sorry, i`m learning of thermaldynamics and want to make a graph of that x-axis  is number of spin-up and y-aixs is number of configuraions when there are atoms could only have spin-up and down.

if the atoms are 10, what is the formular in maple 17

how about 100 ?

please let me know, thank you

I have 101 point with very low value

and I'm trying to get the best curve that fits that points. I have tryed with a polynomial interpolator but the curve is not very good. I have also tried with an exponential but an error ocurrs. 

Error, (in Statistics:-ExponentialFit) dependent values must evaluate to positive numbers

Can anyone help me? Any ideas? How can I find the best curve fitting?

Thanks.

Hello,

I try to simplify a system of 6 trigonometric equations and then to extract the 3 first equations.

When I conduct my calculations, It seems that that I have some troubles with some index.

There is a term with "table" which is not evaluated.

Do you have ideas why the last equations in my code have a table inside and consequently can not be evaluated?

I attached my code

example.mw

Thank you for your help.

Hi all

How can I make maple to write the values of each contour plot on the graph?

I have a 3d graph and want to have a contour plot in which each line have the associated value on it. I know I can use legends and input the values for each line by hand but I dont know those values. I just need maple to calculate the values and write them on the contour plot. 

Many thanks for helping me 

Hi Maple People,

My question is, "How can I combine the two plots shown in the attachment into one plot?".

Download plot_real_example_5_Exact_Curve_Fit_questiion_for_MaplePrimes.mw

Regards

Matt

Maple is a scientific software based on Computational Algebraic System (SAC) which has enabled this work entirely solve applied to Civil Engineering, Mechanical and Mecatrónica.The present problems in education, research and engineering are developed with static work sheets ie coding used innecesaria.Maple proposed models are shown below with an innovative structure; with the method of graphics algorithms and embedded components; putting aside the traditional and obsolete syntax; using dynamic worksheets as viable and optimal solutions to interpret and explain problems Ingineering.Design Advanced Analysis Tools (Applied Mathematics) Sophisticated Applications (efficient algorithms) and Multiple deployment options (different styles); this allowed generate math apps (applications engineering); can be interactive on the internet without the need to have the software installed on our computer; This way our projects can be used with a vision of sustainability around the world. Resulting in the generation of data and curves; which in turn will help you make better decisions analytical and predictive modeling in manufacturing and 3D objects; which would lead to new patterns of contrasting solutions.

ECI_2016.pdf

ECI_2016v_full.mw

Lenin Araujo Castillo

Ambassador of Maple - Perú

This is somehow an old problem which came back and I decided to post it. So, I have some code which runs in Grid framework locally. Each node saves data directly to hard disk and there is no need to return anything at the end to the node of ID 0. Nevertheless, I noticed that memory usage on one instance of the mserver is very huge.  Moreover, this instance is all the time in S state, namely sleeping. Below you can see dump from top. I deny this is caused by some particular procedures called in my code since in this case I should rather observe more uniform memory usage. I am not sure if for this moment I could share some code with you which demonstrate this behavior. I will try to write some toy example because my productive code cannot be posted here.

%MEM     TIME+ COMMAND

49.1 17:00.19 mserver
0.1 12:43.70 mserver
0.1 12:32.15 mserver
0.1 13:54.02 mserver
0.1 14:45.45 mserver
0.1 12:35.22 mserver
0.1 13:50.77 mserver
0.1 14:14.85 mserver
0.1 8:58.82 mserver
0.1 12:58.48 mserver
0.1 8:51.00 mserver
0.1 10:35.92 mserver
0.1 12:58.13 mserver
0.1 9:34.39 mserver
0.1 10:10.13 mserver
0.1 12:07.77 mserver
0.0 8:21.17 mserver
0.0 11:41.42 mserver
0.0 5:07.27 mserver
0.0 8:31.88 mserver
0.0 6:30.12 mserver

hi.please see attached file below and help me for gain real or complex answer 

with out show answer in root of manner

thanksroot_of....mw

What is the maximal independent set of monomial ideal$<c^4a^3b>$ in $K[a,b,c]$?

(Some) prime reciprocals have an interesting property. the repeating sequence has length p-1.

eg 7, has repeats after 6.

1/7=0.142857142857......

17 has repeats after 16

1/17=0.05882352941176470588235294117647059.........

of course some primes don''t have this property....

So what I need the experts here is for some code

myproc(17)=16, (and the sequence) 0588235294117647

my go:pinched from

http://199.71.183.11/questions/39621-Pattern-Matching-In-A-Sequence-Of-Digits

PriDigits := "" || (op(1, evalf(1/17, 50)));

reps := StringTools[Repeats](PriDigits);

lngth := seq(op(3, A), A in [reps]);

the leading 0 (which is part of the sequence)  is a problem.....

hi every one, i would like to know if it is possible to implement the following recursive sequence in Maple :

q(1)       = q(0)        +q_dot(0)
q_dot(1)  = q_dot(0)  +q_ddot(0)
q_ddot(1) = q_ddot(0)+q_dddot

q(2)       = q(1)        +q_dot(1)   = (q(0)+q_dot(0)) + (q_dot(0)+q_ddot(0)) = q(0)+2q_dot(0)+q_ddot(0)
q_dot(2)  = q_dot(1)  +q_ddot(1)
q_ddot(2) = q_ddot(1)+q_dddot

q(3)      = q(2)        +q_dot(2)=(q(0)+2q_dot(0)+q_ddot(0))+(q_dot(1)+q_ddot(1))= q(0)+3q_dot(0)+q_ddot(0)+q_dddot
q_dot(3) = q_dot(2)  +q_ddot(2)
q_ddot(3)= q_ddot(2)+q_dddot

I would like every q(n) to be expressed as following : q(n)=q(0)+n_1*q_dot(0)+n_2*q_ddot(0)+n_3*q_dddot.

By computing manually some sequences i am now sure that :
n_1=n
n_2=(n²-n)/2
n_3=?? (I would like to find this one)

The sequence can be written in a more general way as following :
q(n)        = q(n-1) + q_dot(n-1)
q_dot(n)   = q_dot(n-1) + q_ddot(n-1)
q_ddot(n) =q_ddot(n-1)+q_dddot

Can you guys please show me how this can be implementes in Maple ?

Thanks in advance

A wealth of knowledge is on display in MaplePrimes as our contributors share their expertise and step up to answer others’ queries. This post picks out one such response and further elucidates the answers to the posted question. I hope these explanations appeal to those of our readers who might not be familiar with the techniques embedded in the original responses.

The Question: How to sketch a line in space?

vahid65 wanted to know how to sketch the line with equation (x-2)/3 = (y-1)/4 = (z-3)/3 in a three-dimensional space.

This question was answered using two different approaches that we will discuss.

The first approach, given by Preben Alsholm, suggested using these commands: solve, subs, and plots:-spacecurve.

Preben provided the following lines of code:

1. {(x-2)/3 , (y-1)/4 , (z-3)/3} =~t;
2. solve(%,{x,y,z});
3. L:=subs(%,[x,y,z]);
4. plots:-spacecurve(L,t=-5..5,thickness=3,color=red);

The first line sets the three expressions equal to t using the element wise operator =~.  This distributes the operation of equality over the elements of the set of expressions, forming a set of equations.

Result-1: {(x-2)/3=t, (y-1)/4=t, (z-3)/3=t}

The second line invokes the solve command. The solve command, solve(equations, variables), solves one or more equations or inequalities for their unknowns. So in this line, this command was used to solve each expression for its corresponding unknown.

Result-2: {(x= 2+3t, y=1+4t, z= 3+3t}

You may have noticed that the % symbol is used within the command. This symbol is referring to the equation label that was created chronologically last. 

The third line uses the subs command. The subs command, subs(x=a,expr), substitutes “a” for “x” in the expression expr. In this case, “a” is the reference to the equation label referenced by (%) and expr is the sequence of variables x,y,z. The square brackets around expr forms a list, and the replacement imposed by the subs command replaces each of the three names x, y, and z with their equivalents in the set of equations returned by the solve command.

Result-3: [2+3t,1+4t, 3+3t ]

Finally the last line uses the plots:-spacecurve function.  This function, spacecurve(sc,r,opts),  graphs a parametrically defined curve in three-dimensional Cartesian space. 

In this example the first parameter, sc, is replaced by L since L has the properties of a list. The parameter  r is an equation containing the parameter name and the parameter range; here it is the equation t=-5..5. Last but not least, the opts parameter (which is optional) gives the user the opportunity to specify the optional properties of the graph, properties such as thickness and color of the space curve. 

Result 4: 

Another contributer, Carl Love, suggested that these commands could be combined using the zip function, zip( f, u, v), which is an unusual application of it. The zip command applies elementwise to corresponding members of the two lists u and v, the binary function f, creating a new list r, whose members are f(u_k,v_k).

Carl provided the following code:

plots:-spacecurve(  zip(solve, [(x-2)/3 , (y-1)/4 , (z-3)/3] =~ t, [x,y,z]),  t= -5..5, thickness= 3, color= red, axes= normal);

In this case zip is applying solve to u, a list of equations, and v, a list of variables. The equations in u are those in Result-1. The zip function returns the solution of each equation for the indicated variable, that is, the new list r is the list in Result-3. This list is the first argument of plots:-spacecurve. Finally, the parameter range and opts are up to the user’s preferences.

A second approach was suggested by Kitonum. The difference between this approach and the first one is that here we are not using the solve command. Instead, we are treating the line as an intersection of two planes.

Kitonum's code is as follows:

1. L := [(x-2)*(1/3), (y-1)*(1/4), (z-3)*(1/3)]:
2. plots[intersectplot](L[1]-L[2], L[2]-L[3], x = -4 .. 4, y = -4 .. 4, z = -4 .. 4, linestyle = 1, thickness = 3, axes = normal, orientation = [60, 75], view = [-1 .. 3, -4 .. 2, -1 .. 4]);

The first statement initializes a list L that contains all the desired expressions in the given symmetric form of the line.

In the second statement Kionum used the plots[intersectplot] command. This command graphs, in three-dimensional Cartesian space, the intersection of a pair of surfaces. This example uses the calling sequence: intersectplot(expr1, expr2, x=a..b, y=c..d, z= e..f, options). 

What are expr1 and expr2 used in Kitonum’s solution? The pairwise differences of L[1] and L[2], and L[2] and L[3] are planes, the intersection of which is the desired line in space.

expr1 = L[1] – L[2] = (x-2)*(1/3)- (y-1)*(1/4)

expr2= L[2] - L[3] = (y-1)*(1/4)-(z-3)*(1/3)

The variables x,y, and z are the coordinate names and define the axes, whereas a, b, c, d, e, f define the ranges. In this case they were taken as -4 or 4.

In the options parameter Kitonum used linestyle, thickness, axes, orientation, and  view. The help page “plot3d,option” details these and other options that apply.

This blog was written by our intern Pia under the supervision of Dr. Robert Lopez. We both hope that you find this useful. If there is a particular question on MaplePrimes that you would like further explained, please let us know. 

Hi,

say I have defined some (very simple, acting on a finite set M) functions f,g,h. I want to evaluate certain permutations, so I want to make a for loop that goes through possible combinations of functions in my array A=Array([f,g,h]). (In reality my array is a little larger.) No I don't understand how I can use the elements of this array as actual functions. Even if f is defined and I can evaluate, say, f(m), I cannot use A(1)(m) to evaluate m. The output is just "f(m)". How can I make maple recognize that we are having a function here?

Thanks it advance.

Hi,

I'm not sure that I mean datatable component corectly.

I also consider that I was done somthing wrong

Thank you for advanced for any help.

wzel

Download datatable_problem.mw

Is there a way in Maple to convert a list into a string of numbers?

So [1,2,3,4,5] -> 12345

I have tried Maple help, but there are too many convert commands to try them all.
And the ones I have tried didn't work.

Thanks.