MaplePrimes Questions

Hi

 

I am trying to solve a Heat Transfer problem (of transient conduction in a 2D annulus of material with convective boundary conditions). I currently have a fixed heat transfer coefficient, but in reality this varies with surface temperature.

 

I am using the PDEsolve meothod to solve the equation. Is there a way of linking the temperature at the end of each time step into an equation to calculate h.

I am a Maple/programming...

Is it possible to have a contour plot of an ode, 

restart:with(plots);alpha:=1:

de1:=alpha*diff(f(y),y$4)+(diff(f(y),y$2)*diff(f(y),y$3)^2+diff(f(y),y$4)*diff(f(y),y$2)^2);

with  such type of bcs?

bc1:= f(1+sin(x)) = .95, f(-.1-.1*sin(x)) = -.95, (D(f))(1+sin(x)) = -1, (D(f))(-.1-.1*sin(x)) = -1;

contourplot({de1,bc1}, [x,y, f(y)],x=1..10, y=1..10);

Thanks

Let A(2 , -2 , 0) B( 4 , 2 , 5 ) & C( -1 , -3 , 0).Find  H(x,y,z) be the orthocentre of the triangle ABC.

Hi, why is it when i use swapcol, it doesn't register? For example,

k:=RandomMatrix(9):
j:=swapcol(k,1,4):
Dimensions(j)
j

Please help. Thanks. 

Hi, I am trying to use swaprow in a loop, but it is not working, could someone please point out what i am doing wrong please?

aFront:=RandomMatrix(9):

with(linalg):
for m from 1 to 3 do
Quad2:=swaprow(aFront,m,m+2)
end do:

Why can't i get Quad2. Please help, thanks.

What is the difference between with(Student[LinearAlgebra]) and with(LinearAlgebra)?

When i tried to use functions such as AddRow, SwapRow, it doesn't work when i load "LinearAlgebra", but works fine with "Student[LinearAlgebra]". May I know why is this so please? Thanks.

Let N(1, 1)=1 and N(1,k)=0 if k<>1. Let N(s+1,k) = N(s,k) + N(s,k-1) + N(s,k+1).
Acting in such a way, we obtain  the triangle
         1
       1,1,1
    1,2,3,2,1
  1,3,6,7,6,3,1
.................,
where only the nonzero terms are shown.
What is the explicit formula for N(s,k)? How to find it with Maple?

how to solve two equations simultaneously in maple and also i want to get only real values,, just omit the imaginary results.. anyone help to me

 

 

 

Thankyou

I would like to define the "12 by 12" matrix A where a_{ij} = (i-1)^(j-1) using for loops. How can this be done? If for loops are not the most efficient way, any other suggestions are welcome! Thanks!

Hello,

I want to build a paper model of an immersion of real projective plane made out of paper strips. I want to use maple to plot the curves which represent the paper strips. I have written a code shown below which computes the curve for one of the strips. In this code, alpha is set to Pi/2 and the computation goes through. However the computation should be performed for various alpha. But if I set alpha=0, then f (see code below) is not computable, if I set alpha=Pi/4,...

eq1:=diff(f(eta),eta,eta,eta)+f(eta)*diff(f(eta),eta,eta)+beta*(1-diff(f(eta),eta)^2)=0;

eq2:=diff(theta(eta), eta, eta)+pr*f(eta)*(diff(theta(eta), eta))+pr*Ec*(diff(f(eta), eta, eta))^2

+(2-beta)*pr*Q*theta(eta) = 0;

bc:=theta(9)=0,D(theta)(0)=-Nc*(1-theta(0)),f(0)=1,D(f)(0)=lambda,D(f)(9)=1};

Para:={beta=1,Ec=0.5,Q=-0.5,Nc=5,pr=3}:

How to plot -D(theta)(0) vs lambda?

Thanks

How many positive integer solutions (a,b,c) to 2a+3b+3c=2010

I created a math related blog, named ottomath, on Goggle blogger. My Maple 14 is on a PC. I post from a Mac.  Had to copy the Maple file to Word.  Then copy each input or output image to Paint to save as JPG, and then insert each image into the correct spot on the blog.  Very tedious.  Hard to control size.  Lots of unwanted spaces.  Is there a better way?

Hi there.

 

I build a costum component on maplesim. It has 2 inputs and several outpus, like this:

 

As you cant see i get an error. At this simulation the constant where is probe1 is k=4. I have good results if n=2-~3.5. But what is strange is that if instead of a constant input n=4, i use a...

Hi!

I have a function of two variables f(a,b)

 f(a,b) =16*b^2/(a+sqrt(a^2+8*b^2))^2

and I need to rewrite it to a function of a single variable

f(x) = 16*x^2/(2+2*sqrt(1+8*x^2)+8*x^2)

where x=b/a. It is easy...

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