Hi

how can i solve this

dx+4*x*dy/y = dy*a*y^(-6*b-1)

to find x in terms of y

Hey everone, im trying to get 2 legends to apear on my plot im animateing. The problem here is that it just wont. Could you guys help me ?

Heres the code

c := x -> piecewise(0 <= x and x <= 450000, 0.37*x, 450000 < x, 0.37*x + 0.06*(x - 450000));
g := x -> piecewise(0 <= x and x <= 558000, 0.37*x, 558000 < x, 0.37*x + 0.12*(x - 558000));
A1 := plots:-animate(plot, [g(x), x = 0 .. skat, color = blue], frames = 20, skat = 0 .. 1000000);
A2 := plots:-animate(plot, [c(x), x = 0 .. skat, color = red], frames = 20, skat = 0 .. 1000000);
Do(%Plot2 = plots:-display([A1, A2], size = [1000, 700], gridlines = true, legend=["Line 1","Line 2"],legendstyle=[font=[Lucida, roman, 14], location=bottom]));
SetProperty("Plot2", ':-play', true, ':-refresh' = true);

Hi everybody,

Im trying to solve the following trivial pde using Maple 2018

pdsolve([diff(Y(x, t), t, t) = 0, Y(x, 0) = 0, (D[2](Y))(x, 1) = 0]);

Obviuosly the solution is Y(x, t) = 0, but Mapple 2018 is not giving any answer.

This works in Maple 2015.

Why is not working in Maple 2018?

Thanks,

Javier

I have the equation y^2=𝑎𝑥^3+𝑏𝑥^2+𝑐𝑥+𝑑.

How do I plot y against x as the coefficients a, b, c and d vary?

Thank you for your help.

hi

how can i write a number or word on the column or right the row of matrix as this pic

hi, I am trying to evaluate the following integrations (Note that; the values of alpha, lambda_1 and lambda_2) are random and they change with every iteration 

Download ask_maple.mw

Hello,

What means, please, this error

Error, (in RootFinding:-Analytic) Maple was unable to allocate enough memory to complete this computation.  Please see ?alloc
 

What should I to do to overcome this error?

Hi guys,

I'm fairly new to programming as a whole, but I've currently set up a script which creates a matrix and then fills it in given a  condition. i.e if the x and y indices of the matrix are the same it has been told to add m^2F. If the y and x index differs by 3 is has been asked to fill in V3/4 and if they differ by 6 it has been asked to fill in V6/4. After the matrix is created it will then calculate the eigenvalues.

My question is as follows:

m^F is a constant and V3 and V6 are variables. I currently, manually, set a value of V3 and V6 at the top of the script and then calculate the eigenvalues. How would one go about reversing this process - i.e provide a set of eigenvalues and then perform a fit to find the best values of V3 and V6. Is this 'doable' in Maple or would it be best to use something else.

I have attached a copy of the script for viewing purposes in case what I have written is not very clear - Hindered_rotor.mw

Thanks for your time,

David

How 2 solve summation when M,  Z,  X are given with mixed conditions?

Hello everyone, I'm trying to run a simple calculation (Water flowing out of a pressurised container) using a combination of conservation of energy and conservation of mass. I have working models of the same system without pressurisation (purely gravity working) which work fine in Maple, but when re-writing the pressure as a function of the height of the water I receive the error:

"Error, (in DEtools/convertsys) unable to convert to an explicit first-order system".

The formula used is:

"Eq1:= -Rho_Water * A_Barrell * v_Barrel = Rho_Water * A_Nozzle * v_Nozzle"

Which returns:

"Eq1:= -25.23733555 * d/dt h_Water(t) = 0.5982 * (-190.1309944 - 13.64385474 * h_Water(t) + (d/dt h_Water(t))²)^1/2"

With initial condition:

"ics1:= h_Water(0) = 0.2"

After giving the command:

"Sol1:= dsolve({Eq1, ics1}, numeric)"

Maple returns the aforementioned error. When trying to solve non-numerically the output is a list filled with "RootOf" and "_Z". Instinctively I would say the square root in the second part of the equation is the problem here, but I would not know how to fix this. Does anybody have a quick fix for this problem? Or is there a fundamental issue with the equation? Thank you in advance!

I have matrix:

m1 := Matrix([[x[0,0]=1,x[0,1]=1,x[0,2]=0,x[0,3]=0,x[0,4]=0,x[0,5]=0],[x[1,0]=0,x[1,1]=0,x[1,2]=1,x[1,3]=1,x[1,4]=0,x[1,5]=0],[x[2,0]=0,x[2,1]=0,x[2,2]=0,x[2,3]=0,x[2,4]=1,x[2,5]=1]]);

How to get values on the rhs of x without using for loops and create a matrix using these values?.

Results should be:

m2 := Matrix([[1,1,0,0,0],[0,0,1,1,0,0],[0,0,0,0,1,1]]);

How to write a code to get following Matrix D?

MY TRY: (But it' s not completely what I seek)

restart:

k:=1:
M:=2:
N:=2^k*(M+1):

U:=Matrix(M+1,M+1):
for r from 2 to M+1 do
for s from 1 to r-1 do
if type(r+s,odd) then
U(r,s):=2^(k+1)*sqrt((2*r-1)*(2*s-1)):
 else 0 end if:
end do:
end do:

#Let's find Matrix D, In here it' s shown matrix DD 
DD:=Matrix(N,N,shape=diagonal,fill=U);

Dear all,

I hope everyone helps me about the problem of converting a permutation into numbers and vice versa on maple

Let S_n denote the set of all permutations of the set {0, 1, ..., n − 1}. 

Lehmer code is a bijective function l : S_n ->{0, 1, 2, ..., n! − 1}.

Define function l(S)=Sum(c_i x (n − 1 − i)! ) where S in S_n and c_i is the number of elements of the set { j > i | s_j < s_i }

Inverse Lehmer code is a bijective function l⁻¹ : {0, 1, 2, ..., n! − 1} -> S_n

For example: n=4 -->{0, 1, 2, 3}, for S = (0, 2, 1, 3) , so c₀ = 0, c₁ = 1 ( j=2 > i=1 and s_j = 1 < s_i = 2), c₂ = 0, c₃ = 0 -->

I(S) = 0 x (3-0)! + 1 x (3 - 1)! + 0 x (3-2)! + 0 x (3 - 3)! = 2! = 2. So I((0, 2, 1, 3)) =2  and I^-1(2) = (0, 2, 1, 3).

How to calculate I and I^-1 on maple? Please help me! Thanks alot.

restart;

##########  omega and theta are variables,where J[3],F[2],H[2],etc are constants.

#### I tried with "evlf" and "evlc" command but maple was not ready to provide the solution,please help me to solve this

t1:=-1/(-16.*omega^2+exp(-4*omega)+exp(4*omega)-2.)*(-(0.5817764173e-1*I)*exp((2/9)*omega*cos(theta))*omega^5*cos(theta)*J[3]-(.6981317009*I)*exp((2/9)*omega*cos(theta))*omega^4*cos(theta)*H[3]-0.4524927691e-1*exp(.2222222222*omega*(cos(theta)-9.))*cos(theta)*omega^3*G[3]-.6205615118*exp(.1111111111*omega*(2.*cos(theta)-9.))*cos(theta)*omega^3*H[2]+.6205615118*exp(.1111111111*omega*(2.*cos(theta)-9.))*cos(theta)*omega^3*F[2]+.9308422676*exp(.2222222222*omega*(cos(theta)-9.))*cos(theta)*omega^4*H[3]-.1034269187*exp(.1111111111*omega*(2.*cos(theta)-9.))*cos(theta)*omega^3*G[2]-0.7757018900e-1*exp(.1111111111*omega*(2.*cos(theta)-9.))*cos(theta)*omega^2*G[2]-0.7757018898e-1*exp(.2222222222*omega*(cos(theta)-9.))*cos(theta)*omega^4*J[3]-0.9696273622e-1*exp(.2222222222*omega*(cos(theta)-9.))*cos(theta)*omega^3*J[3]-0.4524927691e-1*exp(.2222222222*omega*(cos(theta)-9.))*cos(theta)*omega^2*J[3]-.2714956613*exp(.2222222222*omega*(cos(theta)-9.))*cos(theta)*omega^2*H[3]-0.7757018898e-1*exp(.2222222222*omega*(cos(theta)-9.))*cos(theta)*omega^4*G[3]+0.8726646261e-1*exp((2/9)*omega*cos(theta))*omega^3*J[3])*cos((2/9)*omega*sin(theta));

t2:=int(int(t1,omega=0..infinity),theta=0..2*Pi);

Is there any Maple command to detect whether the degree of a polynomial w.r.t. all variables is less or equal 1?

For example, if $f=ax+by-1$ when $x$ and $y$ are variables then the output is true and if $g=a*x^2+b*y-c$ then it returns false.