I want to put the solution obtained from ShowSolution() command of Student[Calculus1] into my LaTeX file. How I can achieve that?

I succeeded in getting latex of ExpandSteps because it was a module, but ShowSolution() is not a module.

Hello everyone,

I have nonlinear partial differential equations (see the attached file) need to be solved:

https://drive.google.com/file/d/0B14...ew?usp=sharing

With initial condition: h(x, y) = K1 (constant), dh/dx = K2 (constant); dh/dy = K3 (constant); And h(x,y) is function of (x,y) other factors are constant. Could anyone tell me how to solve these equations by using numerical method? Do you know any library in c/ c++ language that can solve these equations??

I have tried with Maple 17 and the response is: "Error, (in pdsolve/info) first argument is not a differential equation". Whole of my input:

with(PDEtools); declare(U1(x, y), U2(x, y), U3(x, y));

PDEs = [diff(U1(x, y), y) = U2(x, y),

diff(U1(x, y), x) = U3(x, y),

(diff(U2(x, y), y))*((L-U1(x, y))^2+(D2+tan(alpha)*(L+U1(x, y)))^2)+.5*U2(x, y)*(2*tan(alpha)*U1(x, y)-D2) = 0,

(diff(U3(x, y), x))*((L-U1(x, y))^2+D1^2*cos(alpha+2*U2(x, y))^2)+.5*U3(x, y)*D1*cos(alpha+2*U2(x, y))+.5*D1*sin(alpha+2*U2(x, y))*(L-U1(x, y)) = 0];

[ d d / d
PDEs = [--- U1(x, y) = U2(x, y), --- U1(x, y) = U3(x, y), |--- U2(
[ dy dx \ dy

\ / 2 2\
x, y)| \(L - U1(x, y)) + (D2 + tan(alpha) (L + U1(x, y))) /
/

/ d
+ 0.5 U2(x, y) (2 tan(alpha) U1(x, y) - D2) = 0, |--- U3(x, y)
\ dx

\ / 2 2 2\
| \(L - U1(x, y)) + D1 cos(alpha + 2 U2(x, y)) /
/

+ 0.5 U3(x, y) D1 cos(alpha + 2 U2(x, y))

]
+ 0.5 D1 sin(alpha + 2 U2(x, y)) (L - U1(x, y)) = 0]
]

pdsolve(PDEs);
Error, (in pdsolve/info) first argument is not a differential equation

I will be very appreciated with your help!!!

I need to convert a base 10 int(defined as num) to its base 3 format using a while loop. I would like to store the remainder of the num%3 to a list/sequence/array in maple. Now, if I were to use a sequence, I would need a pre-defined range. How do I solve this issue?

I've got a piece-wise function(for which I've made the procedure) f defined over x<=-1, -1<x<1 and x>=1 which I am trying to plot over the range of (-2,2). I've tried using plot(f,-2..2) but it doesn't show any curve. Should I add a few more parameters to plot()?

I've got the following lists :

list1:=[1, 5, 14, 30, 55, 91, 140, 204, 285, 385, 506, 650, 819, 1015,

1240, 1496, 1785, 2109, 2470, 2870]
list2:=[1, 5, 14, 30, 55, 91, 140, 204, 285, 385, 506, 650, 819, 1015,

1240, 1496, 1785, 2109, 2470, 2870]

each generated by a procedure I defined. I need to verify that they are equal, which is the case. However, when I tried to use the evalb function as well as a flag that I was updating during a loop, in both cases, I got 'false' as  the answer along with the error message: 

"error, final value in a for loop must be numeric or a character"

What I am doing wrong?

I am required to generate a list containing the square of numbers 1 through k where k is an arbitrary int,defined from 1 to n. To do this, I've currently got the following commands:

local k, mylist:=[];

for k from 1 to n do

mylist[k]=sumsquare(k);

end do;

where sumsquare() is a procedure I defined to compute the sum of the squares of 1 through a number passed as an argument

At present this gives me an out of bounds error. 

How can I initialize mylist to be of size n, like in other languages such as C++?

Hi,

im trying to calculate the divergence of a 3x3 tensor. The tensor is created by the following code:

with(VectorCalculus);
with(LinearAlgebra);
SetCoordinates(cartesian[x, y, z]);
alias(u = u(t, x, y, z), v = v(t, x, y, z), w = w(t, x, y, z)); alias(eta = eta(t, x, y, z));
U := VectorField(`<,>`(u, v, w));
M := OuterProductMatrix(U, U);

The last command gives a 3x3 tensor:

Now I want to calculate the divergence of this tensor. But the function "Divergence" (VectorCalculus-package) is only able to handle vectors. A workaround would be the extract the data row by row -> convert it to a vector -> calculate the divergence.

Is there a more elegant possibility to do this?

Thanks in advance.

Hi,

for my simulation I have to calculate several gradients and jacobian matrices. The equations are quite complex and with my current setup hard to read.

Here is some exampel code:

restart;
with(VectorCalculus);
SetCoordinates(cartesian[x, y, z]);
alias(u = u(t, x, y, z), v = v(t, x, y, z), w = w(t, x, y, z)); alias(eta = eta(t, x, y, z));
U := VectorField(`<,>`(u, v, w));
Divergence(U);
Jacobian(U);
Diff(U, t);

The Divergence operator gives me a very compact result:

But Jaobian and Diff look like:

To achive a better readability I want to do two things (if possible):

1) hide the independet variables (t,x,y,z) in the result of Jacobian, Diff

2) display the result of Diff in a row vector (3x1) instead

Is this possible?

Thanks in advance for your help

I am looking to return all the substrings of a string that match a particular pattern (regexp). This is a very common text processing operation.

StringTools[RegMatch] returns boolean about whether the given pattern exists somewhere in the string. That's a start, but it is not efficient to hunt around for where the match is in order to extract the characters.

StringTools[Search] and [SearchAll] can return position information, but they work on exact matches of the pattern space, not on regular expressions. I could pre-generate all the possible matching sequences of up to some length and search for those exactly, but that is inconvenient at best and pretty much useless if there is a .* or .+ in the regular expression (as the space of potential matches grows exponentially.)

StringTools[RegSub] can be used to find one match by using something like ".*(REALPATTERN).*" = "\1" but since this does not extract any position information, one would at the very least then have to StringTools[Search] of the exact match to determine the position, then take a substring of the original string, and continue searching. And if you are going to do that, you might as well just use StringTools[RegMatch] with an optional third argument of a symbol to return the matched characters, instead of fooliing around with deleting everything else using RegSub.

Have I overlooked a possibility?

Example of use:

I would like to search "variable %1 needs to be of the form %3+2.9 in order to use routine %2 to find the fizturl", extracting the "%1", "%3", "%2". This would be regular expression "%[0-9]+". Notice that there might be other digits in the string that I do not want to extract, so I cannot just search for digits. I also cannot just remove all characters "[^0-9%]" as that would leave digits and would, for example, merge together the %3+2.9 into %329 leaving post-processing to extract the true pattern matches.

For what I am doing at the moment, I do not need to know the positions those occured at, just the matches.

I want to solve a Laplace integral transform step-by-step its as follows:

f(t):=e^at

IntTutor(Int(e^-st f(t),t=0..infinity)

but it says that the expression can't be integrated, and secondly it does not work with 'infinity'. How I can solve this for step-by-step solution?

Thanxs

We are happy to announce the first results of a partnership between Maplesoft and the University of Waterloo to provide effective, engaging online education for technical courses.

Combining rich course materials developed by the University with Maple T.A. and Maplesoft technology for developing, managing, and displaying dynamic content, the Secondary School Courseware project supports high school students and teachers from around the world in their Precalculus and Calculus courses. The site includes interactive investigations, videos, and self-assessment questions that provide immediate feedback.

Feel free to take a look. The site is free, and no login is required.  

For more information about the project, see Online Mathematical Courseware.

eithne

When I open My Maple 18 on my Macbook pro, with all updates on the operating system and on Java, my Maple starts up fine, but when I press 2+2 and the enter, nothing happens.

I have tried reinstalling Maple, without any change of the problem

Per Kirkegaard

hi

i want to use Direct Search Package for solve system of equation but i have an error:

Error, SolveEquations is not a command in the DirectSearch package.

please help me. code is attached.boltmohasebe.mw

Hi all.

I try to get the real part from the complex expression. But it turns out to not be the simplest result:

A:=I*sin(k*Pi*(x-h*cos(theta))/a)*sin(l*Pi*(y-h*sin(theta))/b)*exp(-I*k[0]*h)*sin(k*Pi*x/a)*sin(l*Pi*y/b)

convert(exp(-I*k[0]*h), sin);

simplify(Re(A));

Maple results in:

Re(sin(k*Pi*(-x+h*cos(theta))/a)*sin(l*Pi*(-y+h*sin(theta))/b)*exp(-I*k[0]*h)*sin(k*Pi*x/a)*sin(l*Pi*y/b))

while the simplified result should be:

sin(k*Pi*(x-h*cos(theta))/a)*sin(l*Pi*(y-h*sin(theta))/b)*sin(k*Pi*x/a)*sin(l*Pi*y/b)*sin(k[0]*h)

I wander how to get the simplifyed result in maple. Thanks

How can I breal kong code lines in "Code Edit Region" like "..." in Matlab?