Is there anyway to prevent Maple from converting a log10 function to a ln function when it displays a result?

Bonjour,

Qui peut m'éxpliquer l'algorithme de division d'un polynôme P(X,Y) sur un polynôme Q(x,y) ?

Avec mes plus vifs remmerciements,
Raymond Gérard.

after union ideal I and J, how to remove the intersection of I and J in order to do primedecomposition?

G1 := [v*y-w*x, r*y-u*x, -v*u+w*r, u*y^2-v*x^2, u^2*y-v*r*x, u*w*y-v^2*x, u^3-v*r^2, u^2*w-v^2*r, -v^3+u*w^2, x^4-r, x^3*y-u, x*y^3-v, y^4-w, w*y^2*x^2-v^2];

TypeTools[AddType](`w`,typefunc(string, symbol));
L:= `if`(G1::`w`, [op], '[]')(G1);

it seems above code incorrect.

Dear friends,

I wonder how I would go about calculating the asymptotic expansion of

sum(5^j/j, j=1..m+1)?

The motivation for this calculation can be found here. The correct answer is

5/4 5^(m+1)/(m+1).

The classic asympt and the one from multiseries both fail on this one.

Thanks,

Marko Riedel

i need your kind sggestions for this. i wrote the function w:=(xi(t),eta(t),diff(xi(t),t),diff(eta(t),t))→value.

but i cannot get the output, it wrote error in argument name. here value means the expression of the function.

best regards

Hi, I've got  a worksheet to do for my homework. I answered the first question, and then an error message appeared in the part of the code written by the teacher. At the following part,

Normalisation and expectation values of the superposition state
Lets consider the normalisation of, say, the mixed state Psi represented by the superposition of 1st and 2nd levels at an arbitrary time t.
int(evalc(conjugate(Psi(1,x,t))*Psi(1,x,t)),x=-infinity..infinity);

If Z is N(0,1) find

a) P(0<=Z<=.87)

I understand how to get to 0-0/1<=Z-0/1<=.87-0/1

which ends up being OI(.87), but am not sure how to get this to calculate. Plus I ant use proper functions here becuase I dont have the pallette, but OI is an O with the I through it... Φ(.87) I beleive....

I dont know how to have Maple calculate ths to give me the correct normal distribution value.

Hi all,

I have a differential equation as follows:

x(t)^2+cos(x(t))+diff(x(t), t)+diff(x(t), t, t) = 100

x(0)=2, D(x)(0) = 3;

After using "dsolve" to solve this equation, the solution x(t) is obtained.

How can we obtain the following function?

g(k) = ₀∫^kx²(t)dt

How can we plot the function g(k...

hi,

i have one equation (like equ1) wich this equatioin is a function of x. i want to find x in such a way that the equ1 minimizes. unfortunetly the equ1 is large and when i want to use NLPsolve it takes several time. is there any quick method to find the minimum x?

thanks for your attention in advance

Here is a plot in table format of the standard Times, Helvetica, and SYMBOL fonts. This plot provides a reference table that can be used to find the character codes to plot any one-byte character that can be plotted, which is especially useful for the SYMBOL characters and character codes 128-255 in the standard fonts. These characters are available for plotting in both the Standard and Classic GUIs.

All characters are aligned to be immediately above and immediately...

How do I find the vertical asymptote of tan(x) when x=x/x+1?

restart;
with(Groebner):
g1 := x^2-w*y;
g2 := x*y-w*z;
g3 := y^2-x*z;
S13 := -y^3*w+x^3*z;
eq1:= S13 = h131*g1 + h132*g2 + h133*g3;

hsol := solve(identity(eq1, x), [h131, h132, h133]);
match(eq1,{x,y,z,w},'s');
s;

h131 should be x*z

h312 should be 0

h133 should be -y*w

Hi, I need to maximize a quadratice function and I need to check if my variables are satisfying the Kuhn-Tucker conditions or not.

I defined the objective and I want to use the command

QPSolve(`&varphi;`, assume = nonnegative, maximize);

and the Kuhn-Tucker conditions that I want to apply are

(&PartialD;)/(&PartialD; x[i]) `&varphi;`=0 and x[i]>=0; or (&PartialD;)/(&PartialD; x[i]) `&varphi;`<=0 and x[i]=0

Dear All,

I found that the _Z is a already asked question from learners like me. However, I am asking for your inputs that are related to my problem.

I have a implicit expression interms of bessel functions. While making an attempt to solve (using solve command) for a variable , which is an argument inside the bessel function I came up with some output which has _Z as follows: