Download Test_pile.mw

Good Evening Maple Community,

Can anybody please help in the attached file. Highlighted in yellow are the three equations I'm trying to program in Maple procedure, but could not get any output due to an error message. Please Help.

Boyer 

Is this what is supposed to happen when linking Maple to Matlab?  I was hoping it would open the actual Matlab program and write variables to the current worksheet.  I'm I missing something?

Nothing even pops up on the Matlab Command window. What good is this?

I want to define a proc in Maple which gets an integer n and gives a set of arrays like {1,2,3}^n, meaning {[a[1],...,a[n]]|for all 1<=i<=n a[i] in {1,2,3}}. For a fix n, obviously one can use n-for, for example when n is 2

A:=Array(1..3,1..3):
for a[1] from 1 by 1 to 3 do
 for a[2] from 1 by 1 to 3 do
  A(a[1],a[2]):=[a[1],a[2]];
 end for:
end for:

But when n is not fixed, how can I tell Maple to consider n for?! Also how can ask him to make a n-dimensional array?

Hi 

I have 3 equations

eq1 := vs = (Rs+Z)*i1+Z*i3

eq2 := A*vi = Z*i1+(Z+Rf+ro)*i3

eq3:= vo = (Rf+Z)*i3+Z*i1

and I want to solve for vo/vs . How to do that ?

the expected solution is 

Hi;

Could anyone help me to compute the lie derivative of the function h:R^3-->R with respect to the vector-valued function f:R^5-->R^3 below?

f(x,y,L,u,v) = [x + u;
               y + v;
               L]

and 

h(x,y,L) = sqrt((y-x)^2 + (L)^2)

Thank you in advance.

Hi all,

I have have s simple graph, see figure below. I want to export it to e.g. PDF-format.

But I want landscape, not portrait. How can I export PDF to landscape?

I tried a workaround: Export it as to JPG gives very bad quality.

I simply want to export my figures to landscape with good quality.

How can I solve this?

Here is my command

> teksbiasa:=`Kriptografi`;

teksbiasa:=Kriptografi

>len:=length(teksbiasa);

len:=11

>nilaiASCII:=convert(teksbiasa, bytes);

nilaiASCII:=[75,114,105,112,116,111,103,114,97,102,105]

>L:=[seq(i,i=nilaiASCII)]

L:=[75,114,105,112,116,111,103,114,97,102,105]

Anyone know how i need to write the command to add the lenght of the text (len) into each of the number in nilaiASCII?

What is want to get is:

[86,125,116,123,127,122,114,125,108,113,116]

Thank you~=]]

[75,114,105,112,116,111,103,114,97,102,105]

For bonus in my one class, we are required to change the code in a program to have it produce another row when running Neville's Method. We need to, after it runs initially, have it ask "Run another time? Y/N" and type 'Y' or 'N' for Yes or No. If No, it ends the program. If yes, we need to have it input another x(i) and f(x(i)) without having to input all the other data points again. Here is what I have so far (this is just the additional part we have to add, not the whole code):

 print(`Do you want another point? Type Y or N.`):
  J := scanf(` %c`)[1]:print(`Entry = `):print(J):
  if J = "Y" or J="y" then
  AGAIN := "Y":
  AGAIN = "Y" or AGAIN = "y":
        OUP := default:
      fprintf(OUP, `NEVILLE'S METHOD\n `):
       fprintf(OUP, `Table for P evaluated at X = %12.8f , follows: \n`, X):
       fprintf(OUP, `Entries are XX(I), Q(I,0), ..., Q(I,I) `):
       fprintf(OUP, `for each I = 0, ..., N where N = %3d\n\n`, N):
       for I1 from 0 to N+1 do
         fprintf(OUP, `%11.8f `, XX[I1]):
         for J from 0 to I1 do
           fprintf(OUP, `%11.8f `, Q[I1,J]):
         od:
         fprintf(OUP, `\n`):
        od:
    if J="Y" or J="y" then
         AGAIN := Y:
             if AGAIN = Y or AGAIN = y then
                 #N=N+1:
                  if N > 0 then
                  OK := TRUE:
                 for I1 from N to N+1 do
                        print(`Input X(i) and F(X(i)) for i = `):print(I1):
                        print(`separated by a space `):
                       XX[I1] := scanf(`%f`)[1]:
                       Q[I1,0] := scanf(`%f`)[1]:print(`Entries are`):print(XX[I1],Q[I1,0]):
                  od:
                else
                  print(`Number must be a positive integer `):
               fi:


            else
                AGAIN := No:     
         fi:
         fi:
    else
        print(`Ok thanks`):
 fi:

Not sure what I am doing wrong and any help is appreciated. Thanks.

One new feature of Maple 2016 is claimed to be

          FunctionAdvisor(plot, .......)

but when I try HeunD or HeunG there is no output -- no error message, nothing.  Is this behaviour what a user should expect of this command?

I would like to scale the last KernelDensityPlot in the attached worksheet to overlay with the Histogram above it.  The result would look like the 3rd plot in the worksheet, except the y-axis ranges would match.

MonteCarloHistogram.mw

montecarloHistogramExample.txt

Regards,

Georgios

I'm trying to solve a recurrence relation by generating terms and looking for a pattern.  I've learned that i can't stop 

Maple's autosimplification process and the best I can do is use Parse from the InertForm package.  The hand drawn picture below is what I'm trying to replicate.  I know I can use rsolve but I'm trying to do the steps I would with pencil and paper.

I want to set the determinant of the coefficient matrix equal to zero and then solving for the roots. But I could not achieve it via Maple. Can you help me please? 

You can reach two examples in the following file.  Yeni_Microsoft_Word_Belgesi_(2).docx

Besides. how can i compute the following transcental equations via maple 

sinh(beta*L)*sin(beta*L)=0

cosh(beta*L)*cos(beta*L)-1=0

cosh(beta*L)*cos(beta*L)+1=0

regards

mehmet

Here is my command..

> mylist:=[4,6,2]: for x from 1 to nops (mylist) do convert (mylist[x], binary) end do;

> z:=map(convert, mylist, binary);

[100, 110, 10]

> map2(nprintf,"%08d",z);

[00000100, 00000110, 00000010]

how I need to continue the command to get the number of 1s in each of the binary number? 

Thank you~=]]

`00000100`, `00000110`, `00000010`

Sorry for disturbing you again. I am haunted by a problem about Taylor expansion in Maple.

For example, when the angle alpha is small, thus we could use taylor(sin(x),x=0,1) to get a approximated function of sin(x) with different order of precision.

But, if the sin(x) meets diff(x(t),t), (x is a time-dependant variable), could we also apply the Tayolr expansion in Maple to obtain a approximation?

For example, the function: sin(x(t))*diff(x(t),t), x(t) is given with a small value, but diff(x(t),t) could not be neglected, because even x(t) is with a small value , diff(x(t),t) could be great. We could conduct the Talyor expansion with hands, and sin(x(t))*diff(x(t),t) becomes x(t)*diff(x(t),t). But I wonder if we could use Maple to realize this procedure. And if the Maple could make it, I would like to know if the Maple could handle the multi-variable Taylor expansion accompanied with the time derivative. For example, the x(t) and y(t) are considered as small value variables, could we simplified the following function sin(x(t))*cos(y(t))*diff(x(t),t)*diff(y(t),t).

Thank you very much in advance for taking a look. 

Hi. Is there a maple function which can interpolate values from a simple table:

given (x,y) compute z value

eg z(0.5,0.5)=1.5

x:=[0,1,2];y:=[0,1,2]

array:=[0,2,4;1,3,5;2,4,6] #probably the wrong input, but you get the idea

ArrayInterpolation?

there is a method in vba:

http://www.tushar-mehta.com/excel/newsgroups/interpolation/#Two_dimensional_interpolation_