After substitution of (10) into (4), how to collect the terms of like powers of eta (i.e., eta^-3, eta^-2,eta^-1, eta^0, eta^1,eta^2 ), and equate the coefficients to
zero, get a system of algebraic equations for A[m]?

PA.mw 

g := proc() use a=a+b in use b= a-b in a*b end use end use end proc:

Maple shows g := proc() (a+b)*(a+b) end proc. 

My guess is (a+b)*a. What is wrong with me?

I faced a problem with the following syntax which provided me we partial circles inequality plotting, and how able to improve the syntax:
restart: with(plots):
inequal({y > -1, y >= x^2+1, (x-1)^2+(y-1)^2 <= 16}, x = -5 .. 8, y = -6 .. 6, optionsfeasible = (color = grey), optionsexcluded = (color = white));

Hello, 

How can I force Maple to perform division on a fractional polynomial?  Here's an exmaple of what Im trying to do - I want rr and nsr to be divided and simplified and return a polynomial.

I can see from this that its doing what i want for integer exponents - just not fractions!

I've tried everything I can think of... Let me know! Thanks.

Hello! 

Ive stubled into something odd. Here it is: 

Now I really wonder how they figured how i was suppose to figure out how this is suppose to go. They did not explain all that much on how to find this out. This specifically is a "Computerized Question." 

It says "find the smallest number "n", so that A^n=I"

This was the result when i tried to solve it:

"Error, (in Engine:-Dispatch)" I have no idea what is wrong. 

Any way, 

Greetings,

The Function 

Download Mapleprimes_Question_Book_2_Paragraph_4.1_Question_9.mw

I make new cone puzzle. However, I cat't make function l(θ). Can maple solve this puzzle?

θ=90 degree is a YouTube problem I found. 

Have to draw the graph

What's going on in the following? Why can't I restore the default behavior of diff after using Physics:-diff or even just using with(Physics)? Is it because of Physics:-ModuleLoad()?

Download PhysicsDiff.mw

I don't know why the prettyprinted output of my worksheet is shown the way that it is above. I didn't do anything differently than I usually do to upload a worksheet. Anyway, the output is simple enough that I think that my Question is still clear.

Download text_program.mw

Dear all,

      The program is as follows (The "mw" files are also attached). The integraion "evalf(Int(k*sin(x)*T1,x=0..Pi/2,y=-Pi/6..-Pi/6+afa))" can not be worked out in several hours, but if the upper limit of x is changed to 0.5 (for example), the integration can be worked out quickly. I have tried to change the program to math model, however, the question still exists. How to solve this problem?

afa:=0.3:
vh:=3.5:
u:=3.12:
mu:=5.5:
gama:=-4*10^(-29)*(1-cos(6*afa))*(1-1*10^(-8)*I):
d1:=1.78*10^(-9):
d2:=48.22*10^(-9):
HBAR:=1.05457266*10^(-34):
ME:=9.1093897*10^(-31):
ELEC:=1.60217733*10^(-19):
Kh:=2.95*10^10:
kc:=sqrt(2*ME*ELEC/HBAR^2):
k:=kc*sqrt(mu):
k0:=sqrt(k^2-k^2*sin(x)^2):
kh:=sqrt(k^2-(Kh-k*sin(x)*cos(y))^2 - k^2 * sin(x)^2 * sin(y)^2):
khg:=sqrt(k^2-(2*Kh*sin(afa/2)*sin(afa/2)-k*sin(x)*cos(y))^2-(2*Kh*sin(afa/2)*cos(afa/2)+k*sin(x)*sin(y))^2):
kg1:=sqrt(k^2-(Kh*cos(Pi/3-afa)-k*sin(x)*cos(y))^2-(Kh*sin(Pi/3-afa)+k*sin(x)*sin(y))^2):
kg2:=sqrt(k^2-(Kh*cos(afa)-k*sin(x)*cos(y))^2-(k*sin(x)*sin(y)-Kh*sin(afa))^2):
k0pl:=sqrt(k^2-k^2*sin(x)^2+kc^2*vh-kc^2*u):
k0mi:=sqrt(k^2-k^2*sin(x)^2-kc^2*vh-kc^2*u):
khpl:=sqrt(k^2-(Kh-k*sin(x)*cos(y))^2-k^2*sin(x)^2*sin(y)^2+kc^2*vh-kc^2*u):
khmi:=sqrt(k^2-(Kh-k*sin(x)*cos(y))^2-k^2*sin(x)^2*sin(y)^2-kc^2*vh-kc^2*u):
k0plpl:=sqrt(k^2-k^2*sin(x)^2+2*kc^2*vh):
k0mimi:=sqrt(k^2-k^2*sin(x)^2-2*kc^2*vh):
khplpl:=sqrt(k^2-(Kh-k*sin(x)*cos(y))^2-k^2*sin(x)^2*sin(y)^2+2*kc^2*vh):
khmimi:=sqrt(k^2-(Kh-k*sin(x)*cos(y))^2-k^2*sin(x)^2*sin(y)^2-2*kc^2*vh):
khgplpl:=sqrt(k^2-(2*Kh*sin(afa/2)*sin(afa/2)-k*sin(x)*cos(y))^2-(2*Kh*sin(afa/2)*cos(afa/2)+k*sin(x)*sin(y))^2+2*kc^2*vh):
khgmimi:=sqrt(k^2-(2*Kh*sin(afa/2)*sin(afa/2)-k*sin(x)*cos(y))^2-(2*Kh*sin(afa/2)*cos(afa/2)+k*sin(x)*sin(y))^2-2*kc^2*vh):
kg1plpl:=sqrt(k^2-(Kh*cos(Pi/3-afa)-k*sin(x)*cos(y))^2-(Kh*sin(Pi/3-afa)+k*sin(x)*sin(y))^2+2*kc^2*vh):
kg1mimi:=sqrt(k^2-(Kh*cos(Pi/3-afa)-k*sin(x)*cos(y))^2-(Kh*sin(Pi/3-afa)+k*sin(x)*sin(y))^2-2*kc^2*vh):
kg2plpl:=sqrt(k^2-(Kh*cos(afa)-k*sin(x)*cos(y))^2-(k*sin(x)*sin(y)-Kh*sin(afa))^2+2*kc^2*vh):
kg2mimi:=sqrt(k^2-(Kh*cos(afa)-k*sin(x)*cos(y))^2-(k*sin(x)*sin(y)-Kh*sin(afa))^2-2*kc^2*vh):
A1:=1/(1+I*ME*gama/(HBAR^2*k0pl))*exp(I*k0pl*d1)/2:
B1:=1/(1+I*ME*gama/(HBAR^2*k0pl))*exp(I*k0pl*d1)/2:
A2:=1/(1+I*ME*gama/(HBAR^2*khpl))*exp(I*khpl*d1)/2:
B2:=1/(1+I*ME*gama/(HBAR^2*khpl))*exp(I*khpl*d1)/2:
A3:=1/(1+I*ME*gama/(HBAR^2*k0mi))*exp(I*k0mi*d1)/2:
B3:=1/(1+I*ME*gama/(HBAR^2*k0mi))*exp(I*k0mi*d1)/2:
A4:=1/(1+I*ME*gama/(HBAR^2*khmi))*exp(I*khmi*d1)/2:
B4:=1/(1+I*ME*gama/(HBAR^2*khmi))*exp(I*khmi*d1)/2:
T1:=1/4*Re(abs(A1)^2*k0plpl*exp(I*(k0plpl-conjugate(k0plpl))*d2)+abs(A1)^2*kg1plpl*exp(I*(kg1plpl-conjugate(kg1plpl))*d2)+abs(A2)^2*khplpl*exp(I*(khplpl-conjugate(khplpl))*d2)+abs(A2)^2*khgplpl*exp(I*(khgplpl-conjugate(khgplpl))*d2)+abs(B3)^2*k0mimi*exp(I*(k0mimi-conjugate(k0mimi))*d2)+abs(B3)^2*kg1mimi*exp(I*(kg1mimi-conjugate(kg1mimi))*d2)+abs(B4)^2*khmimi*exp(I*(khmimi-conjugate(khmimi))*d2)+abs(B4)^2*khgmimi*exp(I*(khgmimi-conjugate(khgmimi))*d2)+abs(B1+A3)^2*k0*exp(I*(k0-conjugate(k0))*d2)+abs(B1-A3)^2*kg1*exp(I*(kg1-conjugate(kg1))*d2)+abs(A4-B2)^2*kh*exp(I*(kh-conjugate(kh))*d2)+abs(A4+B2)^2*khg*exp(I*(khg-conjugate(khg))*d2)+conjugate(A1)*B3*k0mimi*exp(I*(k0mimi-conjugate(k0plpl))*d2)+A1*conjugate(B3)*k0plpl*exp(I*(k0plpl-conjugate(k0mimi))*d2)+conjugate(A1)*(B1+A3)*k0*exp(I*(k0-conjugate(k0plpl))*d2)+A1*conjugate(B1+A3)*k0plpl*exp(I*(k0plpl-conjugate(k0))*d2)+conjugate(B3)*(B1+A3)*k0*exp(I*(k0-conjugate(k0mimi))*d2)+B3*conjugate(B1+A3)*k0mimi*exp(I*(k0mimi-conjugate(k0))*d2)-conjugate(A1)*B3*kg1mimi*exp(I*(kg1mimi-conjugate(kg1plpl))*d2)-A1*conjugate(B3)*kg1plpl*exp(I*(kg1plpl-conjugate(kg1mimi))*d2)+conjugate(A1)*(A3-B1)*kg1*exp(I*(kg1-conjugate(kg1plpl))*d2)+A1*conjugate(A3-B1)*kg1plpl*exp(I*(kg1plpl-conjugate(kg1))*d2)+conjugate(B3)*(B1-A3)*kg1*exp(I*(kg1-conjugate(kg1mimi))*d2)+B3*conjugate(B1-A3)*kg1mimi*exp(I*(kg1mimi-conjugate(kg1))*d2)-conjugate(A2)*B4*khmimi*exp(I*(khmimi-conjugate(khplpl))*d2)-A2*conjugate(B4)*khplpl*exp(I*(khplpl-conjugate(khmimi))*d2)+conjugate(A2)*(B2-A4)*kh*exp(I*(kh-conjugate(khplpl))*d2)+A2*conjugate(B2-A4)*khplpl*exp(I*(khplpl-conjugate(kh))*d2)+conjugate(B4)*(A4-B2)*kh*exp(I*(kh-conjugate(khmimi))*d2)+B4*conjugate(A4-B2)*khmimi*exp(I*(khmimi-conjugate(kh))*d2)+conjugate(A2)*B4*khgmimi*exp(I*(khgmimi-conjugate(khgplpl))*d2)+A2*conjugate(B4)*khgplpl*exp(I*(khgplpl-conjugate(khgmimi))*d2)-conjugate(A2)*(A4+B2)*khg*exp(I*(khg-conjugate(khgplpl))*d2)-A2*conjugate(A4+B2)*khgplpl*exp(I*(khgplpl-conjugate(khg))*d2)-conjugate(B4)*(A4+B2)*khg*exp(I*(khg-conjugate(khgmimi))*d2)-B4*conjugate(A4+B2)*khgmimi*exp(I*(khgmimi-conjugate(khg))*d2)):
T2:=1/4*Re(abs(A1)^2*k0plpl*exp(I*(k0plpl-conjugate(k0plpl))*d2)+abs(A1)^2*kg2plpl*exp(I*(kg2plpl-conjugate(kg2plpl))*d2)+abs(A2)^2*khplpl*exp(I*(khplpl-conjugate(khplpl))*d2)+abs(A2)^2*khgplpl*exp(I*(khgplpl-conjugate(khgplpl))*d2)+abs(B3)^2*k0mimi*exp(I*(k0mimi-conjugate(k0mimi))*d2)+abs(B3)^2*kg2mimi*exp(I*(kg2mimi-conjugate(kg2mimi))*d2)+abs(B4)^2*khmimi*exp(I*(khmimi-conjugate(khmimi))*d2)+abs(B4)^2*khgmimi*exp(I*(khgmimi-conjugate(khgmimi))*d2)+abs(B1+A3)^2*k0*exp(I*(k0-conjugate(k0))*d2)+abs(B1-A3)^2*kg2*exp(I*(kg2-conjugate(kg2))*d2)+abs(A4-B2)^2*kh*exp(I*(kh-conjugate(kh))*d2)+abs(A4+B2)^2*khg*exp(I*(khg-conjugate(khg))*d2)+conjugate(A1)*B3*k0mimi*exp(I*(k0mimi-conjugate(k0plpl))*d2)+A1*conjugate(B3)*k0plpl*exp(I*(k0plpl-conjugate(k0mimi))*d2)+conjugate(A1)*(B1+A3)*k0*exp(I*(k0-conjugate(k0plpl))*d2)+A1*conjugate(B1+A3)*k0plpl*exp(I*(k0plpl-conjugate(k0))*d2)+conjugate(B3)*(B1+A3)*k0*exp(I*(k0-conjugate(k0mimi))*d2)+B3*conjugate(B1+A3)*k0mimi*exp(I*(k0mimi-conjugate(k0))*d2)-conjugate(A1)*B3*kg2mimi*exp(I*(kg2mimi-conjugate(kg2plpl))*d2)-A1*conjugate(B3)*kg2plpl*exp(I*(kg2plpl-conjugate(kg2mimi))*d2)+conjugate(A1)*(A3-B1)*kg2*exp(I*(kg2-conjugate(kg2plpl))*d2)+A1*conjugate(A3-B1)*kg2plpl*exp(I*(kg2plpl-conjugate(kg2))*d2)+conjugate(B3)*(B1-A3)*kg2*exp(I*(kg2-conjugate(kg2mimi))*d2)+B3*conjugate(B1-A3)*kg2mimi*exp(I*(kg2mimi-conjugate(kg2))*d2)-conjugate(A2)*B4*khmimi*exp(I*(khmimi-conjugate(khplpl))*d2)-A2*conjugate(B4)*khplpl*exp(I*(khplpl-conjugate(khmimi))*d2)+conjugate(A2)*(B2-A4)*kh*exp(I*(kh-conjugate(khplpl))*d2)+A2*conjugate(B2-A4)*khplpl*exp(I*(khplpl-conjugate(kh))*d2)+conjugate(B4)*(A4-B2)*kh*exp(I*(kh-conjugate(khmimi))*d2)+B4*conjugate(A4-B2)*khmimi*exp(I*(khmimi-conjugate(kh))*d2)+conjugate(A2)*B4*khgmimi*exp(I*(khgmimi-conjugate(khgplpl))*d2)+A2*conjugate(B4)*khgplpl*exp(I*(khgplpl-conjugate(khgmimi))*d2)-conjugate(A2)*(A4+B2)*khg*exp(I*(khg-conjugate(khgplpl))*d2)-A2*conjugate(A4+B2)*khgplpl*exp(I*(khgplpl-conjugate(khg))*d2)-conjugate(B4)*(A4+B2)*khg*exp(I*(khg-conjugate(khgmimi))*d2)-B4*conjugate(A4+B2)*khgmimi*exp(I*(khgmimi-conjugate(khg))*d2)):
evalf(Int(k*sin(x)*T1,x=0..Pi/2,y=-Pi/6..-Pi/6+afa))

Download text_program.mw

I tryning to to plot 3d and then contour plot of the function N vs alpha

This is my try please any comments might help

N_vs_alpha.mw

Dear all,

im having trouble with adding two matrixes when they are only described with a letter asigned to them. I really dont know why it is the case. But it has got the be done with letters only because later on i will need this a lot with vector calculations etc. 

Thank you!

Greetings,

The Function

Download Mapleprimes_Question_Book_2_Paragraph_4.1.mw

SlitRecoil.mw

At line 46 I do some integrals of a probablity function obainted from complex amplitudes. The plot of the function is shown above. However, the integral suddlenly drops to almost nothing when I increase the limits from +/- 0.195 to +/-0.2. The transition actually occus at ~0.196 (not shown)

This makes no sense. It doesn't seem  from the plot that the step size could get so large as to miss the peak! However, I don't know how to change numerical integral step size to test that.

---Arthur (a.k.a. Traruh)

Download how_do_I_algebraically_factor_an_expression_from_an_expression.mw

I have an expression and I want to select the part of the expression which has diff(y(x),x) in the expression.

Using select(has,expr,diff(y(x),x) works, except when the expression happend to be exactly diff(y(x),x) in this case select returns diff()

I understand why this happens. But I can not avoid this problem by say first checking if the expression has more than one operand, because nops(diff(y(x),x) is 2 and not one. Also 1+diff(y(x),x) has two operands. And I can not check if the expression is of type `+` or `*` before, because other types can have more than one operand also.

So now what I do is the folliwng: first check if the expression has diff(y(x),x). If so, convert the expression to D and now check if nops is more than one, and if so, only now call select.

This is becuase nops(D(y)(x)) is one, while nops(diff(y(x),x) is two.

Is there a better way to do this, in order to avoid calling select and getting diff() ? I suppose I could also just check if the expression is exactly diff(y(x),x) before even calling select or has and avoid all this?

Worksheet attached

Download best_way_to_check.mw

Hi

I have an equation which i want solve it with DTM and sketch the graph of f(η) along y axis and η along x axis, f ‘( η) and g( η)

M:=0..5

F[0]:=0;F[1]:=1;F[2]:=a/2;G(0)=0

That's my pleasure If there is somebody help me to code and solve this problem.

Thanks for every one very very much.