Hello all,

I have the following equation:

N*exp(-(1/2)*eta*epsilon*(N*alpha*epsilon*w+2*N*w*C[max]-alpha*epsilon*z-2*Q1*alpha)/(w*N))*S1*upsilon*w-N*S1*upsilon*w+K1^2*alpha*eta*z*epsilon+K1*alpha*eta*z*epsilon*S1 = 0

in which I need to find solution for epsilon (analytical solution) when epsilon>0.  

Thanks,

Dmitry

I have a nonlinear system with 4 equations and 4 unknowns. I am using fsolve. I know that there are multiple solutions for each variable but am only getting one. I need the others. what do I do??

This is my code:

R__1 := Matrix([[1, 0] , [0, 1] ]);

R__2 := Matrix([[1/2, sqrt(3)/2] , [-sqrt(3)/2, 1/2] ]);

R__3 := Matrix([[-1/2, sqrt(3)/2] , [-sqrt(3)/2, -1/2] ]);

R__4 := Matrix([[-1, 0] , [0, -1] ]);

R__5 := Matrix([[-1/2, -sqrt(3)/2] , [sqrt(3)/2, -1/2] ]);

d__1 := Vector( [ 0, 5.4] );

d__2 := Vector( [ 6.4, 4.539] );

d__3 := Vector( [ 11, 4.078] );

d__4 := Vector( [ 15.5, 2.079] );

d__5 := Vector( [ 19, 1.039] );

a := Vector( [ a__x, a__y] );

A__1:=R__1.a+d__1;

A__2:=R__2.a+d__2;

A__3:=R__3.a+d__3;

A__4:=R__4.a+d__4;

A__5:=R__5.a+d__5;

OO:=Vector([O__x,O__y]);

DA1:=A__2.A__2-A__1.A__1-2*(A__2-A__1).OO;

DA2:=A__3.A__3-A__1.A__1-2*(A__3-A__1).OO;

DA3:=A__4.A__4-A__1.A__1-2*(A__4-A__1).OO;

DA4:=A__5.A__5-A__1.A__1-2*(A__5-A__1).OO;

fsolve({DA1,DA2,DA3,DA4},{a__x,a__y,O__x,O__y});

Thanks for any tips you may be able to offer

How do I plot the following equations in Maple ?:

I already tried this: 

According to the given solution the plot should look like that: 

I think I have to tell maple that the function is defined from R^2 -> R, but I don't know how to do this. 

Thanks in advance for your kind help.

Hello people in mapleprimes,

I want to draw a graph of a procedure.

filter:=x->if x<10 then 1-x/10 else 0 fi;

plot('filter(x)',x=0..20);

works well. But, I don't know why it is needed for filter(x) is wrapped with foward quotte ' .

I changed that quote to back quote ` but, in this case the result hadn't appeared.

And, without the foward quote ', error appears.

And, even if I wrapped x with ' as in plot('filter(x)','x' =0..20),

a graph appeared properly, though I cannot understand why wrapped x, 'x' is right.

Please teach me the logic of the above code.

Best wishes.

taro yamada

solve(a/(x+1)>1,x)

When I type this command and run it,It returns nothing but this warning

"Warning, solutions may have been lost"

How can I get the correct solution using Maple 18

AoA. How are you hope you will be fine. Sir the following matrix have been given

A := Matrix(2, 2, {(1, 1) = 1, (1, 2) = 2, (2, 1) = -1, (2, 2) = 2});

B := Matrix(2, 2, {(1, 1) = 1, (1, 2) = 0, (2, 1) = -2, (2, 2) = 3});

C := Matrix(2, 2, {(1, 1) = 0, (1, 2) = 0, (2, 1) = 0, (2, 2) = 0});

I want to write M by M matrix using the above matrices like this

P:=[[[A,B,B,...,B],[C,A,B,...,B],[C,C,A,...,B],[.,.,.,...,B],[C,C,C,...,A]]]

PhD (Scholar)
Department of Mathematics

AoA... I want to plot the following functions

f(x)=sin(x)

g(x)=sin(x)-x+x^2

h(x)=cos(x)-sin(x)

I(x)=exp(x)-x

J(x)=sin(x)+exp(x)

in one coordinate having the line style and legend like attached file.

1-s2.0-S0377042714003331-main.pdf

PhD (Scholar)
Department of Mathematics

After I do

restart;
plot(cos);

Now I right-click on the plot, and from the menu change the "line" to "dashed" style, so the plot becomes like this:

Now I would like to obtain the Maple plot command that would have generated the above plot, so I can use the command later in my script.  I could not find a menu option to show the Maple command.

Maple 18.02 on windows 7

I want to get the result of multi-matrix multiply like followed below,

but error "final value in for loop must be numeric or character"

(*n is arbitrary and B[1],B[2],...,B[n] have been obtained*)

A:=LinearAlgebra:-IdentityMatrix(n);
#using the multiplication operation of matrix
for i from 1 to n do
   A:=LinearAlgebra:-Multiply(A,B[i]);
od:

return A

help me 

thanks

Hello

I have a loop with the do structure but there is an error in the loop .

how can I continue the loop by error or disregard it?

y(t) = _C1*exp(-1.*t)*sin(.57736*t)+_C2*exp(-1.*t)*cos(.57736*t)

The answer i got for a DE raised in mapleprime is given above.

What command do i write now to get a plot of the same?

Ramakrishnan V

Hey, how is can i see all the steps in maple? I would specially like to know it for differential equations.

For example we could use this one:

dl := 3*(diff(y(t), t, t))+6*(diff(y(t), t))+4*y(t) = 0 

Download problem.mw

This is part of a large simplifcation where lots of terms are being substituted. In two of those terms, it did not simplify as we would expect.

I think the main thing is trying to find a way to factor out the "2".

I could do this

> rule3:=w[1]/(1+1/exp(mu[p]))^2+(-w[1]+1)/(1+1/(exp(mu[p])*exp(eta[p2])))^2 = s[3];
>rule3:=2*rule3;

> rule3ne:=-(w[1]/(1+1/exp(mu[p]))^2+(-w[1]+1)/(1+1/(exp(mu[p])*exp(eta[p2])))^2) = -s[3];
> rule3ne:=2*rule3ne;

> applyrule(rule3,tmp[1]);
> applyrule(rule3ne,tmp[2]);

For this example, this works.

But I hope for a more generic approach.

Thanks,

casper

Hello, Im trying to do a jocobian

http://www.maplesoft.com/support/help/Maple/view.aspx?path=VectorCalculus/Jacobian

but when I try the example code

jacobian([rcos(t), rsin(t), r^2*t], [r, t])

i only get the output as 

jacobian([rcos(t), rsin(t), RandomMatrix(4, 4*density = .75, outputoptions = [shape = tringular*lowe])^2*t], [RandomMatrix(4, 4*density = .75, outputoptions = [shape = tringular*lowe]), t])

I want the output as a matrix as in the example url.

Thanks

a:=[1,2,3]:

b:=[1,2,3]:

evalb(a=b)    #The result is true

c:=Array([1,2,3]):

d:=Array([1,2,3]):

evalb(c=d)    #The result is false

This is Why?