandNumeric_format_doesnot_work_in_some_casesWhy.mwonlineResultandNumeric_format_doesnot_work_in_some_casesWhy.mw

Ramakrishnan V

rukmini_ramki@hotmail.com

Hello,

 I am trying to solve an differential equation in Maple, but I have no response from Maple.Can someone give a look for me? The coefficients a and b cannot be zero.

 Thanks a lot.

 

Download edo_solução_A_U.mw

 

NULLIn TEXT MODE the greek letters phi and varphi behave peculiarly in text entries inside text box in drawing. If it is the first letter it prints alright. Otherwise they rverse themselves (phi to varphi and viceversa). Is this solvable?

 

NULL

 

Download A_DOUBT_on_phi_varphi.mw


 


 

 

Ramakrishnan V

rukmini_ramki@hotmail.com

 

``

 

I would appreciate if anyone lets me know how to write circular references  (say 1 inside a circle to refer element 1. At present i do a drawing insert text and using.

 

Also i do not know how to remove the boundary of the overall drawing.

NULL

 

Download A_DOUBT_to_be_sent_to_prime_community.mw

Ramakrishnan V

rukmini_ramki@hotmail.com

hello

I have recently install Maple17 on my computer (Windows10) and I need to use some Greece alphabet such as ß but I look everywhere in maple's icon and I just could find capital Greece alphabet.

does anybody know how can I find those?

Hello,

I'm having an issue with this and I can't seem to fix it. Any help is greatly appreciated! Thank you in advance!!! For some reason mapleprimes won't let me upload the worksheet so I have pasted it below this message.

 

Kind regards.

Gambia Man

with(LinearAlgebra); UseHardwareFloats; with(plots); interface(rtablesize = infinity); with(Statistics);
L := 4; U := 1;
V := proc (x, y) options operator, arrow; piecewise((1/4)*L <= x and x <= (1/2)*L and (1/4)*L <= y and y <= (1/2)*L, U) end proc;
plot3d(V(x, y), x = 0 .. L, y = 0 .. L);

Vij := proc (ni, mi, nj, mj) local Xi, Xj; option remember; global U, L; Xi := 2*sin(ni*evalf(Pi)*x/L)*sin(mi*evalf(Pi)*y/L)/L; Xj := 2*sin(nj*evalf(Pi)*x/L)*sin(mj*evalf(Pi)*y/L)/L; return U*(int(int(Xi*Xj, x = (1/4)*L .. (1/2)*L), y = (1/4)*L .. (1/2)*L)) end proc;
HamilMat := proc (K::integer) local ni, mi, nj, mj, N, Hamil, Eigenvec, i, j, res; option remember; global Vij, U, L; N := K^2; ni := Vector(N); mi := Vector(N); nj := Vector[row](N); mj := Vector[row](N); for i to N do for j to K do res := (i+K-j)/K; if type(res, integer) = true then ni[i] := j; nj[i] := j; mi[i] := res; mj[i] := res end if end do end do; Hamil := Matrix(N, shape = symmetric); for i to N do for j from i to N do if i <> j then Hamil(i, j) := Vij(ni[i], mi[i], nj[j], mj[j]) elif i = j then Hamil(i, j) := Vij(ni[i], mi[i], nj[j], mj[j])+(1/2)*(ni[i]^2+mi[i]^2)*Pi^2/L^2 end if end do end do; Eigenvec := Eigenvectors(Hamil, output = ['values', 'vectors']), Hamil end proc;
SigFigEi := proc (Location::integer, SigFig::integer, VecSize::integer) local values, Eig, i; global HamilMat, OptK; Eig := Vector(VecSize); for i from 2 to VecSize do Eig[i] := HamilMat(i)[1][Location]; if evalf(Eig(i), SigFig+1) = evalf(Eig(i-1), SigFig+1) then OptK := i; break end if end do; values := evalf(Eig[i], SigFig); return values, OptK end proc;
BasisFunc := proc (location) local ni, mi, func, i, j, p, N, res, BasisSol; global HamilMat, L, OptK; p := evalf(Pi); N := OptK^2; ni := Vector(N); mi := Vector(N); for i to N do for j to OptK do res := (i+OptK-j)/OptK; if type(res, integer) = true then ni[i] := j; mi[i] := res end if end do end do; func := Vector(N); for i to N do func[i] := HamilMat(OptK)[2][i][location]*sin(ni[i]*p*x/L)*sin(mi[i]*p*y/L) end do; BasisSol := unapply(add(func[i], i = 1 .. N), x, y); return plot3d(BasisSol(x, y), x = 0 .. L, y = 0 .. L), func end proc;
BasisFunc(1);
Error, (in Vector) dimension parameter is required for this form of initializer

Note added: Issue resolved, see my comment below.

I have a sum of several thousands addends each of which is the product of a c-number times a product of 6 Grassmann-odd degrees of freedom, the latter of which does each belong to a set of 24 Grassmannians. The specific numbers are not that important, though.

This sum should equal zero. So I would like to add all c-numbers multiplying the same product of six Grassmannians, taking proper care of anticommutativity, of course. The sum would then be zero if all these sums of c-numbers are zero. Unfortunately, using Physics:-Coefficients is far too slow; actually, it has never succeeded in even completing the calculation.

Therefore, I have tried to loop through all the addends, splitting each one of them using selectremove(), and then adding the c-numbers in an Array (properly indexed), or in a table (associatively indexed, of course). Consistently, by converting the Array and table to two sets, the two methods result in the same set of equations. But solving these equations yields a result that is not stable: it varies from session to session.

I am baffled. Can anyone give me a hint to a safe and reasonably quick method for extracting these c-number-valued equations?, for there has to be something wrong with what I do.

i need to plot tow functions but the legend not in top, bottom, left or right 

Given the sequence defined by the recursive relation a[n+1] = r*a[n](1-a[n])
You need to use the procedure iterate.
Throughout this problem you should choose initial values in the interval 0<a0<1.
(a) Let r=3/2. Calculate a moderate number of terms in the sequence (between 10 and 20). Does the sequence appear to be converging? If so to what value? Does the limit depend upon your choice of initial value? Plot the terms you have calculated
(b) Let r=2.8. Calculate a moderate number of terms in the sequence (between 10 and 20). Does the sequence appear to be converging? If so to what value? Does the limit
depend upon your choice of initial value? Plot the terms you have calculated How does this sequence differ from that in part (a).
(c) Let r=3.2. Calculate a moderate number of terms in the sequence (between 10 and 20). Show that the sequence does not appear to converging. Plot the terms you have calculated and describe how the sequence behaves in this case.
(d) Consider intermediate values between 2.8 and 3.2 to determine more precisely where the transition in behaviour takes place. Provide a few plots (no more than 4) showing the values you have investigated.
(e) Consider the values of r in the range 3.43<r<3.46. Determine as accurately as you can the value of r for which the period of oscillation doubles.
(f) As r increase further period doubling occurs. Try to find the when the sequence appears to oscillate between 8 values.
(g) Let r =3.65 and calculate a considerable number of terms (at least a few hundred) and plot your values.
(h) For r=3.65 choose a0=0.3 and then a0=0.301. Find and plot some terms in the sequence for each initial value. Determine how long the terms in the two sequences remain close together and when they begin to depart significantly from each other.

Hi. I have a commutation table, that I've got as output of Greg Reid algorithm.

Can I use to define Lie algebra for components DifferentialGeometry & Lie Algebras?

Worksheet is attached...

FCT.mw

 

I have used data and the curve fitting procedure to find a curve and I now have to put error bars on the graph to complete my task? I know that there is an errorplot function but I cant seem to find a way to do it with the curvefitting thing?

 

I have attached the whole worksheet, I hope someone can help! Thanks Detectors_Tutorial.mwDetectors_Tutorial.mw

 

Even if there was some method of exporting the graph to another medium that would also be very helpful

 

This is the code  hw2_final.mw

 

Let me explain it.

I am sure that the mistakes must be about the expresstion of the I1(t) and I2(t). Actually if you delete I1(t) and I2(t) , the whole code works and get the picture at the bottom. 

What I want is to put the expresstion of the I1(t) and I2(t) into 'sol:=dsolve...' and 'plots...' to get the picture of I1(t) and I2(t) with respect to t. Before the t* which subject to Phi(t*)=0 (The blue line in the picture at the bottom is Phi) I want I1(t) and after t* I want I2(t).

I1(t) = (int(sqrt(2*(H(t)+omega*cos(q(t)))), q(t) = q(t)-2*Pi .. q(t), numeric))/Pi.    what I want of this experesstion is to get  'int(sqrt(2*(H(t)+omega*cos(q(t)))' from  'q(t)-2*Pi' to 'q(t)' by numeric method.This q(t) is the solution of the ODE sys.

For example(the number I used is not true,just for example) , at the point t=20, q(t)=30-2*Pi.

so I1(t)= (int(sqrt(2*(H(t)+omega*cos(x))), x = 30-2*Pi .. 30, numeric))/Pi.The I2(t) I want is similar to I1(t).

 

How can I solve it?

Hello, 

 

I am pretty new to Maple and Im trying to find the parameters of an equation using some kind of fit routine but I can only find such a routine to fit an expression to data and not vice versa.

my equation is as follows

 

epsilon(E):= a0 + a1*ln(E) + a2*ln(E)^2 + a3*ln(E)^3

 

I do have data for E which I imagine I need. 

 

E:= {121, 244, 344, 411, 444, 778, 867, 964, 1085, 1112, 1212, 1299, 1408} all in keV :)

 

Any suggestions/help would be much appreciated, although I am new to the program so go easy on me :) 

 

 

Cheers

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