what is the wrong with Pi set ::: in this function ::: Warning, no iterations performed as initial point satisfies first-order conditions

Optimization[Minimize](x^2 + y^2 + 25*(sin(x)^2+sin(y)^2), x=-2*Pi .. 2*Pi , y= -2*Pi .. 2*Pi);

Warning, no iterations performed as initial point satisfies first-order conditions
[0., [x = HFloat(0.0), y = HFloat(0.0)]]

Optimization[Maximize](x^2 + y^2 + 25*(sin(x)^2+sin(y)^2), x=-2*Pi .. 2*Pi , y= -2*Pi .. 2*Pi);

Warning, no iterations performed as initial point satisfies first-order conditions
[-0., [x = HFloat(0.0), y = HFloat(0.0)]]

--------------------------------

I got my good result when I apply it with this function :

f:= (x,y)->cos(x)*sin(y) -(x/(y^2+1));


Optimization[Maximize](f(x,y), x = -1 .. 2, y = -1 .. 1);

[0.994945017202501170,[x = HFloat(-0.6362676080636113), y = HFloat(1.0)]]

Optimization[Minimize](f(x,y), x = -1 .. 2, y = -1 .. 1);

[-2.02180678335978703,[x = HFloat(2.0), y = HFloat(0.10578346945175972)]]

Hi, this question is for Samir Kahn or other maplesoft staff.

Is there a way to use modelica biochem or any other chemical path library into maplesim? Do you plan to integrate this library in future versions of maplesim? Wolfram systemModeler has this library already integrated as does symbiology in matlab. Mr Kahn, I hope that your background in chemical engineering help you push for this new development in maplesim and help this product be even better than the competion. thank you and let me know as soon as possible.

juan

Hello,

Is it possible to use Maple 15 Student Edition with the same license information and purchase code both on Windows and Ubuntu?

I did a few Windows reinstalls (guess about 3) hence I used the same purchase code to activate the license that many times. Today I tried installing and using Maple 15 on Ubuntu 12.04.3 LTS 32-bit and to my dismay the license manager said, "Not enough activations left on this account." Furthermore, I have exhausted my download links and would like to know how many times Maple 15 can be activated and if the download links can be refreshed?

Thanks

Hi, guys and happy eastern to all! :)

I have a realy big problem. I have to do beziercurves in 3d plots.

I can´t plot it in 3d, something wrong with the plot (complex). Can anybody pls help me?! It´s very important to me, thanks! :)

im solving 4 ODe with boundary conditions.. i got this error Error, (in dsolve/numeric/bvp/convertsys) too few boundary conditions: expected 8, got 7

Hi,

I open a discussion about convolution and Fourier coefficients in Fourier series.

I have a function defined by f(x)=0 if x in [-Pi,0[ and 1 if x in [0,Pi[, of course f 2*Pi periodic function.

My goal is compare the Fourier coefficients of f*f ( * convolution ) and The Fourier Coefficient of f.

Thanks for your help.

I already finished part a, my question is how do i define the function g with the variable k being any real value so that maple will find <f,g> = 0 (using the inner product defined)?

Im have alittle trouble with my secant method code. and was wondering if could get some help on the matter.

Secant:=proc(f,x0,tol)
fp=diff(f,x);
fp2=diff(f,x)-1;
guess0=x0;
guess1:=evalf(guess0-subs(x=guess0,fp)/subs(x=guess0,limit((fp-fp2)/guess0-guess1),x=guess1)); count:=1;
while abs(guess0-guess1)>tol do
guess0:=guess1;
guess1:=evalf(guess0-subs(x=guess0,fp)/subs(x=guess0,limit((fp-fp2)/guess0-guess1),x=guess1)); count:=count+1;
end;
guess1;count;
end:

im sort of new with numercal analysis.

The Maple command

int(exp(-z^2*sin(z)^2), z = 0 .. infinity, numeric, epsilon = 0.1e-1);
outputs
                          2.835068335

However, I am not sure if the answer is correct.

AOA... I want to plot the following function which is continuous in [0,3]

f:=x^2+1  for x belong to [0,1]

f:=x^2-1  for x belong to [1,2]

f:=x+1  for x belong to [2,3]

Kindly help...

Trying to call matrix from escel spreadsheet by command

M=ExcelTools:-Import("Book1.xlsx")

and getting error      M=?"Book1.xlsx"?  in red box and message error.

What is wrong? I do not understand. file Book1.xlsx is present in the same directory as my maple worksheet and not empty.

Please advise.

I have found the value of t1 and T, but I am unsure of the value. t1 and T in this case is the initialization time at the which the inventory level to zero in Reaches
warehouse. whether possible negative value? is there a lack of proper writing of parameters in this case? so that the output of t1 and T is negative? thanks a lot

> TC := (p*A*((lambda-sigma)*(exp(lambda*t2)-1)+lambda*(exp((lambda-sigma)*T)-exp((lambda-sigma)*t2)))/(lambda*(lambda-sigma))-Ca-A*exp(lambda*t1)*((beta*a2+b2)*(exp(beta*t1)-1)/beta^2-(lambda*a2-b2)*(1-exp(-lambda*t1))/lambda^2)/(beta+lambda)+A*exp(lambda*t1)*b2*t1/(lambda*beta)-W*((alpha*a1+b1)*(1-exp(-alpha*t1))-alpha*b1*t1*exp(-alpha*t1))/alpha^2+A*(exp(lambda*t2)*((a1+b1*t2)*lambda*alpha+b1*(lambda-alpha))-exp(lambda*t1)*(b1*(alpha^2-lambda^2*exp((lambda+alpha)*(t2-t1)))-(a1+b1*t1)*lambda*alpha*(alpha+lambda*exp((lambda+alpha)*(t2-t1))))/(lambda+alpha))/(lambda^2*alpha^2)+Cs*A*exp((lambda-sigma)*t2)*((T-t2)*(lambda-sigma)-exp((T-t2)*(lambda-sigma))+1)/(lambda-sigma)^2-L*A*((exp(lambda*T)-exp(lambda*t2))/lambda-(exp((lambda-sigma)*T)-exp((lambda-sigma)*t2))/(lambda-sigma))-C*(A*(exp((beta+lambda)*t1)-1)/(beta+lambda)+W+A*(exp((lambda-sigma)*T)-exp((lambda-sigma)*t2))/(lambda-sigma)))/T;
>
> TC2 := subs(t2 = (ln(W*(lambda+alpha)/A)+(lambda+alpha)*t1)/(lambda+alpha), TC);
>
> x1 := diff(TC2, t1) = 0;
>
> x2 := diff(TC2, T) = 0;
>
> x3 := evalf(simplify(lhs(eval(subs(A = 200, lambda = 0.3, a2 = 2.4, b2 = 0.01, a1 = 0.9, b1 = 0.01, alpha = 0.01, beta = 0.04, W = 100, Ca = 90, L = 7, C = 10, p = 15, Cs = 3, sigma = 0.25, x1)))));
>
> x4 := evalf(simplify(lhs(eval(subs(A = 200, lambda = 0.3, a2 = 2.4, b2 = 0.01, a1 = 0.9, b1 = 0.01, alpha = 0.01, beta = 0.04, W = 100, Ca = 90, L = 7, C = 10, p = 15, Cs = 3, sigma = 0.25, x2)))));

> x5 := fsolve({x3, x4}, {T, t1});
          x5 := {T = -15.72808468, t1 = -12.55374671}

Hi,

Maybe a good question.

Write  f(x)=ln(abs(cos(x)))   with infinite serie cosine(2*n*x).

Thank for your remark.

Hi everybody,

i don't understand when i use these examples from the help:

DE1 := {diff(z(x), x) = y(x)*x, diff(y(x), x, x) = y(x)*z(x)};
DEplot3d(DE1, [y(x), z(x)], x = -2 .. 2, [[y(0) = 1, (D(y))(0) = 2, z(0) = 1]], y = -4 .. 4, obsrange = true, stepsize = 0.5e-1, iterations = 3, orientation = [-124, 72]);

and when i look on my screen i have a white cube without phase portrait so i don't understand...

Thanks! and sorry for my english i'm french...

You have clickable calc. Today I saw in your email that you have clickable physic but in french. Do you have it in english too>?

Thank you

manolo