I've been on this question a week now and still no conclusive answer! What I need is a function that produces the inequalities that determine a triangle given the 3 points and then using a 4th point, prints true if the 4th point satisfies 2 or 3 or the inequalities and prints false if it only satisfies 1 or none of the inequalities. I need to have this solved by tonight so any quick help would be greatly appreciated!

Consider the curve defined by f(x, y) = 3+2x+y+2x^2+2xy+3y^2 = 0.Locally on the curve we can view y as a function of x, i.e. y = y(x).Compute formulas for the first and second derivative of y with resoect to x.

2. Give the Maple command(s) to compute \frac{\partial^8 f}{\partial^5 x \partial^3 y} for f(x, y) = e^{2x+ cos(y)}.

How to show the code in file with extension .lib and edit it?

I am stuck with an IVP which is

eq1:=diff(y(x),x$2)+2/x*(diff(y(x),x))+y^M=0;

ic:=y(0)=a,D(y)(0)=0;

its quite easy to find the series solution of the ode 

dsolve({eq1, ic}, y(x), series);

y(x)=a-(1/6)*exp(M*ln(a))*x^2+(1/120)*(exp(M*ln(a)))^2*M*x^4/a;

But I am facing problem when I try to solve it numerically,

dsolve(subs(a=1,M=3,{eq1,ic}),numeric);

THanks

Hello

Am trying to convert a vector projection to matrix type output.

Attached is a sample worksheet.

Transformation_matri.mw 

Consider:

> restart:
> int(exp(I*x)/x,x=-infinity..infinity,CauchyPrincipalValue)
                                                                                                   Pi I

> int(exp(I*3*x)/x,x=-infinity..infinity,CauchyPrincipalValue)
                                                                                                   Pi I

> int(exp(I*k*x)/x,x=-infinity..infinity,CauchyPrincipalValue) assuming k::positive;
                                                                                                  2 I Pi

I would expect the last line to also give me Pi I

Mathematica gives a Pi I via:

FullSimplify[Integrate[Exp[I k x]/x, {x, -\[Infinity], \[Infinity]}, PrincipalValue->True, Assumptions->{k>0}],  Assumptions->{k>0}]

Any idea what this could be?

thanks.

Congratulations to Eric Miles, a graduate teaching assistant at Colorado State University, for winning the second individual prize of The Möbius App Challenge! Eric will be receiving an iPad prize pack for his app Stretch and Translate Sin(x).

Maplesoft launched the Möbius App Challenge earlier this year to give Maplesoft community members the opportunity to get involved in the creation of Möbius Apps. This contest seeks to challenge users to create Math Apps using Maple, submit them to The Möbius Project website, then award the most useful, creative, and effective submissions. Finalists from the individual level challenge are chosen four times a year, so make sure to enter the next round of the challenge for your chance at a Maplesoft prize pack!

For full contest details and to enter, please visit: http://www.maplesoft.com/lp/mobius/index.aspx.

Jonny Zivku
Maplesoft Product Manager, Maple T.A.

I need to make a graph that has dates 1/14/2000 on the x axis and intrest rates on the y axis but when i import my spread sheet from excell the dates keep getting converted into lager numbers like 37000 for some reason and i cannot figure out how to stop this odd conversion. Has anyone encountered this?? i tried looking up dates in maple hepl but cant find much on this topic. Hope i explained what is happening well enough. Graph_One_b.mwGraph_One_b.mw

I have to solve a complex equation whose solutions, I'm looking for, are real numbers, I chose a command 'solve ' to solve this problem but the program shows me this message 'warning solutions May Have Lost'. How I can resolve this problem?

this is the equation and the message :

solve({((abs((((1-(nc-I*kc))/(1+(nc-I*kc)))+(((nc-I*kc)-(0.518-I*0.023))/((nc-I*kc)+(0.518-I*0.023)))*exp(-I*4*3.14*h*(nc-I*kc)/lamda))/(1+((1-(nc-I*kc))/(1+(nc-I*kc)))*(((nc-I*kc)-(0.518-I*0.023))/((nc-I*kc)+(0.518-I*0.023)))*exp(-I*4*3.14*2500*(nc-I*kc)/581))))^2)*100=43.12,((abs((((1-(nc-I*kc))/(1+(nc-I*kc)))+(((nc-I*kc)-(0.176-I*0.023))/((nc-I*kc)+(0.176-I*0.023)))*exp(-I*4*3.14*h*(nc-I*kc)/lamda))/(1+((1-(nc-I*kc))/(1+(nc-I*kc)))*(((nc-I*kc)-(0.176-I*0.023))/((nc-I*kc)+(0.176-I*0.023)))*exp(-I*4*3.14*2500*(nc-I*kc)/720))))^2)*100=44.37},{kc,nc});
{kc,nc};

Warning, solutions may have been lost            {kc, nc}

So I need a help .

Hi,

I have a system of equations for which I want to get a solution around an initial guess, unfortunatly I cannot succed it. Here is the system and the initial guess

solve({(-(((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.005+0.009)*sin(-0.785)+(0.072+1*(Ladssec+Ll))*cos(-0.785)))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.072+1*(Laqssec+Ll))*sin(-0.785)-(0.005+0.009)*cos(-0.785)))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0))/(2*2.5))=-1.7858
,(-((((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/Lfd))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-(((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*Lfd))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0)+((Ladssec*iq0)/Lfd)) /(2*2.5))=0.1036
,(-((-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/L1d))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-(((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1d))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0)+((Ladssec*iq0)/L1d)) /(2*2.5))=0.2279
,(-((((0.072+1*(Ladssec+Ll))*Laqssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1q))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Laqssec/L1q))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0)-((Laqssec*id0)/L1q)) /(2*2.5))=-2.3313

,(-(1*Rfd*((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.072+1*(Laqssec+Ll))*sin(-0.785)-(0.005+0.009)*cos(-0.785)))*Ladssec)/(Lfd))=0.0023
,(-(1*Rfd*(1-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*Lfd)) *Ladssec)))/(Lfd))=-0.0054
,(-(1*Rfd*(-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1d)) *Ladssec)))/(Lfd))= 0.0018
,(-(1*Rfd*(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Laqssec/L1q))*Ladssec)/(Lfd))=5.8369e-04

,(-(1*R1d*((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.072+1*(Laqssec+Ll))*sin(-0.785)-(0.005+0.009)*cos(-0.785)))*Ladssec)/(L1d))=0.1303
,(-(1*R1d*(-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*Lfd))*Ladssec)))/(L1d))=0.1157
,(-(1*R1d*(1-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1d)) *Ladssec)))/(L1d))= -0.3192
,(-(1*R1d*(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Laqssec/L1q))*Ladssec)/(L1d))=0.0333

,(-(1*R1q*((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.005+0.009)*sin(-0.785)+(0.072+1*(Ladssec+Ll))*cos(-0.785))) *Laqssec)/(L1q))=-0.1323
,(-(1*R1q*(((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/Lfd))*Laqssec)/(L1q))=-0.0044
,(-(1*R1q*(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/L1d))*Laqssec)/(L1q))= 0.0051
,(-(1*R1q*(1-(Laqssec/L1q)+((((0.072+1*(Ladssec+Ll))*Laqssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1q))*Laqssec)))/(L1q))=-0.2349}, {L1d, L1q, Ladssec, Laqssec, Lfd, R1d, R1q, Rfd},useassumptions)

Lfd ~=0.233, R1d~=0.0848, L1d~=0.2, L1q~=-0.09, Ladssec~=0.099, Laqssec~=-0.1, Rfd~=0.00173, R1q~=0.0129

Dear Maple forum,

given A, B real numbers,

and after defining the recurrent sequence

x(0) = A

x(n) = 0.5* x(n-1)^3 + B

I would like to see a graphic of x(n) on the plane x(n) - n.

how could I implement in maple 16?

thank you for your help.

JeanJ

Dear sirs/madams,

I tried to use my MAPLE in a MacBook with a quiet large screen...however I see the letter sizes of my Maple16 very small (the same wiht the font size on input and ouput sheets..and everywhere)..

Is there some way to "see larger and bigger"?

Thanks for your attention,

JeanJV

So I have the energy of an ion at a several points in space, where the x and z coordinates have been varied from 0-1, keeping y constant. The data is in the following file: 

y=0.xlsx

When I come to produce a 3D surface plot (grid) of this file using the plots option in the context menu (on right clicking), the following is produced: the x-axis is in red and the y-axis (z-coordinate) is in blue.

Yet if I use the interactive plot builder, to plot the same data, the only option available to me is a 3D point plot, which produces the following:

[If I try to plot a 3D surface plot (points) using the context menu, I get stuck at a evaluating stage...]

as, ideally, I want a surface plot, why, in the surface plot (grid) is MAPLE not recognising the data that corresponds to the higher z-coordinate values and how I can produce a full surface plot... 

Hi, I just want to know if there is simulated annealing programming in maple 14 and where I can get that programming