MaplePrimes Questions

 Suppose that A is an m×n real matrix. The function TA:ℝn→ℝm   defined by

TA(x)=Ax,  for all 𝕩∈ℝn

     is a linear transformation.

let A=<< 87, -66, -90, 12, 48>|<-36, -40, -82, -54, 15>|<99, 79, 76, -31, 27>|<-69, 15, -10, 45, -9>>

and x= <9,-4,2,-17>.

Then TA(x)=   Preview   

   Alternatively, you can copy your answer from your Maple worksheet and paste it to the answer box.

 

(b) Suppose now that the linear map T:ℝ2→ℝ3  is defined by, for all 𝕩=(x1,x2)∈ℝ2

 T(x)=  <<x1+6x2>|<−2x2>|<−4x1+2x2>>

    

     Enter the matrix M , in Maple syntax, in the box below such that T(x)=Mx  for all x∈ℝ2,  

  M=    Preview   

 

Can someone pls help me with this question. TIA.

   

 

 

I have no problems assigning simple plots to variables and then displaying all in a single plot using the display command.

However, I am now trying to do the same using implicitplot without success.

This is my code;

restart;
f := 3*(x^2 + y^2)^2 = 100*x*y;

with(plots, implicitplot);
p1 := implicitplot(f, x = -4 .. 4, y = -4 .. 4, rangeasview = true):

p2 := pointplot([[1, Pi/2], [-1, -Pi/2]], color = red):

display({p1,p2})

What I get is a small implicit plot and the code for the pointplot back at me.

Is there any way to make this work?

Thank you for your help.

Jose

 

I solved this ODE and got a solution and wanted to compre it with Maple. This is initial value first oder ODE. So it should have no constants in it. But Maple's solution contains something I never seen before _B1~

I wonder what it means? And odetest did not verify Maple's solution. 

restart;
ode:=diff(y(x),x)-y(x)/x+csc(y(x)/x)=0;
sol:=dsolve([ode,y(1)=0]);
simplify(odetest(sol,ode));

odetest does not gives zero.

This is my solution

mysol:=y(x)=x*arccos(ln(x)+1);
odetest(mysol,ode)

   0

Any idea what _B1~ means? The ~ looks like it is an assumed variable? may be leaked from inside Maple.

Maple 2020.1 on windows 10

 

We've come over another annoying "feature" in units handling.

Maple isn't able to compare variables that have similar units, but are defined differently (like MPa and N/mm^2).

Did a quick check in Mathcad, seems to work there.

Compare_units.mw

I use odeadvisor a lot to tell me the type of the ode. It is one of the best tools in Maple.

But sometimes it overlooks some types of ODE's, if the ODE is written in different way. This does not happen alot. Here is an example

ode:=diff(y(x),x) = (2*x+y(x))/(3-x+3*y(x)^2);
DEtools:-odeadvisor(ode)


And advisor says it is rational, which is correct. 

But it does not also say it is exact. By rewriting as follows, it now see it is exact as well as rational:

ode2:=(denom(rhs(ode)))*diff(y(x),x)-(numer(rhs(ode)))=0;
DEtools:-odeadvisor(ode2);

And now it says [_exact, _rational]. It is the same ODE, just written different.

This is not a complaint about the advisor, I know it is not easy to figure the type of the ODE under different trasformations, but may be something to look into to improve it to be able to detect more types.

Maple 2020.1 

One thing I always liked about Maple, is that it does not do automatic simplifications or automatic re-write of expressions without the user explicitly asking for it like some other CAS systems do, which I think this is the right way.

So I was surprised when I set up a rational expression of a numerator and denominator, then when I asked for its denom and numer, I found Maple did automatic rewrite (even though on the screen the expression remained as it was originally). This caused a bug in my program (since it assumed as long as no simplifcation is made on the expression, numer and denom will remain as it was orginally placed). Here is an example

restart;
num:=-(1-x/exp(y));
den:=(exp(y)+x);
expr:=num/den;

So now, one would expect, by looking at the screen, when asking for numer(expr) to obtain back -(1-x/exp(y))  but this is not what happens

numer(expr)

And 

denom(expr)

So Maple's internal representation of numer and denom, is not what "appears" on the screen for the user. Maple automatically replaced -1+x/exp(y) by (-exp(y)+x)/exp(y) and then moved denominator of this, which is exp(y), down to the denominator of the orginal expression.

I was surprised by this, since as I said, my experence with Maple is that it keeps expressions as entered and will change them only when the user asks for a change.

How common is such behavior in Maple? and why did Maple do this under the cover manipulation in this case? It is probably documented somewhere if I search hard enough.

 

 

 

ode := diff(x(t), t, t) = - sin(x(t)^3)/x(t)^2

ics := x(0) = 0.7, D(x)(0) = 0.8

sol := dsolve({ics, ode}, numeric)

How can I  plot the derivative of the function x(t)?

I tried something like that:

odeplot(diff(sol, t), t = 0 .. 20) 

but not working

 

How to create procedure "mySumOfMatrixDiagonal(M)" which calculates the sum of the square of diagonal components for any given square matrix

Good day.

I have a simple function that I would like to plot, but am finding this awkward to do. My objective is to plot the function for varying k-values and I tried doing this using implicitplot and sequencing values of k.

The function in question is:
y := k*x*sqrt(z*(1-z));

The constant, k, takes the values: 5, 10, 15, ..., 100
The variables lie in the range: 0 ≤ x < 1 and 0 ≤ z < 1

So, if someone can tell me how to construct a plot of multiple solution curves for varying k, I would be most grateful.

Thanks for reading!

MaplePrimes_Plot.mw

 

Hello all, 

When I tried to extract the RHS of the answer from 'solve()' command, the attempt failed. 


 

restart;

sys := U__s^2 = ((1+sigma)*U__T2N - u__rN * U__T2N/(1+sigma))^2+(u__xN * U__T2N/(1+sigma))^2;

U__s^2 = ((1+sigma)*U__T2N-u__rN*U__T2N/(1+sigma))^2+u__xN^2*U__T2N^2/(1+sigma)^2

(1)

answer := solve( sys, {U__T2N} );

{U__T2N = (1+sigma)*U__s/(sigma^4+4*sigma^3-2*sigma^2*u__rN+6*sigma^2-4*sigma*u__rN+u__rN^2+u__xN^2+4*sigma-2*u__rN+1)^(1/2)}, {U__T2N = -(1+sigma)*U__s/(sigma^4+4*sigma^3-2*sigma^2*u__rN+6*sigma^2-4*sigma*u__rN+u__rN^2+u__xN^2+4*sigma-2*u__rN+1)^(1/2)}

(2)

answer[1];

{U__T2N = (1+sigma)*U__s/(sigma^4+4*sigma^3-2*sigma^2*u__rN+6*sigma^2-4*sigma*u__rN+u__rN^2+u__xN^2+4*sigma-2*u__rN+1)^(1/2)}

(3)

rhs(answer[1]);

Error, invalid input: rhs received {U__T2N = (1+sigma)*U__s/(sigma^4+4*sigma^3-2*sigma^2*u__rN+6*sigma^2-4*sigma*u__rN+u__rN^2+u__xN^2+4*sigma-2*u__rN+1)^(1/2)}, which is not valid for its 1st argument, expr

 

 


Perhaps, the failure might be related to the fact that the equation is contained in curly brackets, but I could not come up with a solution. 

Please let me have a chance to learn the way to do the 'rhs()' operation in the correct way. 

Thank you, 

In Kwon Park 

Download Qprime_20200710.mw

I want to define a vector function, then plot it, differentiate it, etc.

The best I've been able to do so far is to define it two different ways: one for evaluating, one for symbolic manipulation

with(plots): with(VectorCalculus):
r:= < cos(t), sin(t), t >;  # symbolic version of function, for example to take derivative
# returns derivative,
diff(r,t);
rf := (t)->evalf( < cos(t), sin(t), t > );   # returns numerical value of function
# we use numerical version to plot
rCurve := spacecurve( rf(t), t = -1 .. 1 );
# But how to return value of derivative?? Next line doesn't work.
df := (t)->evalf( diff(r,t) );

But how do I plot the derivative? The last line doesn't work. I've tried various variations but no luck.

I don't think this approach is write (why define two different ways?) but haven't been able to figure out how to do it.

Various online docs haven't helped.

 

I was trying to compare my solution with Maple on this ode, when I noticed Maple gives solution with no y(x)= in it. 

restart;
ode:=(y(x)-x*diff(y(x),x))/(y(x)^2+diff(y(x),x))=(y(x)-x*diff(y(x),x))/(1+x^2*diff(y(x),x));
sol:=dsolve(ode)

When there is more than one solution, Maple write y(x) on each. For an example

dsolve(diff(y(x),x)^2=x)

How to explain this output?

Maple 2020.1

I think I've seen such a problem before but thought it was fixed.

Here is an example, where depending on what one calls the constant of integration, maple can or not, verify the solution of the ode.

This should not happen.

When calling the constant of integration C[1] or _C Maple does not verify the solution. Only when using _C1 it does.

This is a problem, since I do not use _C1 or _C2  in my solution (so not to conflict with Maple's), I use C[1] and C[2].

Is there a workaround for this? 

Example 1

ode:=diff(z(x),x)+z(x)*cos(x)=z(x)^n*sin(2*x);
mysol:=z(x) = 1/((_C1*exp(sin(x)*(n - 1))*n - _C1*exp(sin(x)*(n - 1)) + 2*sin(x)*n - 2*sin(x) + 2)/(n - 1))^(1/(n - 1));
odetest(mysol,ode);

    0

Now I just changed _C1 to C[1] 

restart;
ode:=diff(z(x),x)+z(x)*cos(x)=z(x)^n*sin(2*x);
mysol:=z(x) = 1/(( C[1]*exp(sin(x)*(n - 1))*n - C[1]*exp(sin(x)*(n - 1)) + 2*sin(x)*n - 2*sin(x) + 2)/(n - 1))^(1/(n - 1));
odetest(mysol,ode);

 

and I get 2 pages full of stuff thrown at the screen. Same when using C as constant of integration.

I could change my C[1] and C[2] to _C1 and _C2 each time just before calling odetest as workaround.

But would like to ask if this is supposed to happen and why it happens. I depend on odetest alot, as I use it to tell me if my solution is correct or not and I do not want false negatives.

I have found additional ones. May be these will help locate the problem

Example 2

restart;
ode:=diff(y(x),x) = (1+x+y(x))^(1/2);
mysol1:=y(x) = LambertW(-exp(-x/2 - 1 + C[1]/2))^2 + 2*LambertW(-exp(-x/2 - 1 + C[1]/2)) - x:
odetest(mysol1,ode);

gives

But when using _C1 instead of C[1], this is the answer

restart;
ode:=diff(y(x),x) = (1+x+y(x))^(1/2):
mysol2:=y(x) = LambertW(-exp(-x/2 - 1 + _C1/2))^2 + 2*LambertW(-exp(-x/2 - 1 + _C1/2)) - x:
odetest(mysol2,ode);

Example 3

restart;
ode:=diff(y(x),x) = f(x)*y(x)+g(x)*y(x)^k:
mysol1:=y(x) = (-exp(-(k - 1)*Int(f(x), x))*(int(g(x)*exp((k - 1)*Int(f(x), x)), x)*k - int(g(x)*exp((k - 1)*Int(f(x), x)), x) - C[1]))^(-1/(k - 1)):
odetest(mysol1,ode);

   #long output is given

Changing C[1] to _C1 gives 0 right away

restart;
ode:=diff(y(x),x) = f(x)*y(x)+g(x)*y(x)^k:
mysol2:=y(x) = (-exp(-(k - 1)*Int(f(x), x))*(int(g(x)*exp((k - 1)*Int(f(x), x)), x)*k - int(g(x)*exp((k - 1)*Int(f(x), x)), x) - _C1))^(-1/(k - 1)):
odetest(mysol2,ode);

     0

 

Example 4

restart;
ode:=3*y(x)*diff(y(x),x)+5*cot(x)*cot(y(x))*cos(y(x))^2 = 0:
mysol1:=y(x) = RootOf(10*ln(sin(x))*cos(_Z)^2 - 3*cos(_Z)*sin(_Z) + 30*C[1]*cos(_Z)^2 + 3*_Z):
odetest(mysol1,ode);

Gives pages long output. Changing C[1] to _C1 gives zero

restart;
ode:=3*y(x)*diff(y(x),x)+5*cot(x)*cot(y(x))*cos(y(x))^2 = 0:
mysol2:=y(x) = RootOf(10*ln(sin(x))*cos(_Z)^2 - 3*cos(_Z)*sin(_Z) + 30*_C1*cos(_Z)^2 + 3*_Z):
odetest(mysol2,ode);

    0

 

Example 5

restart;
ode:=x*(x-a*y(x))*diff(y(x),x) = y(x)*(y(x)-a*x);
mysol1:=y(x) = exp((-a + 1)*RootOf(x*exp(ln(x)*a + _Z*a + C[1]*a + C[1]) + exp(ln(x)*a + _Z*a + C[1]*a - _Z + C[1])*x - 1) - ln(x)*a - C[1]*(a + 1)):
odetest(mysol1,ode);

gives

Changing C[1] to _C1 gives zero

restart;
ode:=x*(x-a*y(x))*diff(y(x),x) = y(x)*(y(x)-a*x);
mysol2:=y(x) = exp((-a + 1)*RootOf(x*exp(ln(x)*a + _Z*a + _C1*a + _C1) + exp(ln(x)*a + _Z*a + _C1*a - _Z + _C1)*x - 1) - ln(x)*a - _C1*(a + 1)):
odetest(mysol2,ode);

              0

 

Example 6

restart;
ode:=x*diff(y(x),x)^2-a*y(x)*diff(y(x),x)+b = 0:
mysol1:=y(x) = x*RootOf(2*x*_Z^2*a - 2*C[1]*_Z^((2*a - 1)/(a - 1))*a - x*_Z^2 + C[1]*_Z^((2*a - 1)/(a - 1)) - b)/a + b/(RootOf(2*x*_Z^2*a - 2*C[1]*_Z^((2*a - 1)/(a - 1))*a - x*_Z^2 + C[1]*_Z^((2*a - 1)/(a - 1)) - b)*a):
odetest(mysol1,ode);

gives many pages of output. Changing C[1] to _C1 gives zero

restart;
ode:=x*diff(y(x),x)^2-a*y(x)*diff(y(x),x)+b = 0:
mysol2:=y(x) = x*RootOf(2*x*_Z^2*a - 2*_C1*_Z^((2*a - 1)/(a - 1))*a - x*_Z^2 + _C1*_Z^((2*a - 1)/(a - 1)) - b)/a + b/(RootOf(2*x*_Z^2*a - 2*_C1*_Z^((2*a - 1)/(a - 1))*a - x*_Z^2 + _C1*_Z^((2*a - 1)/(a - 1)) - b)*a):
odetest(mysol2,ode);

             0

and more. I think the above should hopefully help locate the issue.

Maple 2020.1 with Physics 708

 

The general solution of x2y'' + 3xy' + λy = 0 is (from Example 4 here)

Why does dsolve(x^2*diff(y(x), x, x) + 3*x*diff(y(x), x) + lambda*y(x) = 0) give only the third case instead of the whole solution?

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