Hey folks, I'll give you the actual problem I'm trying to solve before I show you my code in case anyone can think of a better idea...

Long read but you can ignore the examples and additional info if you don't need it.

Take the doubling map,

f(x) = 2x if 0 <= x <= 1/2

f(x) = 2x - 1 if 1/2 < x <= 1.

Or in maple code, f := x -> piecewise(x<=1/2, 2*x, 2*x - 1):

This looks...

Hi!

I've got two Sums vith variable arbitrary boundaries:

a:=Sum(x(i),i=n..m);
b:=Sum(x(i),i=n-1..m+1);

I would like to substract theese sums and I want Maple to simplify the result to

x(n-1)+x(m+1)

Is that possible?

Hello,

When I multiplify some terms like

(x+k-n+5)*(x-3k+n^2+2)

I get a long expression. Nevertheses, I would like to rearrange first according to the power of k (in other cases, according to n). Is there some command to rearrange my polynomials?

Thanks for you attention,

Jean-Jacques

Dear Maple users

Often I use Maple for solving problems in Physics. Maple does indeed a nice job when calculating expressions containing units. However when I want to plot functions containing units it sometimes work and sometimes not. Look at the following example: 

Using the Open Maple application program interface (API), the ExternalCalling module, a C compiler, and some basic understanding of the Maple data structure format, you can create Maple utilities that run nearly as fast as Maple builtin procedures.

To show how this is done, I will start with a simple example and then proceed to a slightly more complex procedure that improves ?ListTools[SearchAll]

I'm using the commands:

RungeKutta(d/dt(y(t))=-y(t),y(0)=1,t=1,submethod=rk4,output=plot,numsteps=10);

Euler(d/dt(y(t))=-y(t),y(0)=1,t=1,output=plot,numsteps=10);

Each of these commands yields its own serperate graph.  How can I plot both on graph to see how the approximations vary?

Thanks!

Hi,

I am presented with a list of known roots to a polynomial. How can I reconstruct the original polynomial with a variable "x"  from the given roots?

The list of roots is: [-1/2,2/3,7/3,4+3I,4-3I]

Hi,

I have the following function:

y(t) = _C1*exp(-2*t)*sin(6*t)+_C2*exp(-2*t)*cos(6*t)

My start parameters are y(0)=1, and y'(0)=2

How do I isolate _C1 when y(0)=1?

Thanks in advance

My code works fine when not part of a procedure it is only until I turn it into a procedure when I have problems. After running the proc once I get:

"Error, (in opt) cannot determine if this expression is true or false: min(`.`(Transpose(Vector(1, {(1) = 7})), ..."

Strangely if I execute the proc() code a second time and try again I get an answer out. Any suggestions as to how I can solve this problem?

I have (which I believe is where the problem lies),

Hi 

Hi have made my first package in maple, and need some help. I've got a funktion, and need maple to put something into this function.. 

Dams := proc (a, b, c)

local A, f;

 f(x) := a;

printf("\nDin funktion er %a", f(x));

 A := diff(a, b);

printf("\nDen differentierede funktion er %a", A);

use x = c in f(x);

 printf("\n%a i ligningen ", f(x));  ...

In the name of God

Dear my friends

Hi

Can Maple work with differential operators without introducing a known function?

For example, assume that we have

diff(diff(f(x),x)+f(x),x);

How can we apply differential operators such as diff or D without applying any known function as:

diff(diff(...,x)+...,x);

if...

I have two issues.

if I say

int(exp(I*k*x),x=-Pi..Pi) assuming k::integer

Maple answers me with 

0

which is wrong, as one would expect the result to be a kronecker delta (k=0 is a type-integer for mapel). Is there a way to make Maple understand it is doing a mistake?

Related to this there is another point.

If I write

int(exp(I*(k-q)*x),x=-infinity..infinity)

Maple does not write (or convert) the result...

In the name of God

Dear my friends

Hi

 I have a function as the following:

 temp:=phi(Lambda(tau, 0), tau, 0)+((D[1](phi))(Lambda(tau, 0), tau, 0)*(D[2](Lambda))(tau, 0)+(D[3](phi))(Lambda(tau, 0), tau, 0))*q;

 I have equivalent functions for Lambda(tau,0) and phi(Lambda(tau,0),tau,0) as the following:

 c[0](tau) instead of Lambda(tau,0)

y[0](c[0](tau),tau) instead of phi(Lambda(tau,0),tau,0)